A circuit with several resistances but only one conducting path.

Slides:

Advertisements

Similar presentations

SERIES RESISTOR CIRCUIT. THE EQUIVALENT SERIES RESISTANCE IS : Req = R 1 + R 2 + R 3 THE CURRENT OF THE CIRCUIT IS : I = U / (R 1 + R 2 + R 3 ) THE EQUIVALENT.

Advertisements

Pew Pow Think about the differences between a series circuit and a parallel circuit and explain which method is used to wire your house. Show a formula.

1 SERIES CIRCUITS Benchmark Companies Inc PO Box Aurora CO

…the movement of charge between varying locations and the corresponding loss and gain of energy which accompanies this movement. Unit 4 - Electric Circuits…

Series Circuits. Schematic Circuit Diagrams There are many different ways to represent circuits. Below is an artist’s drawing and a schematic drawing.

Circuits Series and Parallel. Series Circuits Example: A 6.00 Ω resistor and a 3.00 Ω resistor are connected in series with a 12.0 V battery. Determine.

If current is disrupted through one element (e.g. the light goes out) If current is disrupted through one element (e.g. the light goes out) then they.

Lecture 2 Basic Circuit Laws

Combined Series and Parallel Circuits Objectives: 1. Calculate the equivalent resistance, current, and voltage of series and parallel circuits. 2. Calculate.

Resistors in Series and Parallel

Electrical Energy - Moving electrons in a path is electricity

The “Live Action” Physics Review Game Topic: Circuits.

Electric Circuits. What is an Electric Circuit? Electric Circuit: is a closed loop through which charges can continuously move. Need to have complete.

Series and Parallel Circuits Khemraj Nandanwar T.G.T.(Work Experience) Kendriya Vidyalaya,Golaghat.

Electricity Jeopardy Circuits 1 Circuits 2 Electric Current OhmExtra Q $100 Q $200 Q $300 Q $400 Q $500 Q $100 Q $200 Q $300 Q $400 Q $500 Final Jeopardy.

Section 2: Series and Parallel Circuits. Series Circuits Picture of Series Circuit:Properties: 1)Current: 2) Voltage: 3) Equivalent Resistance:

Is this a series circuit or a parallel circuit?

Circuits. V = IR Voltage is electric potential. It is measured in volts (V). I is current. This is the flow rate of electrical charge. It is measured.

PRACTICE (WB) 1)Four resistors in series. Choose voltage for your battery. Determine I and V across each resistor. 2)Four resistors in series. Chose I.

Regents Physics Chapters 17/18 Circuits  Series Circuits.

Electrical Energy in Circuits and Conductive material

Ohm’s Law Resistance in Series Circuits

Series & Parallel Circuits

Chapter 20 Super Review Circuits. 1. What is the potential difference across a resistor of 6 Ω that carries a current of 3 A?

What we will do today Introduce potential divider circuits. Devise a formula comparing resistances and voltages in potential divider circuit.

Physics Section 18.2 Apply series and parallel circuits. Note: A simple circuit may contain only one load. A more complex circuit may contain numerous.

Glencoe Physics Chapter 23 ”Circuits and Circuit Elements"

C OMBINATION C IRCUITS Lesson 7. C OMBINATION CIRCUITS Combination or mixed circuits contain both series and parallel connections.

Solving Problems 14.1 & A circuit contains 5-ohm, 3-ohm, and 8-ohm resistors in series. What is the total resistance of the circuit? Rt = R1.

Series and Parallel Circuits

1. Write the three rules governing voltage, current, and resistance relationships in a series circuit containing a battery and three resistors. Some Electricity.

The Series Circuit Summary 1. The sum of the _____________or voltage equals the potential rise of the source. 2. The current is ______________ everywhere.

Kirchhoff’s Current Law For a series circuit: In a series circuit there is only one path so the current must be… Kirchhoff’s Current Law For a series.

Bell Ringer 2/10 Write the objective

Symbols for Circuits.

10 Ω 2.75 Ω 3.75 R2 R1 R3 6 Ω 6 Ω 80 V 2.5 Ω 2 R6 3 Ω R5 4.5 R7 2 Ω R4 3 Ω R8 4 Ω 5 Ω R9 R RT = = 10 Ω.

Series and Parallel Circuits

Solving Circuits.

Series Circuit.

October 18, 2017 Parallel Circuit.

Series-Parallel Combination Circuits

Series-Parallel Combination Circuits

Circuits Any complete path along which electrons (charge, current) can flow. Can be arranged in series or in parallel.

Characteristics of Series & Parallel Circuits

Electrical Circuits & Ohm’s Law

Electric Circuits & Problem Solving!

Resistance, Ohm’s Law Physics 1161: Lecture 06 Georg Ohm

8 Series Circuits UEENEEE104A DC CIRCUITS PURPOSE:

Determine the current through each resistor, the total current and the voltage across each resistor. VB R4 R5.

(a) the equivalent resistance, (b) V0,

Circuits and Circuit Elements

SERIES-PARALLEL COMBINATION CIRCUITS

One Thing at a Time Series Circuits.

Circuits and Circuit Elements

Comparing Series and Parallel Circuits

Resistance in Series and Parallel

Resistance, Ohm’s Law & Circuits

Learning objectives Series Resistances Parallel Resistances

Fill in the gaps for the unknown Voltage and current readings

(b) ρ L R = A 1.59 x 10-8 (1.8) (a) (c) (d) (1) GIVEN = A

Combination Circuits.

Equivalent Resistance

Resistance and Ohm’s Law: More Practice

Electrical Circuits.

Series and Parallel Circuits

Aim: How do we explain Ohm’s Law?

Example Example 1: An electric lamp is rated 110 W, 200 V. When the lamp is operated at its rated power and voltage, calculate a) the current flowing through.

No; there is no continuous path resists light heat

Presentation transcript:

A circuit with several resistances but only one conducting path. SERIES CIRCUITS SERIES CIRCUITS A circuit with several resistances but only one conducting path. A circuit with several resistances but only one conducting path.

SERIES CIRCUIT FORMULA’S Req= R1 +R2 + R3 VT = V1+V2 +V3 IT = I1 =I2 =I3 Req- equivalent resistor If one resistor goes out, all three go out.

EXAMPLE A toaster of 60Ω, a lamp of 80Ω and a hair dryer of 100Ω are connected in series across a potential difference of 120V. Find the total resistance and current in the circuit. RT= R1 +R2 + R3 RT= 60Ω + 80Ω + 100Ω RT= 240Ω RT = VT / IT 240Ω = 120V/ IT IT = 0.50Amps

b) Find the drop in potential across each resistor. R1=V1/I1 R2= V2 / I2 60Ω =V1/ 0.5Amp 80Ω = V2 / 0.5Amp V1= 30V V2= 40V R3 = V3 / I3 100Ω = V3 / 0.5Amp V3 = 50V CHECK: VT = 30V + 40V + 50V = 120V √

c) Draw a circuit diagram V1=30V I1= 0.5 Amp = 60Ω VT =120V RT=240Ω IT=0.5Amp = 80Ω V2 = 40V I2 = 0.5Amp = 100Ω V3= 50V I3 = 0.5Amp