CSE 373 Data Structures Lecture 12

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Presentation transcript:

CSE 373 Data Structures Lecture 12 Binomial Queues CSE 373 Data Structures Lecture 12

Binomial Queues - Lecture 12 Reading Reading Section 6.8, 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Merging heaps Binary Heap has limited (fast) functionality FindMin, DeleteMin and Insert only does not support fast merges of two heaps For some applications, the items arrive in prioritized clumps, rather than individually Is there somewhere in the heap design that we can give up a little performance so that we can gain faster merge capability? 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Binomial Queues are designed to be merged quickly with one another Using pointer-based design we can merge large numbers of nodes at once by simply pruning and grafting tree structures More overhead than Binary Heap, but the flexibility is needed for improved merging speed 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Worst Case Run Times Binary Heap Binomial Queue Insert (log N) (log N) FindMin (1) O(log N) DeleteMin (log N) (log N) Merge (N) O(log N) 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Binomial queues give up (1) FindMin performance in order to provide O(log N) merge performance A binomial queue is a collection (or forest) of heap-ordered trees Not just one tree, but a collection of trees each tree has a defined structure and capacity each tree has the familiar heap-order property 2/10/03 Binomial Queues - Lecture 12

Binomial Queue with 5 Trees depth 4 3 2 1 number of elements 24 = 16 23 = 8 22 = 4 21 = 2 20 = 1 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Structure Property Each tree contains two copies of the previous tree the second copy is attached at the root of the first copy The number of nodes in a tree of depth d is exactly 2d B2 B1 B0 depth 2 1 number of elements 22 = 4 21 = 2 20 = 1 2/10/03 Binomial Queues - Lecture 12

Powers of 2 (one more time) Any number N can be represented in base 2: A base 2 value identifies the powers of 2 that are to be included 23 = 810 22 = 410 21 = 210 20 = 110 Hex16 Decimal10 1 1 3 3 1 4 4 1 1 5 5 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Numbers of nodes Any number of entries in the binomial queue can be stored in a forest of binomial trees Each tree holds the number of nodes appropriate to its depth, i.e., 2d nodes So the structure of a forest of binomial trees can be characterized with a single binary number 1012  1·22 + 0·21 + 1·20 = 5 nodes 2/10/03 Binomial Queues - Lecture 12

Structure Examples 4 4 8 5 8 7 22 = 4 21 = 2 20 = 1 22 = 4 21 = 2 N=210=102 22 = 4 21 = 2 20 = 1 N=410=1002 22 = 4 21 = 2 20 = 1 4 9 4 9 8 5 8 7 N=310=112 22 = 4 21 = 2 20 = 1 N=510=1012 22 = 4 21 = 2 20 = 1

Binomial Queues - Lecture 12 What is a merge? There is a direct correlation between the number of nodes in the tree the representation of that number in base 2 and the actual structure of the tree When we merge two queues of sizes N1 and N2, the number of nodes in the new queue is the sum of N1+N2 We can use that fact to help see how fast merges can be accomplished 2/10/03 Binomial Queues - Lecture 12

There are no comparisons and there is no restructuring. + BQ.2 9 BQ.1 Example 1. Merge BQ.1 and BQ.2 Easy Case. There are no comparisons and there is no restructuring. N=110=12 22 = 4 21 = 2 20 = 1 4 + BQ.2 8 N=210=102 22 = 4 21 = 2 20 = 1 4 9 = BQ.3 8 N=310=112 22 = 4 21 = 2 20 = 1

This is an add with a carry out. Example 2. Merge BQ.1 and BQ.2 This is an add with a carry out. It is accomplished with one comparison and one pointer change: O(1) 1 BQ.1 3 N=210=102 22 = 4 21 = 2 20 = 1 4 + BQ.2 6 N=210=102 22 = 4 21 = 2 20 = 1 1 = BQ.3 4 3 6 N=410=1002 22 = 4 21 = 2 20 = 1

BQ.1 Example 3. Merge BQ.1 and BQ.2 Part 1 - Form the carry. + BQ.2 7 Example 3. Merge BQ.1 and BQ.2 Part 1 - Form the carry. BQ.1 3 N=310=112 22 = 4 21 = 2 20 = 1 4 8 + BQ.2 6 N=310=112 22 = 4 21 = 2 20 = 1 7 = carry 8 N=210=102 22 = 4 21 = 2 20 = 1

Part 2 - Add the existing values and the carry. + BQ.2 7 1 7 + BQ.1 carry 8 3 N=210=102 22 = 4 21 = 2 20 = 1 N=310=112 22 = 4 21 = 2 20 = 1 4 8 Example 3. Part 2 - Add the existing values and the carry. + BQ.2 6 N=310=112 22 = 4 21 = 2 20 = 1 1 7 = BQ.3 4 3 8 6 N=610=1102 22 = 4 21 = 2 20 = 1

Binomial Queues - Lecture 12 Merge Algorithm Just like binary addition algorithm Assume trees X0,…,Xn and Y0,…,Yn are binomial queues Xi and Yi are of type Bi or null C0 := null; //initial carry is null// for i = 0 to n do combine Xi,Yi, and Ci to form Zi and new Ci+1 Zn+1 := Cn+1 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Exercise 4 9 2 13 1 8 7 10 15 12 N=310=112 22 = 4 21 = 2 20 = 1 N=710=1112 22 = 4 21 = 2 20 = 1 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 O(log N) time to Merge For N keys there are at most log2 N trees in a binomial forest. Each merge operation only looks at the root of each tree. Total time to merge is O(log N). 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Insert Create a single node queue B0 with the new item and merge with existing queue O(log N) time 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 DeleteMin Assume we have a binomial forest X0,…,Xm Find tree Xk with the smallest root Remove Xk from the queue Remove root of Xk (return this value) This yields a binomial forest Y0, Y1, …,Yk-1. Merge this new queue with remainder of the original (from step 3) Total time = O(log N) 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Implementation Binomial forest as an array of multiway trees FirstChild, Sibling pointers 0 1 2 3 4 5 6 7 1 2 5 5 2 1 4 7 10 9 9 4 7 10 13 8 12 15 13 8 12 15 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 DeleteMin Example FindMin 0 1 2 3 4 5 6 7 0 1 2 3 4 5 6 7 Remove min 5 2 1 5 2 9 4 7 10 9 4 7 10 13 8 12 13 8 12 15 15 Return this 1 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 0 1 2 3 4 5 6 7 0 1 2 3 4 5 6 7 Old forest 5 2 5 2 9 9 New forest 0 1 2 3 4 5 6 7 4 7 10 13 8 12 10 7 4 15 12 13 8 15 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 0 1 2 3 4 5 6 7 0 1 2 3 4 5 6 7 5 2 Merge 9 5 2 0 1 2 3 4 5 6 7 10 4 7 9 13 8 12 10 7 4 15 12 13 8 15 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Why Binomial? B4 B3 B2 B1 B0 tree depth d 4 3 2 1 nodes at depth k 1, 4, 6, 4, 1 1, 3, 3, 1 1, 2, 1 1, 1 1 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Other Priority Queues Leftist Heaps O(log N) time for insert, deletemin, merge The idea is to have the left part of the heap be long and the right part short, and to perform most operations on the left part. Skew Heaps (“splaying leftist heaps”) O(log N) amortized time for insert, deletemin, merge 2/10/03 Binomial Queues - Lecture 12

Binomial Queues - Lecture 12 Exercise Solution 4 9 2 13 1 + 8 7 10 15 12 2 1 4 7 10 9 13 8 12 15 2/10/03 Binomial Queues - Lecture 12