Q = mL Melting or boiling a substance Q -> Potential Energy

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Presentation transcript:

Q = mL Melting or boiling a substance Q -> Potential Energy Q - Heat (in J) m - Mass (in kg) L - Latent heat (in J kg-1) of fusion = melting vaporization = boiling Q -> Potential Energy (Temperature does not rise)

Q = mL Melting or boiling a substance (in J kg-1) Fusion Vaporisation Some latent heats (in J kg-1) Fusion Vaporisation H2O 3.33 x 105 22.6 x 105 Lead 0.25 x 105 8.7 x 105 NH3 0.33 x 105 1.37 x 105 Notice that these are all huge Notice that vaporisation is more

Example: Dewey Cheatham melts 4.51 kg of lead. What heat is needed? Some latent heats (in J kg-1) Fusion Vaporisation H2O 3.33 x 105 22.6 x 105 Lead 0.25 x 105 8.7 x 105 NH3 0.33 x 105 1.37 x 105 Q = mL Q = ??, m = 4.51 kg, L = .25 x 105 J kg-1 112,750 J = 1.1 x 105 J 1.1 x 105 J

(in J kg-1) Fusion Vaporisation Helen Highwater pumps 45 MJ (45 x 106 J) of heat into some water at 100 oC. How much boils away? Some latent heats (in J kg-1) Fusion Vaporisation H2O 3.33 x 105 22.6 x 105 Lead 0.25 x 105 8.7 x 105 NH3 0.33 x 105 1.37 x 105 Q = mL Q = 45 x 106 J, m = ??, L = 22.6 x 105 J kg-1 19.91 kg 20. kg

(in J kg-1) Fusion Vaporisation Aaron Alysis has a 1500. Watt heater. What time will it take him to melt 12.0 kg of ice, assuming all of the heat goes into the water at 0 oC Some latent heats (in J kg-1) Fusion Vaporisation H2O 3.33 x 105 22.6 x 105 Lead 0.25 x 105 8.7 x 105 NH3 0.33 x 105 1.37 x 105 Q = mL, power = work/time (= heat/time) Q = ??, m = 12.0 kg, L = 3.33 x 105 Jokg-1 3,996,000 J, power = heat/time heat = 3,996,000 J, power = 1500. J/s 2660 seconds

(in J kg-1) Fusion Vaporisation Eileen Dover takes 1.42 kg of ice ( c = 2100 J oC-1kg-1) from -40.0 oC to water ( c = 4186 J oC-1kg-1) at 20.0 oC. What TOTAL heat is needed? Some latent heats (in J kg-1) Fusion Vaporisation H2O 3.33 x 105 22.6 x 105 Q = mciceT + mL + mcwaterT 711022.4 J 7.11 x 105 J