Each molecule contains 3 oxygen atoms GFM

Slides:



Advertisements
Similar presentations
Copyright Sautter 2003 STIOCHIOMETRY “Measuring elements” Determing the Results of A Chemical Reaction.
Advertisements

Molar Quantities: Balancing Equations
Stoichiometry The calculation of the quantities of chemical substances involved in chemical reactions.
The Basics Balancing Equations. The Reaction Burning METHANE or any hydrocarbon gives WATER and CARBON DIOXIDE Burning METHANE or any hydrocarbon gives.
Chapter 9 Chemical Quantities. 9 | 2 Information Given by the Chemical Equation Balanced equations show the relationship between the relative numbers.
Excess.
Problem What mass of Br 2 is produced when 45.9g of NaBr react with 12.8g of Cl to produce Br 2 and NaCl?
Bell Work NH 3 + O 2  N 2 + H 2 O How many moles of oxygen react with 0.23 moles of NH 3 ?
Limiting Reagent. Did you know? Hydrogen is the most abundant element in the Universe…it makes up about 75% of it. So far, all of the examples and equations.
Bell Ringer What is a Mole? What is the mass of a NaCl molecule?
Proportions  A proportion is an equation with a ratio on each side. It is a statement that two ratios are equal.  3 = 6 is an example of a proportion.
Balancing equations: 1 st …review what we already know.
Stoichiometry: the mass relationships between reactants and products. We will use the molar masses ( amount of grams in one mole of a element or compound)
Copyright Sautter 2003 STOICHIOMETRY “Measuring elements” Determining the Results of A Chemical Reaction.
Chemical equations give information in two major areas. First, they tell us what substances are reacting (those being used up) and what substances are.
Chemical Equations IV Stoichiometric Calculations.
Aim: Using mole ratios in balanced chemical equations.
Burning is a chemical change
Jeopardy ChemicalPhysicalFormulasEquations Chemistry Q $100 Q $200 Q $300 Q $400 Q $500 Q $100 Q $200 Q $300 Q $400 Q $500 Final Jeopardy.
5- Determining the Formula of a Compound: The formula of a compound gives the atoms (or mole) ratio. It can be represented as: ❶empirical formula of a.
Unit 12 Mass and Moles.
Chemical Equations and Reaction Stoichiometry AP Chemistry Milam.

Word Equations A word equation is a shorthand way of explaining what happens in a chemical reaction When calcium carbonate reacts with hydrochloric acid.
Balancing Equations. The Law of Conservation of Mass (or Matter) In a chemical reaction, matter is neither created nor destroyed.
IIIIIIIVV A Balancing Act Chemical Reactions. Chemical Reactions Take Place… n Every minute of every day both in and around you n Examples:  Digestion.
Chemical Equations. What is a “chemical equation”?  Chemical Equations use symbols to represent a chemical reaction and show the relationship between.
Stoichiometry Devon Bateman. Essential Question Why is a foot…a foot? –King Henry I had a foot 12 inches long.
III Equation Problems A What does an equation represent? Represents chemical change Made up “reactants” and “products”  Reactants  starting materials.
Stoichiometry. What Is It? Branch of chemistry that shows the relationships among reactants and products in a chemical reaction Equations must be balanced.
 1 mole = x particles  The mass of one mole of atoms of a substance.  The average atomic mass from the chart.  For diatomic molecules,
Chemical Equations Formulae, names, equations, moles and stoichiometry.
Relative Formula Mass expressed in grams
Stoichiometry – Chemical Quantities Notes. Stoichiometry Stoichiometry – Study of quantitative relationships that can be derived from chemical formulas.
Stoichiometry Chapter 10.
Chemical Equations III
Chapter 11: Stoichiometry
Stoichiometry MolesMass Remember! You cannot convert directly from a mass of one substance to the mass of another substance! You must always find moles.
Mole GRAM FORMULA MASS MOLES TO GRAMS AND GRAMS TO MOLES.
Law of Conservation of Mass. causes a chemical change, which creates a new substance with new and different properties.
Chapter Three Mass Relationships in Chemical Reactions.
Balanced Equations A balanced equation has the same number of atoms for each element on both sides We can use this to find the ratio of moles that are.
Section 2Chemical Reactions EQ: 〉 What is a chemical equation? 〉 What can a balanced chemical equation tell you?
Finding and Using Molar Ratios The coefficients in a balanced chemical equation can be used to determine the relative number of molecules, formula units,
Stoichiometry.
1/9 Opener Don’t forget to turn in extra credit!
Stoichiometry.
Burning is a chemical change
Chemical Reactions: An Introduction
What mass of methane could be produced from 10 grams of hydrogen?
Balancing Equations Section 7.3 in Textbook.
MASS - MASS STOICHIOMETRY
The Law of conservation of mass
Chapter 12 Review.
Chemical reactions Unit
Review – 1 More! Propane (C3H8) and oxygen react to produce carbon dioxide and water. Write AND BALANCE the chemical equation. ANSWER: C3H8(g) + 5O2(g)→
Empirical Formulas and Mole Ratios
Chemical Reactions Essential Unit 5.
Stoichiometry II.
9.1 NOTES Stoichiometry.
Stoichiometry Moles to Moles.
Calculations Based on Chemical Equations
Stoichiometry.
Balancing Chemical Equations
Opener 1/11 Balance the following:
Reaction Stoichiometry
Stoichiometry.
Bell Work 4NH3 + 3O2    N2 + 6 H2O How many moles of oxygen react with 0.23 moles of NH3?
Reacting Masses and Volumes
The mole ratio.
Presentation transcript:

