Functions Test Review

What kind of slope is it? Purple Line: Red Line: Blue Line: Green Line:

What kind of slope is it? Purple Line: Undefined Red Line: Blue Line: Green Line:

What kind of slope is it? Purple Line: Undefined Red Line: Negative Blue Line: Green Line:

What kind of slope is it? Purple Line: Undefined Red Line: Negative Blue Line: Positive Green Line:

What kind of slope is it? Purple Line: Undefined Red Line: Negative Blue Line: Positive Green Line: Zero

Find the equation in slope intercept form given the following: Slope is -2 Passes through (5,-1)

Find the equation in slope intercept form given the following: Slope is -2 Passes through (5,-1) Plug in: y– y1 = m ( x – x1)

Find the equation in slope intercept form given the following: Slope is -2 Passes through (5,-1) Plug in: y– y1 = m ( x – x1) y – (-1) = (-2)(x-5)

Find the equation in slope intercept form given the following: Slope is -2 Passes through (5,-1) Plug in: y– y1 = m ( x – x1) y +1 = (-2)(x-5) distribute

Find the equation in slope intercept form given the following: Slope is -2 Passes through (5,-1) Plug in: y– y1 = m ( x – x1) y +1 = (-2)(x-5) y + 1 = -2x +10

Find the equation in slope intercept form given the following: Slope is -2 Passes through (5,-1) Plug in: y– y1 = m ( x – x1) y +1 = (-2)(x-5) y + 1 = -2x +10 -1 -1

Find the equation in slope intercept form given the following: Slope is -2 Passes through (5,-1) Plug in: y– y1 = m ( x – x1) y +1 = (-2)(x-5) y + 1 = -2x +10 -1 -1 y = -2x +9

What is the equation of line RS if R(-2,3) and S(2,-5)

What is the equation of line RS if R(-2,3) and S(2,-5) First, find the slope

What is the equation of line RS if R(-2,3) and S(2,-5) First, find the slope y2 – y1 x2 – x1

What is the equation of line RS if R(-2,3) and S(2,-5) First, find the slope y2 – y1 x2 – x1 -5– 3 2 – (-2) =

What is the equation of line RS if R(-2,3) and S(2,-5) First, find the slope y2 – y1 x2 – x1 -5– 3 2 – (-2) = -8 4 =

What is the equation of line RS if R(-2,3) and S(2,-5) First, find the slope y2 – y1 x2 – x1 -5– 3 2 – (-2) = -8 4 = = -2

What is the equation of line RS if R(-2,3) and S(2,-5) Slope = -2 Now we plug in:

What is the equation of line RS if R(-2,3) and S(2,-5) Slope = -2 Now we plug in: y– y1 = m ( x – x1)

What is the equation of line RS if R(-2,3) and S(2,-5) Slope = -2 Now we plug in: y– y1 = m ( x – x1) y – 3 = (-2)(x-(-2))

What is the equation of line RS if R(-2,3) and S(2,-5) Slope = -2 Now we plug in: y– y1 = m ( x – x1) y – 3 = (-2)(x+2)

What is the equation of line RS if R(-2,3) and S(2,-5) Slope = -2 Now we plug in: y– y1 = m ( x – x1) y – 3 = (-2)(x+2) distribute

What is the equation of line RS if R(-2,3) and S(2,-5) Slope = -2 Now we plug in: y– y1 = m ( x – x1) y – 3 = (-2)(x+2) y – 3 = -2x -4

What is the equation of line RS if R(-2,3) and S(2,-5) Slope = -2 Now we plug in: y– y1 = m ( x – x1) y – 3 = (-2)(x+2) y – 3 = -2x -4 +3 +3

What is the equation of line RS if R(-2,3) and S(2,-5) Slope = -2 Now we plug in: y– y1 = m ( x – x1) y – 3 = (-2)(x+2) y – 3 = -2x -4 +3 +3 y = -2x -1

What is the equation of line RS if R(-2,3) and S(2,-5) y– y1 = m ( x – x1) y – 3 = (-2)(x+2) y – 3 = -2x -4 +3 +3 y = -2x -1 So RS has the equation y=-2x-1

Find the equation of the line that passes through P and Q

Find the equation of the line that passes through P and Q Record the points Q P

Find the equation of the line that passes through P and Q Record the points P(-6,-3) Q(-2,3) Q P

Find the equation of the line that passes through P and Q Find the slope Q P

Find the equation of the line that passes through P and Q Find the slope Q y2 – y1 x2 – x1 P

