Practice for FA5.2.

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Presentation transcript:

Practice for FA5.2

1. a. A 0.145 kg baseball going 22.0 m/s straight up goes how high before stopping? 24.7 m W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

1 b. A baseball pitcher speeds a 0. 145 kg ball from rest to 38 1 b. A baseball pitcher speeds a 0.145 kg ball from rest to 38.0 m/s over a distance of 3.80 m. What must be the average force exerted on the ball? (Neglect friction or any change in elevation) 27.6 N W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

1 c. A 1340 kg car is moving at some speed at an elevation of 5 1 c. A 1340 kg car is moving at some speed at an elevation of 5.50 m partway up a hill, and then coasts to a stop at an elevation of 12.0 m. How fast was it going at 5.50 m elevation? (Neglect friction) 11.3 m/s W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

1 d. A 150. kg sled is going 3. 40 m/s at the top of a 2 1 d. A 150. kg sled is going 3.40 m/s at the top of a 2.50 m tall hill. At the bottom it hits a patch of dirt that exerts a slowing force of 180. N for 4.20 m. How fast is the sled going after the dirt patch? (Neglect friction) 7.10 m/s W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

2. a. A 0. 320 kg hammer is going 8. 20 m/s 2. a. A 0.320 kg hammer is going 8.20 m/s. What force would stop it in 0.120 m? 89.7 N W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

2 b. A 1530 kg car starts at rest and rolls down a hill 2 b. A 1530 kg car starts at rest and rolls down a hill. At the bottom it is going 13.6 m/s. How high was the hill? (Neglect friction) 9.44 m W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

2 c. Mom gives 55.0 kg Tamara a push from rest on her massless sled for a distance of 7.20 m at the top of a 3.80 m tall hill. If she is going 11.0 m/s at the bottom of the hill, what force did Mom exert at the top to speed her up? (Neglect friction) 178 N W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

2 d. A 410. kg rollercoaster car going 3 2 d. A 410. kg rollercoaster car going 3.40 m/s hits an accelerator that exerts a force of 780. N to speed up the car over a distance of 14.0 m. The car then rolls up a hill where it is going 4.20 m/s. What is the height of the hill? (Neglect friction) 2.41 m W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

3. a. A 5. 00 kg pendulum starts from rest 0 3. a. A 5.00 kg pendulum starts from rest 0.150 m above the lowest point. What is its speed when it reaches the lowest point? 1.71 m/s W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

3b. A 0. 170 kg ball is sped up with a 5 3b. A 0.170 kg ball is sped up with a 5.00 N force straight up from rest a vertical distance of 3.50 m. To what height does it rise above its lowest point before stopping? (Neglect air friction) 10.5 m W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

3c. A 0. 170 kg ball is sped up with a 5 3c. A 0.170 kg ball is sped up with a 5.00 N force straight up from rest a vertical distance of 3.50 m. What is the velocity of the ball when it is a height of 6.00 m above its lowest point? (Neglect friction) 9.40 m/s W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

3d. A 784 kg rollercoaster car is going 7. 50 m/s at the top of a 2 3d. A 784 kg rollercoaster car is going 7.50 m/s at the top of a 2.15 m tall hill. At what height is it when it is going 4.50 m/s? (Neglect friction) 3.99 m W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

question W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)

question W = Fd (pushed) PE = mgh (on a hill) KE = 1/2mv2 (moving)