Each molecule contains 3 oxygen atoms GFM 50g CaCO3 1 mole CaCO3 3 mole O 6.022 x 1023 atoms O 100g CaCO3 1 mole CaCO3 1 mole O View whole question: Each row contains same substance CaCO3 looks like all is about moles so GFM is key Look at answer choices make a conclusion choose which is key Here I see if statement II is true only two answer choices are possible so I will check this first Annotate statement 2 Find GFM of CaCO3 = 100 Strategy independently assess each one Therefore each row needs its own annotation

goal Given 200g CaCO3 1 mole CaCO3 100g CaCO3 Since 2 is true then all I need to do is check if III is true

Enough CH4 to make 2 moles of CO2 1 2 1 2 32g CH4 1 mole CH4 1 mole CO2 2 mole CO2 16g CH4 1 mole CH4 View whole question Look like I need to balance this first 32g O2 1 mole O2 1 mole CO2 Only ½ mole of CO2 is made Enough CH4 to make 2 moles of CO2 Therefore enough CH4 left to make 1.5 mole of CO2 1/2 mole CO2 32g O2 2 mole O2

RATIO !! View whole question This question is about ratios So don’t get put off by the complexity of the equation Just know the sorry 1A reacts with 5B and 8C to make 1D, 5E and 4F

Given Given 6 mole C3H8 4 mole HCl goal 24 mole HCl 1 mole C3H8 Two givens and 1 goal this normally means a limiting reactant question 20 mole Cl2 4 mole HCl Two “Given”s one Goal LIMITING!?! 20 mole HCl 4 mole Cl2

So 1.5 x 10 23 atoms have a mass of 12 g Mass of one mole 6.022 x 1023 = one mole So 1.5 x 10 23 atoms have a mass of 12 g So 6.022 x 10 23 would have a mass of This is a ratio question 12g is to 1.5 x 1023 as gfm is to 6.022 x 1023 So 1.5 x 10 23 atoms is to 12 g as 6.022 x 10 23 is to GFM

Cross multiply and solve 72.26g = 1.5 GFM g Mass of one mole 12g GFM g 6.022 x 1023 = one mole = 1.5 x 1023 6.022 x 1023 Multiply both sides by 1023 12g GFM g = This is a ratio question 12g is to 1.5 x 1023 as gfm is to 6.022 x 1023 1.5 6.022 Cross multiply and solve 72.26g = 1.5 GFM g 48.2g

Each molecule contains 3 oxygen atoms ¼ of a mole ¼ of a mole Each molecule contains 3 oxygen atoms This is a ratio question 12g is to 1.5 x 1023 as gfm is to 6.022 x 1023