3.4 Solve by Factoring (Part 2)
Factoring Perfect-Square Trinomials If the first term and the last term of a trinomial are perfect squares but there is a center term It can not be the difference of perfect squares but it may be a perfect square trinomial
Example: x4 – 16 4x2 – 24x + 36 9x2 – 49 x2 + 16x + 28
Zero Product Property (ZPP) When finding the solutions to Quadratic Equations we need to use ZPP the Zero Product Property Solutions are also known as … Roots of the function Zeros of the function “x =” Where the graph crosses the x – axis To find solutions we must factor (completely) first then set the factors equal to zero and solve for “x”
Examples Find the roots/zeros of the equation. x2 – 2x – 15 = 0 (i.e. Find the answers) x2 – 2x – 15 = 0 x2 + 2x – 3 = 0
Homework Pg. 76, 1 – 29 odds Pg. 77, 3 – 24 (x 3’s) and 25 - 30