Find the equation of the line that passes through P and Q Find the slope Q y2 – y1 x2 – x1 = 3-(-3) -2-(-6) P

Find the equation of the line that passes through P and Q Find the slope Q y2 – y1 x2 – x1 = 3 + 3 -2+6 P

Find the equation of the line that passes through P and Q Find the slope Q y2 – y1 x2 – x1 = 3 + 3 -2+6 P = 6 4

Find the equation of the line that passes through P and Q Find the slope Q y2 – y1 x2 – x1 = 3 + 3 -2+6 P = 6 4 3 2 =

Find the equation of the line that passes through P and Q m= 3/2 Q P

Find the equation of the line that passes through P and Q m= 3/2 P Q y– y1 = m ( x – x1)

Find the equation of the line that passes through P and Q m= 3/2 P Q y– y1 = m ( x – x1) y – 3 = (3/2)(x-(-2))

Find the equation of the line that passes through P and Q m= 3/2 P Q y– y1 = m ( x – x1) y – 3 = (3/2)(x+2)

Find the equation of the line that passes through P and Q m= 3/2 P Q y– y1 = m ( x – x1) y – 3 = (3/2)(x+2) y – 3 = (3/2)x+3

Find the equation of the line that passes through P and Q m= 3/2 P Q y– y1 = m ( x – x1) y – 3 = (3/2)(x+2) y – 3 = (3/2)x+3 y = (3/2)x + 6

What makes lines PARALLEL?

What makes lines PARALLEL? They have the SAME slope y = mx + b

What makes lines PARALLEL? They have the SAME slope y = mx + b Give me a line parallel to the given lines: y = 3x+7 y = -(1/2)x +(3/2) y = (1/3)x-1 y=-5 x=3

What makes lines PARALLEL? They have the SAME slope y = mx + b Give me a line parallel to the given lines: y = 3x+7 y = -(1/2)x +(3/2) y = (1/3)x-1 y = 3x-5 y = -(1/2)x+8 y = (1/3)x+1777 y=-5 x=3 y=7 x=-15

What makes lines PERPENDICULAR?

What makes lines PERPENDICULAR? Slopes are NEGATIVE RECIPROCALS y = mx + b

What makes lines PERPENDICULAR? Slopes are NEGATIVE RECIPROCALS y = mx + b Give me a line perpendicular to the given lines: y = 3x+7 y = -(1/2)x +(3/2) y = (1/3)x-1 y=-5 x=3

What makes lines PERPENDICULAR? Slopes are NEGATIVE RECIPROCALS y = mx + b Give me a line perpendicular to the given lines: y = 3x+7 y = -(1/2)x +(3/2) y = (1/3)x-1 y = -(1/3)x-12 y = 2x+8 y = -3x+5 y=-5 x=3 x=7 y=-15

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD Line AB y2 – y1 x2 – x1

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD Line AB y2 – y1 x2 – x1 9 - 3 1-(-2) =

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD Line AB y2 – y1 x2 – x1 9 -3 1+2 =

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD Line AB y2 – y1 x2 – x1 9 -3 1+2 6 3 = =

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD Line AB y2 – y1 x2 – x1 9 -3 1+2 6 3 = = = 2

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD Line AB: m = 2 Line CD: y2 – y1 x2 – x1 =

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD Line AB: m = 2 Line CD: y2 – y1 x2 – x1 7 - 5 -4-0 =

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD Line AB: m = 2 Line CD: y2 – y1 x2 – x1 2 -4 7 - 5 -4-0 = =

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD Line AB: m = 2 Line CD: m=(-1/2) y2 – y1 x2 – x1 2 -4 7 - 5 -4-0 1 -2 = = =

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD Line AB: m = 2 Line CD: m=(-1/2) Now that we have both slopes, are these lines parallel, perpendicular, or neither?

Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD Find the slopes of line AB and line CD Line AB: m = 2 Line CD: m=(-1/2) Now that we have both slopes, are these lines parallel, perpendicular, or neither? Perpendicular

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4 We know our slope and we have a point, so we plug in: y– y1 = m ( x – x1)

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4 We know our slope and we have a point, so we plug in: y– y1 = m ( x – x1) y – (-2) = (-3) (x-1)

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4 We know our slope and we have a point, so we plug in: y– y1 = m ( x – x1) y +2 = (-3) (x-1)

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4 We know our slope and we have a point, so we plug in: y– y1 = m ( x – x1) y +2 = (-3) (x-1) y +2=-3x +3

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4 We know our slope and we have a point, so we plug in: y– y1 = m ( x – x1) y +2 = (-3) (x-1) y +2=-3x +3

