Pg. 637 #15-18 15.) A.(18.9,25.1) We are 95% confident that the mean gain for all SAT math second-try scores to be between 18.9 and 25.1 points. 90%

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Pg. 637 #15-18 15.) A.(18.9,25.1) We are 95% confident that the mean gain for all SAT math second-try scores to be between 18.9 and 25.1 points. 90% interval is (19.4,24.6); 99% interval is (17,93,26.07) The confidence interval widens with increasing confidence level. 16.) A. (15.8, 28.2) (20.45, 23.55) The margin of error are 6.198, 3.099, and 1.550. The margin of error decreases as the sample size increases. 2401

17.) A. The calculations are correct. Since the numbers are based on a voluntary response instead of a SRS, the methods of this section cannot be used; the interval does not apply to the whole population. 18.) A. It is based on a method that captures the unknown parameter 95% of the time. Since the margin of error was 2%, the true value of p could be as low as 49%. Thus, some values in the interval would suggest that Bush will win. The proportion of voters who favor Kerry is not random- either a majority favors Kerry or they don’t. Discussing probability for a non-random event does not make sense.

20.) A. (449.48, 472.52) We are 99% confident that the mean SAT math score for all California seniors is between 449 and 473 points. 2655 students 23.) A. We can be 99% confident that between 63% and 69% of all adults favor such an amendment. The survey excludes people without telephones. 24.) A. The distribution appears to be roughly symmetric. (22.57,28.77) We are 90% confident that the mean rate of healing is between 22.57 and 28.77 micrometers per hour. Her interval is wider. To be more confident, you must have a wider confidence interval. 25.) 174 newts

Estimating a Population Mean Section 10.2

When you don’t know σ: 1.) Use standard error Sample std. dev. 1.) Use standard error 2.) Can’t use Normal Distribution… You use t distribution Symmetric, similar to Normal They are different, depending on sample size (n) Use degree of freedom (df)=n-1

t Distribution: More spread due to using sample standard deviation Less probability in the middle, more in the tails

t* Practice 80% confidence with n=12 90% confidence with n=20 99% confidence with n=47

Step 1: State population and parameter IN CONTEXT We are looking for the AVERAGE…

Step 2: Conditions SRS Normality- Possibilities: 1.) It could state it’s Normal 2.) If n>30, then CLT applies 3.) if we don’t know about the population, and n is less than 30: check data for symmetric and single peaked Independence: Population is 10 times the sample OR Observations are independent

Step 3: One Sample t-Interval t*=values in table C, based on df.

Step 4: We are _____% confident that the AVERAGE…(Write in context!)

Example: pg. 650 #32

Pg. 648 #27,28,30,31 Homework