10 9 8 7 6 4 2 0 5 10 15 20 25 30 3 55 60 65 0 5 10 15 20 25 30 35 40 45 50 Time Distance Graphs Time (mins) Distance (km) E D B C F A Distance from A 0 km 3 km 9 km

10 9 8 7 6 4 2 0 5 10 15 20 25 30 3 55 60 65 0 5 10 15 20 25 30 35 40 45 50 Time Distance Graphs Time (mins) Distance (km) A B C D E F 3 A is the start point A - B is the first part of the journey Read the distance from A on the y axis 3 km Read the time from A on the x axis 15 mins = 0.25 hrs Calculate the speed: S = D T S = 3 0.25 = 12 km/h

10 9 8 7 6 4 2 0 5 10 15 20 25 30 3 55 60 65 0 5 10 15 20 25 30 35 40 45 50 Time Distance Graphs Time (mins) Distance (km) A B C D E F 3 B - C the distance from A did not change The cyclist was stopped for 5 minutes Horizontal line means stopped

10 9 8 7 6 4 2 0 5 10 15 20 25 30 3 55 60 65 0 5 10 15 20 25 30 35 40 45 50 Time Distance Graphs Time (mins) Distance (km) A B C D E F 3 C - D the next part of the journey Notice that the gradient of the graph is steeper for C – D than for the section A – B. C - D is a longer distance (6 km) in a shorter time (10 mins) than A – B so the speed must have been faster. Steeper gradient means faster speed

10 9 8 7 6 4 2 0 5 10 15 20 25 30 3 55 60 65 0 5 10 15 20 25 30 35 40 45 50 Time Distance Graphs Time (mins) Distance (km) A B C D E F 3 E - F the line returns to the x axis The cyclist went back to A The distance travelled was from A to 9 km away, then back again The total distance 18 km Calculate the average speed: S = D T S = 18 1 = 18 km/h

10 9 8 7 6 4 2 0 5 10 15 20 25 30 3 55 60 65 0 5 10 15 20 25 30 35 40 45 50 Time Distance Graphs Time (mins) Distance (km) E D B C F A Distance from A 0 km 3 km 9 km