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4 We know our slope and we have a point, so we plug in: y– y1 = m ( x – x1) y +2 = (-3) (x-1) y +2=-3x +3 y = -3x +1

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4 We know our slope and we have a point, so we plug in: y– y1 = m ( x – x1) y +2 = (-3) (x-1) y +2=-3x +3 y = -3x +1 Now that we have the equation, we plug in 4 for x and solve to get the y value

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4 We know our slope and we have a point, so we plug in: y = -3x +1 y = (-3)(4) +1

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4 We know our slope and we have a point, so we plug in: y = -3x +1 y = (-3)(4) +1 y = -12 +1

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4 We know our slope and we have a point, so we plug in: y = -3x +1 y = (-3)(4) +1 y = -12 +1 y = -11

If line AB has a slope of -3 and B(1,-2) If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4 We know our slope and we have a point, so we plug in: y = -3x +1 y = (-3)(4) +1 y = -12 +1 y = -11 So A(4,-11)

Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)

Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3) Get the equation into y = mx + b form 5x -2y = 8

Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3) Get the equation into y = mx + b form 5x -2y = 8 -2y = -5x +8

Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3) Get the equation into y = mx + b form 5x -2y = 8 -2y = -5x +8 y = (5/2)x -4

Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3) Get the equation into y = mx + b form So m = (5/2) 5x -2y = 8 -2y = -5x +8 y = (5/2)x -4

Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3) Get the equation into y = mx + b form So m = (5/2) Since we are looking for the line PARALLEL to the above equation, the slope for our new equation is also 5/2 5x -2y = 8 -2y = -5x +8 y = (5/2)x -4

Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3) m = (5/2) Now that we have our slope and a point, Plug in: y– y1 = m ( x – x1)

Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3) m = (5/2) Now that we have our slope and a point, Plug in: y– y1 = m ( x – x1) y –(-3) = (5/2) (x-(-2))

Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3) m = (5/2) Now that we have our slope and a point, Plug in: y– y1 = m ( x – x1) y +3 = (5/2) (x+2)

Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3) m = (5/2) Now that we have our slope and a point, Plug in: y– y1 = m ( x – x1) y +3 = (5/2) (x+2) y +3 = (5/2)x +5

Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3) m = (5/2) Now that we have our slope and a point, Plug in: y– y1 = m ( x – x1) y +3 = (5/2) (x+2) y +3 = (5/2)x +5 y = (5/2)x +2

Find the distance of AB if A(-2,-3) and B(5,3)

Find the distance of AB if A(-2,-3) and B(5,3) PLUG IN:

Find the distance of AB if A(-2,-3) and B(5,3) PLUG IN: d = √(5-(-2)) 2+ (3-(-3))2

Find the distance of AB if A(-2,-3) and B(5,3) PLUG IN: d = √(5-(-2)) 2+ (3-(-3))2 d = √(5+2) 2+ (3+3)2

Find the distance of AB if A(-2,-3) and B(5,3) PLUG IN: d = √(5-(-2)) 2+ (3-(-3))2 d = √(5+2) 2+ (3+3)2 d = √(7) 2+ (6)2

Find the distance of AB if A(-2,-3) and B(5,3) PLUG IN: d = √(5-(-2)) 2+ (3-(-3))2 d = √(5+2) 2+ (3+3)2 d = √(7) 2+ (6)2 d = √49+ 36

Find the distance of AB if A(-2,-3) and B(5,3) PLUG IN: d = √(5-(-2)) 2+ (3-(-3))2 d = √(5+2) 2+ (3+3)2 d = √(7) 2+ (6)2 d = √49+ 36 = √85

Find the distance of AB if A(-2,-3) and B(5,3) PLUG IN: d = √(5-(-2)) 2+ (3-(-3))2 d = √(5+2) 2+ (3+3)2 d = √(7) 2+ (6)2 d = √49+ 36 = √85

Q is the bisector of segment PR Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R

Q is the bisector of segment PR Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R We are given the midpoint, and 1 endpoint. We must find the other endpoint.

