Part 1: Unit Circle & Formula Sheet, 4-Function Calculator

Slides:



Advertisements
Similar presentations
Law of Sines The Ambiguous Case
Advertisements

Law of Sines Lesson Working with Non-right Triangles  We wish to solve triangles which are not right triangles B A C a c b h View Sine Law Spreadsheet.
Warm-Up 3/24-25 What are three basic trigonometric functions and the their ratios? Sine: sin  Cosine: cos  Tangent: tan 
Class Work 1.Sketch a right triangle that has acute angle , and find the five other trig ratios of . 2.Evaluate the expression without using a calculator.
9.5 Apply the Law of Sines When can the law of sines be used to solve a triangle? How is the SSA case different from the AAS and ASA cases?
Set calculators to Degree mode.
6.1 Laws of Sines. The Laws of Sine can be used with Oblique triangle Oblique triangle is a triangle that contains no right angle.
Law of Sines Lesson Working with Non-right Triangles  We wish to solve triangles which are not right triangles B A C a c b h.
5.5 Law of Sines. I. Law of Sines In any triangle with opposite sides a, b, and c: AB C b c a The Law of Sines is used to solve any triangle where you.
Section Day 2 The Ambiguous Case of the Law of Sines.
Chapter 6.  Use the law of sines to solve triangles.
7.1 The Law of Sines 56 46° 63° A B C. 7.1 The Law of Sines 14 64° 82° A B C.
Notes: Law of Sines Ambiguous Cases
EXAMPLE 2 Solve the SSA case with one solution Solve ABC with A = 115°, a = 20, and b = 11. SOLUTION First make a sketch. Because A is obtuse and the side.
Chapter : Trigonometry Lesson 3: Finding the Angles.
EXAMPLE 1 Solve a triangle for the AAS or ASA case Solve ABC with C = 107°, B = 25°, and b = 15. SOLUTION First find the angle: A = 180° – 107° – 25° =
Trigonometry Section 7.4 Find the sine and cosine of special angles. Consider the angles 20 o and 160 o Note: sin 20 o = sin160 o and cos 20 o = -cos 160.
Lesson 29 – Sine Law & The Ambiguous Case IB Math HL - Santowski 6/23/20161Math HL - Santowski.
Lesson: Regular Polygons, Trigonometry, & Area
5.7 The Ambiguous Case for the Law of Sines
9.1 Law of Sines.
Unit 6: Trigonometry Lesson: Law of coSines.
Unit 6: Trigonometry Lesson: Law of Sines.
The Law of SINES.
Solving Practical Problems Using Trigonometry
LCHL Strand 3: Trigonometry
Unit 5: Introduction to Trigonometry Lesson 5: Evaluate Trig Functions
Unit #7: Trig Identities & Equations
Laws of Sines.
50 a 28.1o Warm-up: Find the altitude of the triangle.
Warm Up Chapter 3 Solve and graph on a number line: −
Law of Cosines Section 5-6.
Taking Unit 1 Test #2 Today --- AL
Unit 8: Extended Trigonometry Lesson 4: Polar Coordinates (Part 1)
Copyright © 2017, 2013, 2009 Pearson Education, Inc.
Day 9: Review Unit 8: Trigonometry.
Day 79 AGENDA: DG minutes.
Day 21 Agenda: DG minutes Finish notes on Ellipse (U2 L3)
Accel Precalc Unit 8: Extended Trigonometry
Unit #5: Introduction to Trigonometry
Do Now If the legs of the right triangle are 4 and 5 find the hypotenuse and all the angles.
Lesson 1: Establishing Trig Identities
Unit #7: Trig Identities & Equations
Unit 2 Test Review is on blog.
Law of Sines Goal: To solve triangles which aren’t necessarily
Day 27 Agenda: DG minutes Scientific Calc only.
Day 43 Agenda: Quiz minutes.
Section 6.1.
Day 54 AGENDA: DG minutes No Unit Circle 4-function Calc only.
Day 12 AGENDA: DG minutes Work time --- use this time to work on practice problems from previous lessons.
The Law of SINES.
Trigonometry To be able to find missing angles and sides in right angled triangles Starter - naming sides.
Unit #7: Trig Identities Lesson 5: Half-Angle Formulas
Unit #7: Trig Identities Lesson 5: Half-Angle Formulas
DAY 61 AGENDA: DG minutes.
Lesson 6: Inverse of Matrices (part 3)
DG34 (LAST ONE!)---10 minutes
Day 58 AGENDA: Notes Unit 6 Lesson8.
Day 74Agenda: Turn in Recommendation Letter DG minutes
DAY 74 AGENDA: DG minutes Turn in Rec Letter --- due Mon.
Accel Precalc Unit 8: Extended Trigonometry
Unit 7 Test # 1 (Identities) – 1 HOUR; Formula Sheet;
The Law of SINES.
1..
Day 49 Agenda: DG minutes.
The Law of SINES.
Finish Conditional Probability
Law of Sines (Lesson 5-5) The Law of Sines is an extended proportion. Each ratio in the proportion is the ratio of an angle of a triangle to the length.
EQ: How do you convert angle measures in
The Law of SINES.
Presentation transcript:

