Formulas pages 113–115 Exercises 12. y = –2x + 4 1. r = 13. y = ALGEBRA 1 LESSON 2-6 pages 113–115  Exercises 1. r = 2. d = 3. = – w 4. B = 5. h = 6. s = 7. b1 = – b2 8. h = 9. y = –2x + 5 10. y = 6x – 1 11. y = –4x + 3 12. y = –2x + 4 13. y = 14. y = 15. y = 16. y = 17. x = 18. g = 19. z = a + y 20. y = 21. t = 22. r = – 1 23. p = 24. y = mx + b 25. a. H = b. 11 ft 26. a. h = na b. 53 hits 27. a. p = b. $3000 c. If the interest at 3.5% for 4 yr is $420, the principal is $3000.00. 28. a. s = b. $494.20 C 2 5x + 9 3 N 7L C –3x + 7 4 P 2 –5x + 4 4 S – L 2 –2x + 4 7 I rt V w c d P 4 d c 2A h V r 2 c – ax b C 0.05 A – P Pr S C qm n 2-6

42. Answers may vary. Sample: Both types of equations are Formulas ALGEBRA 1 LESSON 2-6 29. b = 30. x = (y – 8) 31. p = 32. p = – r 33. h = 34. y = 35. b = 36. m = hw – k 37. h = 38. y = 3x – 2 39. y = w 40. x = m – 4 A h S 180 –V – 2.69 +0.104h 0.018 41. a. n = + 2 b. 5; 7; 4; 9 42. Answers may vary. Sample: Both types of equations are transformed in the same way. In solving a literal equation, you must be concerned about dividing by a variable where the value of the variable might be zero. 43. Check students’ work. 44. a. 5.85 b. b = 2m – a c. 5.9 45. a. A = b. 27 ft2 46. a = 47. B 48. I 49. B 50. G 51. 71, 72, 73 52. 42 cm 53. [–60  9] 54. 55. 3 2 r + b a 5 2 SA –2B 2 r 2x + 14 5 da c 3V r 2 14 –6.2 –16 1 2 3 4 s2 R –15.6 27 3 0 24 –28.5 3 2 2-6