Q is the bisector of segment PR Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R We are given the midpoint, and 1 endpoint. We must find the other endpoint. We find the X coordinate first. PLUG IN: x1 + x2 2 = x

Q is the bisector of segment PR Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R We are given the midpoint, and 1 endpoint. We must find the other endpoint. We find the X coordinate first. PLUG IN: x1 + x2 2 = x 3 + x2 2 = 3

Q is the bisector of segment PR Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R We are given the midpoint, and 1 endpoint. We must find the other endpoint. We find the X coordinate first. PLUG IN: x1 + x2 2 = x 3 + x2 2 = 3 3 + x2 = 6

Q is the bisector of segment PR Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R We are given the midpoint, and 1 endpoint. We must find the other endpoint. We find the X coordinate first. PLUG IN: x1 + x2 2 = x 3 + x2 2 = 3 3 + x2 = 6 x2 = 3

Q is the bisector of segment PR Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R We are given the midpoint, and 1 endpoint. We must find the other endpoint. Now we find the y coordinate. PLUG IN: x1 + x2 2 = x y1 + y2 2 = y 3 + x2 2 = 3 3 + x2 = 6 x2 = 3

Q is the bisector of segment PR Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R We are given the midpoint, and 1 endpoint. We must find the other endpoint. Now we find the y coordinate. PLUG IN: x1 + x2 2 = x y1 + y2 2 = y 3 + x2 2 = 3 4 + y2 2 = -2 3 + x2 = 6 x2 = 3

Q is the bisector of segment PR Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R We are given the midpoint, and 1 endpoint. We must find the other endpoint. Now we find the y coordinate. PLUG IN: x1 + x2 2 = x y1 + y2 2 = y 3 + x2 2 = 3 4 + y2 2 = -2 3 + x2 = 6 4 + y2 = -4 x2 = 3

Q is the bisector of segment PR Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R We are given the midpoint, and 1 endpoint. We must find the other endpoint. Now we find the y coordinate. PLUG IN: x1 + x2 2 = x y1 + y2 2 = y 3 + x2 2 = 3 4 + y2 2 = -2 3 + x2 = 6 4 + y2 = -4 x2 = 3 y2 = -8

Q is the bisector of segment PR Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R We are given the midpoint, and 1 endpoint. We must find the other endpoint. Now we find the y coordinate. PLUG IN: x2 = 3 y2 = -8 So R(3,-8)

Use the grid to complete the questions. Point A(-4,5) Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA

Plot your points, and find the coordinates of B and C Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA Plot your points, and find the coordinates of B and C

Plot your points, and find the coordinates of B and C Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA Plot your points, and find the coordinates of B and C A

5 4 Plot your points, and find the coordinates of B and C Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA Plot your points, and find the coordinates of B and C A 5 4

Use the grid to complete the questions. Point A(-4,5) Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA So B(0,0) A 5 B 4

Use the grid to complete the questions. Point A(-4,5) Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA So B(0,0) A B 8

Use the grid to complete the questions. Point A(-4,5) Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) A B 8 C

Use the grid to complete the questions. Point A(-4,5) Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB d = √(0-(-4)) 2+ (0-5)2 A B C

Use the grid to complete the questions. Point A(-4,5) Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB d = √(0+4) 2+ (0-5)2 A B C d = √(4) 2+ (-5)2

d = √(0+4) 2+ (0-5)2 d = √(4) 2+ (-5)2 d = √16+ 25 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB d = √(0+4) 2+ (0-5)2 A B C d = √(4) 2+ (-5)2 d = √16+ 25

d = √(0+4) 2+ (0-5)2 d = √(4) 2+ (-5)2 d = √16+ 25 d = √41 ≈6.4 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB d = √(0+4) 2+ (0-5)2 A B C d = √(4) 2+ (-5)2 d = √16+ 25 d = √41 ≈6.4

Segment AB= √41 d = √(0-0) 2+ (0-(-8))2 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC A B C d = √(0-0) 2+ (0-(-8))2

Segment AB= √41 d = √(0-0) 2+ (0+8)2 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC A B C d = √(0-0) 2+ (0+8)2

Use the grid to complete the questions. Point A(-4,5) Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC A B C d = √(0) 2+ (8)2

Segment AB= √41 d = √(0) 2+ (8)2 d = √0 + 64 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC A B C d = √(0) 2+ (8)2 d = √0 + 64

Segment AB= √41 d = √(0) 2+ (8)2 d = √64 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC A B C d = √(0) 2+ (8)2 d = √64

Segment AB= √41 d = √(0) 2+ (8)2 d = √64 d = 8 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC A B C d = √(0) 2+ (8)2 d = √64 d = 8

Segment AB= √41 Segment BC= 8 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC= 8 Segment AC A B C

Segment AB= √41 Segment BC= 8 d = √(0-(-4)) 2+ (-8-5)2 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC= 8 Segment AC A B C d = √(0-(-4)) 2+ (-8-5)2

Segment AB= √41 Segment BC= 8 d = √(0+4) 2+ (-8-5)2 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC= 8 Segment AC A B C d = √(0+4) 2+ (-8-5)2