Part 1: Unit Circle & Formula Sheet, 4-Function Calculator AGENDA: DG 30--- 15 minutes Part 1: Unit Circle & Formula Sheet, 4-Function Calculator Part 2: Unit Circle, Formula Sheet, Graphing Calculator Finish Lesson 1 Law of Sines (Part 2)

Accel Precalc Unit 8: Extended Trigonometry Lesson 1: Law of Sines (Part II) EQ: What is the ambiguous case for Law of Sine? How do you determine if a triangle exists?

Scenario 1: A is acute   opp < adj sin NO SOLUTION

adj sin < opp < adj Scenario 2: A is acute adj sin < opp < adj B is  180 -   B is 180 - 

Scenario 3: opp = adj sin A is acute If a = b sin A, a right triangle can be formed. opp = adj sin 1 SOLUTION

Scenario 4: opp > adj A is obtuse If a > b, then one triangle can be formed. opp > adj 1 SOLUTION

Scenario 5: opp < adj A is obtuse If a < b, then no triangle can be formed. opp < adj N0 SOLUTION

1 Right Triangle Now Solve a) a = 8, b = 4, ∡B = 30o Ex 1. Sketch the information given on a triangle. Determine how many solutions exist for each triangle. Find all missing parts. ∡B is ACUTE a)  a = 8, b = 4, ∡B = 30o 8 4 30o 1 Right Triangle Now Solve

90˚ 8 C 60˚ 8 4 30˚ 4 30˚ 90˚ A B 6.93 60˚ 6.93

NO Triangle b) a = 6, b = 4, ∡ B = 45o Ex 1. Sketch the information given on a triangle. Determine how many solutions exist for each triangle. Find all missing parts.     b)  a = 6, b = 4, ∡ B = 45o ∡B is ACUTE 6 4 45o NO Triangle

A Least 1 Triangle 2 Triangles c) b = 7, c = 6.5, ∡ C = 60o Ex 1. Sketch the information given on a triangle. Determine how many solutions exist for each triangle. Find all missing parts.     c)  b = 7, c = 6.5, ∡ C = 60o ∡C is ACUTE 7 6.5 60o A Least 1 Triangle 2 Triangles

A 51˚ 5.8 51˚ 6.5 7 69˚ 7 60˚ 69˚ B C 5.8 60˚ 6.5 Second Triangle : Use Supplement of ∡B

A 7 6.5 7 C 6.5

At Least 1 Triangle FALSE, Only 1 Triangle d) a = 5, c = 10, ∡ C = 70o Ex 1. Sketch the information given on a triangle. Determine how many solutions exist for each triangle. Find all missing parts.     d)  a = 5, c = 10, ∡ C = 70o ∡C is ACUTE 5 10 70o At Least 1 Triangle FALSE, Only 1 Triangle

A 28˚ 5 28˚ 10 10.5 82˚ 10.5 70˚ 82˚ B C 5 70˚ 10

Assignment: Practice Worksheet #2