Chapter 10.3 Announcements:

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Presentation transcript:

Chapter 10.3 Announcements: Homework 10.3: due Tuesday, April 16, in class Exercises: 30, 32, 33, 38, 40, 42 Problems: 19, 23, 24, 25, 26, 28, 29, 30 - Remember: Homework 9.2 is due Thursday, April 11, in class All grades will continue to be posted at: http://www.wfu.edu/~gutholdm/Physics110/phy110.htm Listed by last four digits of student ID We’ll now cover only parts of each chapter (let me know if you want me to cover something that is not on the list and that interests you): 5.1 Balloons 7.1 Woodstoves 9.1 Clocks 9.2 Musical Instruments 10.3 Flashlights 11. Household Magnets & Electric Motor 11.2 Electric Power Distribution 15.1. Optics, cameras, lenses 16.1 Nuclear Weapons

Electric circuits, Ohm’s law Chapter 10.3 Flashlights Electric circuits, Ohm’s law Demos and Objects Concepts How does a flashlight work building an electric circuit electric circuits current voltage voltage rises and drops resistance Ohm’s law; V = R·I electrons charge electric power, P = V·I

Observations About Flashlights (and electrical circuits) They turn on and off with a switch More batteries usually means brighter The orientation of multiple batteries matters Flashlights dim as batteries age

For a functioning circuit we need: battery, switch, light bulb, wire.

In a flashlight we are creating an: Electrical circuit An electrical current (electrons) runs through all the parts of the circuit (close circuit). No current flows when switch is open (open circuit). Electrons carry energy from batteries to the bulb. Short circuit: A path (short cut) in which the light bulb is cut out.

i-clicker-1 If you remove the 2 batteries from a working flashlight (shown below) and reinstall them backward so that they make good contact inside, will the flashlight still work? Yes No

A Battery Battery “pumps” charge from + end to – end Chemical potential energy is consumed Electrostatic potential energy is produced Current undergoes a rise in voltage Alkaline cell: 1.5 volt rise Lead-acid cell: 2.0 volt rise Lithium cell: 3.0 volt rise Chain of cells produces larger voltage rise

A Light Bulb Structure Filament barely lets charge flow through it Contains a protected tungsten filament Filament conducts electricity, but poorly Filament barely lets charge flow through it Electrostatic potential energy (voltage) is consumed Thermal energy is produced Current undergoes a drop in voltage Two-cell alkaline flashlight: 3.0 volt drop

How to connect a battery What’s wrong with each of the schemes shown in the Figure for lighting a flashlight with a flashlight battery and a single wire? (a) (b) (c) - There is no loop for the current to flow around. There is loop to and from the light bulb, but there is no potential difference. Nothing wrong here. The bulb will light up.

Electric Current Water Analogy h V water flow I Current: number of electrons passing through per second Water analogy: number of water molecules passing through per second

I

I Ohm’s Law V = I·R or I = V/R What determines the current through the circuit (Load)? Ohm’s Law V = I·R or I = V/R R I V V… Voltage; units, Volt, 1V I … Current; units, Ampere, 1A R … Resistance; units, Ohm, 1W So, 10V across a 100ohm load = 0.1 Amp Where 1 Amp = 1 coulomb/sec = 6.25 x 1018 e/sec 1 Amp=62,500,000,000,000,000,000 electrons/sec

Ohm’s Law V = I·R Count Alessandro Giuseppe Antonio Anastasio Volta (1745 –1827) was an Italian physicist known especially for the development of the first electric cell in 1800. André-Marie Ampère (1775 –1836) was a French physicist and mathematician who is generally regarded as one of the main discoverers of electromagnetism. Georg Simon Ohm (1789 – 1854) was a German physicist. As a high school teacher, Ohm began his research with the recently invented electrochemical cell, invented by Italian Count Alessandro Volta. Discovered the relationship, V = I·R, Ohm's law.

i-clicker-2; -3 A battery can produce 1.5 V. When connected to a light bulb a current of 2 A (Ampere) runs through the bulb. What is the resistance of the bulb? A bulb in a lamp that is connected to a household outlet has a resistance of 100 W. What current flows through it? Your skin has a resistance of about 106 to 104 W (dry) and 103 W (wet) . What current runs through you when you stick your finger into an outlet (conduction to ground)? 1A. 0.5 W 1B. 0.75 W 1C. 1.5 W 1D. 2.0 W 1E. 3.0 W 2A. 1.2 A 2B. 2.4 A 2C. 3.6 A 2D. 4.8 A 2E. 5.0 A

Electric shock The severity of an electric shock depends on the magnitude of the current, how long it acts and through what part of the body it passes. Can feel ~ 1 mA; pain at a few mA; severe contractions above 10 mA; heart muscle irregularities above 70 mA. Resistance of dry skin ~ 104 to 106 W; wet skin 103 W or less. A person in good contact with ground who touches a 120 V line with wet hands can suffer a current

Positive Charge A word about the sign convention…. Current points in the direction of positive flow Flow is really negative charges (electrons) It’s hard to distinguish between: negative charge flowing to the right positive charge flowing to the left We pretend that current is flow of + charges It’s really – charges flowing the other way

Power Power is energy per unit of time Power is measured in joules/second or watts Batteries are power sources Loads are power consumers

Battery Power power produced by the battery Current: units of charge pumped per second Voltage rise: energy given per unit of charge current · voltage rise = power produced P = Vrise·I Vrise I

current · voltage drop = power received Load Power Current is units of charge passed per second Voltage drop: energy taken per unit of charge current · voltage drop = power received Vdrop P = Vdrop·I I

i-clicker-4 A bulb in a lamp that is connected to a household outlet has a resistance of 100 W. How much power does it consume? (Note: Look at previous i-clicker) A. 120 J B. 120 W C. 144 J D. 144 W E. 100 J A Kilowatt-hour costs 10 cents. If you run 10 lamps for 10 hours, how much does that cost you?