Reacting Masses and Volumes

Question What volume of CO2 will be produced when 20g of calcium carbonate reacts with excess HCl?

Step 1 Step 2 you know the amount of and Write a Balanced Equation for the reaction CaCO3 + 2HCl = CaCl2 + CO2 + H2O Step 2 Underline the substances that you know the amount of and you are asked to work out the amount of CaCO3 + 2HCl = CaCl2 + CO2 + H2O

Step 3 Write down the number of moles of each underlined substance in the equation CaCO3 + 2HCl = CaCl2 + CO2 + H2O 1 mole = 1 mole Step 4 Write down the units given and asked for in the question CaCO3 + 2HCl = CaCl2 + CO2 + H2O 1 mole = 1 mole g = cm3

Step 5 Convert the number of moles to the units given and asked for CaCO3 + 2HCl = CaCl2 + CO2 + H2O 1 mole 1 mole 100 g 22400 cm3

Step 6 Bring the substance you are given the amount of down to 1 Divide the other substance by the value of the substance brought down to 1 CaCO3 + 2HCl = CaCl2 + CO2 + H2O 1 mole 1 mole 100 g 22400 cm3 1 g = 22400/100 cm3

Step 7 Bring the substance you know the amount of up to the asked amount Multiply the other substance by the value of the substance you know the amount of CaCO3 + 2HCl = CaCl2 + CO2 + H2O 1 mole 1 mole 100 g 22400 cm3 1 g 22400/100 cm3 20 g = 20 * 22400/100 = 4480 cm3

Question How many molecules of hydrochloric acid would be needed to produce 10g of CO2?

Answer CaCO3 + 2 HCl = CaCl2 + CO2 + H2O 2 mole 1 mole 2 * 6 * 1023 molecules 44 g 2*6*1023 / 44 1 g 10 * 2*6*1023 / 44 10 g 2.7 * 1023

What mass of CaCO3 would be needed to produce 600 cm3 of CO2 [measured at STP]? 2.68g What volume would this gas occupy at RTP?