1.50 g. NH mol NH3 3.74 ( ) 1 mol = 17.00g STEP 1-Convert to moles

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1.50 g. NH3 0.08823 mol NH3 3.74 ( ) 1 mol = 17.00g STEP 1-Convert to moles 0.08595 mol O2 ( ) 2.75 g. O2 1 mol = 32.00g STEP 1.5 assess limiting reagent THEO ACTUAL The actual ratio is GREATER than the theoretical, therefore the reactant on top is in excess, the one on the bottom is limiting, oxygen limits! NH3 4 0.08823 = = O2 5 0.08595 = 0.80 1.02

4 NH3 5 O2 4 NO 6 H2O 0.08823 0.08595(lim) - 4 X - 5 X + 4 X + 6 X - 4 X - 5 X + 4 X + 6 X 0.08823 - 4(0.01719) 4 (0.01719) 6 (0.01719) + + X IS CALIBRATED TO THE LIMITING REAGENT, OXYGEN. 5 X = 0.08595 MOL LET X = 0.01719 MOL 0.06876 MOL 0.10314 MOL 0.01947 MOL 2.06 g. THEO YEILD 1.85 g. THEO YEILD 0.330 g. REMAIN (( 1.50-0.33)+2.75=3.91 REACTED REACTANTS 3.91 g. PRODUCTS =