Segment AB= √41 Segment BC= 8 d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC= 8 Segment AC A B C d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2

Segment AB= √41 Segment BC= 8 d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC= 8 Segment AC A B C d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2 d = √16+ 169

Segment AB= √41 Segment BC= 8 d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC= 8 Segment AC A B C d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2 d = √16+ 169

Segment AB= √41 Segment BC= 8 d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now that we have our coordinates we need to find our distances. Segment AB= √41 Segment BC= 8 Segment AC A B C d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2 d = √16+ 169 d = √185 ≈13.6

Now we find the midpoint of CA Segment AB= √41 Segment BC= 8 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now we find the midpoint of CA Segment AB= √41 Segment BC= 8 Segment AC = √185 A B C

Now we find the midpoint of CA Segment AB= √41 Segment BC= 8 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now we find the midpoint of CA Segment AB= √41 Segment BC= 8 Segment AC = √185 x1 + x2 , y1 + y2 2 2 A B C

Now we find the midpoint of CA Segment AB= √41 Segment BC= 8 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now we find the midpoint of CA Segment AB= √41 Segment BC= 8 Segment AC = √185 x1 + x2 , y1 + y2 2 2 A B C -4+0, 5+-8 2 2

Now we find the midpoint of CA Segment AB= √41 Segment BC= 8 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now we find the midpoint of CA Segment AB= √41 Segment BC= 8 Segment AC = √185 x1 + x2 , y1 + y2 2 2 A B C -4, 5+-8 2 2

= Now we find the midpoint of CA Segment AB= √41 Segment BC= 8 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) Now we find the midpoint of CA Segment AB= √41 Segment BC= 8 Segment AC = √185 x1 + x2 , y1 + y2 2 2 A B C -4, 5+-8 2 2 -4, -3 2 2 =

= midpoint of CA = (-2, (-3/2)) Segment AB= √41 Segment BC= 8 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) midpoint of CA = (-2, (-3/2)) Segment AB= √41 Segment BC= 8 Segment AC = √185 x1 + x2 , y1 + y2 2 2 A B C -4, 5+-8 2 2 -4, -3 2 2 =

= midpoint of CA = (-2, (-3/2)) Segment AB= √41 Segment BC= 8 Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA B(0,0) And C(0,-8) midpoint of CA = (-2, (-3/2)) Segment AB= √41 Segment BC= 8 Segment AC = √185 x1 + x2 , y1 + y2 2 2 A B C -4, 5+-8 2 2 -4, -3 2 2 =

Using the above questions,Find the perimete of triangle ABC Segment AB= √41 ≈6.4 Segment BC= 8 ≈13.6 Segment AC = √185 A B C

Find the perimete of triangle ABC ≈6.4 Segment AB= √41 A B C Segment BC= 8 ≈13.6 Segment AC = √185 Now that we have the lengths of the three sides, we can find the perimeter.

Find the perimete of triangle ABC Segment AB= √41 ≈6.4 A B C Segment BC= 8 ≈13.6 Segment AC = √185 Now that we have the lengths of the three sides, we can find the perimeter. AB + BC + AC = Perimeter

Find the perimete of triangle ABC Segment AB= √41 ≈6.4 A B C Segment BC= 8 ≈13.6 Segment AC = √185 Now that we have the lengths of the three sides, we can find the perimeter. AB + BC + AC = Perimeter 6.4 + 8 + 13.6=P

Find the perimete of triangle ABC Segment AB= √41 ≈6.4 A B C Segment BC= 8 ≈13.6 Segment AC = √185 Now that we have the lengths of the three sides, we can find the perimeter. AB + BC + AC = Perimeter 6.4 + 8 + 13.6=P P=28

Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept

Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept Since the function is given, USE THE CALCULATOR Go to y= and plug in the function

Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept Since the function is given, USE THE CALCULATOR Go to y= and plug in the function To find the vertex, Hit graph 2nd TRACE to get to CALC 3-minimum Go to left hit ENTER Go to right hit ENTER ENTER Displays x=2, y=2 so the VERTEX is (2,2)

Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept To get the axis of symmetry Use the x value of the vertex[(2,2)] is the axis of symmetry

Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept To get the axis of symmetry Use the x value of the vertex[(2,2)] is the axis of symmetry So the axis of symmetry is x=2

Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept To find the y intercept: Hit 2nd, GRAPH to get to TABLE Look at the table and find where x=0, what is y?

Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept To find the y intercept: Hit 2nd, GRAPH to get to TABLE Look at the table and find where x=0, what is y? x=0, y=6 So the y intercept is (0,6)