Chapter 1 Review Assessment 2 3 4 5 6 7 8 9 10 11 12 14 5 6 10 10 28 3 + xy, 3 + yx, or yx + 3 24 3 6 + a

6) Simplify: 3 • 4 + 2 • 8 12 + 16 = 28

9. Equivalent expression using the commutative property: xy + 3

12. Write an equivalent expression:

17 18 19 20 21 22 23 24 25 26 27 28 29 30 74 24=2•2•2•2 5x3=5•x•x•x 04 = 0 400 (5x)2 if x=4 8x5 48 3y2 if y=4 44 27 512 (4t)3 if t=2 (3•6)2 = 182 = 324 6+33 = 6+27 = 33 220 60

Use the associative property to write an equivalent expression: 31. (x + y) + 5

Use the associative property to write an equivalent expression: 31. (x + y) + 5 x + y + 5

3 • (a • b) 3a • 3b ?? (3 • a)• b (a • 3) • b b • (3 • a) 32. Use the commutative and the associative properties to write three equivalent expressions: 3 • (a • b) 3a • 3b ?? (3 • a)• b (a • 3) • b b • (3 • a)

24y Use the distributive property to write an equivalent expression:

Use the distributive property to write an equivalent expression: 18

Factor: 34. 8a + 12b  4•2•a + 4•3•b 4 ( ) 2a + 3b

Factor: 35. 18a + 6y + 12 6 ( ) 3a + y +2

Factor: 36. 3 + 12b + 36a 3 ( ) 1 + 4b +12a

15a Collect like terms: 38. 7a + 3b + 8a + 4b Variable (letter) and exponent must be exactly the same. Add the coefficients. 38. 7a + 3b + 8a + 4b 15a

15a + 7b Collect like terms: 38. 7a + 3b + 8a + 4b Variable (letter) and exponent must be exactly the same. Add the coefficients. 38. 7a + 3b + 8a + 4b 15a + 7b

9m + 16m2 Collect like terms: 39. 6m + 9m2 + 3m + 7m2 Variable (letter) and exponent must be exactly the same. Add the coefficients. 39. 6m + 9m2 + 3m + 7m2 9m + 16m2

X - 11 2n 6 + n w - 7 40 11 fewer than x 41 half of a number 42 Twice a number 43 Six more than a number 44 45 X - 11 2n 6 + n w - 7

Solve for the given replacement set. X 46. 5n – 4 = 11 {2, 3, 4} 5 • 2 – 4 = 11 ??? 5 • 3 – 4 = 11 yes

Solve for the given replacement set. X 47. x2 – x = 2 {0, 2, 4} 02 - 0 = 2 ??? 22 - 2 = 2 yes

Solve for the given replacement set. 48. 7.2y = 36 {5, 50, 500} 7.2 • 5 = 36

49. Each pair of equations are equivalent 49. Each pair of equations are equivalent. What was done to the first equation to get the second one? Both sides were multiplied by 2

50. Each pair of equations are equivalent 50. Each pair of equations are equivalent. What was done to the first equation to get the second one? 4 was added to both sides +4 +4

51. Find the distance (d) traveled by a train moving at the rate (r) of 50 mi/h for the time (t) of 3 h using the formula d = rt. d = r t d = 50 mi/h • 3 h d = 150 mi

52. Find the temperature in degrees Celsius (C) given a temperature of 77° Fahrenheit (F) using the formula 5 = 25 C