Trial & Improvement Friday, 24 May 2019
Example Andrew wants to work out, correct to one decimal place a solution to the equation 2 𝑥 2 =7 He tries by guessing the value of 𝑥 and starts with 𝑥=1.4. When 𝑥=1.4 he gets the result 3.92 He then tries 𝑥=1.9 and get the result 7.22 By using trial and improvement find the correct solution to one decimal place.
x = 1.3 to 1 decimal place Example Barry is trying to solve the equation 𝑥 2 +𝑥=3 by trial and improvement. Work out the value of x correct to one decimal place x 𝑥 2 +𝑥 Comment 2 6 Too big 1 2 Too small 1.5 3.75 Too big 1.4 3.36 Too big 1.3 2.99 Too small 1.35 3.1725... Too big x = 1.3 to 1 decimal place