Binding energy Electric potential energy => Nuclear Binding energy ( a mass loss! ) What is the energy change that occurs when constituent particles come.

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Presentation transcript:

Binding energy Electric potential energy => Nuclear Binding energy ( a mass loss! ) What is the energy change that occurs when constituent particles come together to create a nucleus?

Binding Energy The binding energy of the nucleus is the work done to separate the nucleus into its constituent parts When a nucleus is pulled apart then work must be done against the strong force. This energy (work) is identical to the binding energy of the nucleus. This in turn will result in a change in mass. An atomic nucleus has less mass than its constituent parts

A E Z

Calculating mass deficit Z 12 C 6 Calculating mass deficit Recall that the number of protons Z and the number of neutrons A-Z can be multiplied by the mass of a proton and neutron respectively to calculate the mass of the constituent parts. Subtracting this from the mass of the atomic nucleus will give the mass deficit. This can then be used with Einstein’s equation to find the energy change:

The electron volt eV is a unit of energy equal to the work done when an electron is accelerated through a pd of 1volt From; V = W Q W = QV but for an electron Q = e = 1.6x 10 -19 C Q1. Calculate the following in Joules: The KE of an electron accelerated through a pd of a. 1 Volt b. 1000 Volt c. 1 MV Q2. State the work done on each electron in eV for the question above. Q3. Calculate the work done (eV) on an ion of charge +2 when accelerated across 100V. Q4 What voltage is required to accelerate an electron of mass 9.1 x10-31 kg to 10% of the speed of light? c = 3 x 10 8 m/s

The electron volt eV is a unit of energy equal to the work done when an electron is accelerated through a pd of 1volt From; V = W Q W = QV but for an electron Q = e = 1.6x 10 -19 C Q1. Calculate the following in Joules: The KE of an electron accelerated through a pd of a. 1 Volt b. 1000 Volt c. 1 MV Q2. State the work done on each electron in eV for the question above. Q3. Calculate the work done (eV) on an ion of charge +2 when accelerated across 100V. Q4 What voltage is required to accelerate an electron of mass 9.1 x10-31 kg to 10% of the speed of light? c = 3 x 10 8 m/s

The electron volt eV is a unit of energy equal to the work done when an electron is accelerated through a pd of 1volt From; V = W Q W = QV but for an electron Q = e = 1.6x 10 -19 C Q. 4 Q1. Calculate the following in Joules: The KE of an electron accelerated through a pd of a. 1 Volt b. 1000 Volt c. 1 MV Q2. State the work done on each electron in eV for the question above. Q3. Calculate the work done (eV) on an ion of charge +2 when accelerated across 100V. Q4 What voltage is required to accelerate an electron of mass 9.1 x10-31 kg to 10% of the speed of light? c = 3x108 m/s KE = ½ mev2 = ½ 9.1 x10-31 x (3 x 107)2 = 4.1 x10-16 J 1.6 x10-19 J 1 eV 1.6 x10-16 J 1000 eV / by 1.6x 10 -19 C for volts 1.6 x10-13 J 1 MeV = 2560 V 200 eV

Atomic Mass Unit u The atomic mass unit u is defined as 1/12th the mass of a Carbon12 atomic nucleus. You can use this value for estimating the mass of a nucleus in the examination if you are not given the mass. Using E=mc2, u = 931.5 MeV

Nuclear Stability The binding energy per nucleon is the average energy needed to remove a nucleon from the nucleus. An increase in binding energy per nucleon means the nucleus will be more stable.

Nuclear Stability Any nucleus to the right of Iron (56) becomes more stable by getting smaller smaller (Fission) ( BE ≈ 0.5 Mev per nucleon) Any nucleus to the left of Iron (56) becomes more stable by getting bigger (Fusion) (BE ≈ 5 Mev per nucleon) ........................................................................................................................................................................................................ ........................................................................................................................................................................................................

Summary The binding energy is the same as the work that would be needed to be done to separate the nucleus into its constituent parts Einstein’s formula E=mc2 can be used to calculate the mass deficit in particles according to the energy changes that occur The atomic mass unit u is an average mass of a neutron or proton in a nucleus, derived from 1/12th the mass of a carbon 12 atom The binding energy per nucleon of an isotope is a measure of it’s relative stability