Lens Equation Word Problems

Slides:

Advertisements

Similar presentations

Mirror and Lens Properties. Image Properties/Characteristics Image Type: Real or Virtual Image Orientation: Erect or Inverted Image Size: Smaller, Larger,

Advertisements

Reflection from Curved Mirrors. 2 Curved mirrors The centre of the mirror is called the pole. A line at right angles to this is called the principal axis.

Curved Mirrors.

(10.3/10.4) Mirror and Magnification Equations (12.2) Thin Lens and Magnification Equations.

26.6 Lenses. Converging Lens Focal length of a converging lens is real and considered positive.

-Terminology -drawing images in mirrors.  Plane Mirror: ◦ A planar reflecting surface  Virtual Image ◦ Image formed by light reflecting off of a mirror.

Curved Mirrors. Two types of curved mirrors 1. Concave mirrors – inwardly curved inner surface that converges incoming light rays. 2. Convex Mirrors –

A. can be focused on a screen. B. can be projected on a wall.

Curved Mirrors Chapter 14, Section 3 Pg

Ray Diagrams Basics Mirror Equations

Mirror Equation Ray diagrams are useful for determining the general location and size of the image formed by a mirror. However, the mirror equation and.

Unit 3 – Light & Optics. v  There are five (5) different situations, depending on where the object is located.

Thin Lens Optics Physics 11. Thin Lens Optics If we have a lens that has a small diameter when compared to the focal length, we can use geometrical optics.

Today’s agenda: Death Rays. You must know when to run from Death Rays. Refraction at Spherical Surfaces. You must be able to calculate properties of images.

Unit 3: Light.  Symbols used: ◦ Ho- height of the object ◦ Hi- height of the image ◦ m-magnification ◦ do (or p)- distance between object and vertex.

Thin Lenses. Two Types of Lenses Converging – Thicker in the middle than on the edges FOCAL LENGTH (+) POSITIVE Produces both real and virtual images.

Reflection & Mirrors Topic 13.3 (3 part lesson).

Starter (5 mins): Draw ray diagrams

Spherical Mirrors A spherical mirror has the shape of a section of a sphere The mirror focuses incoming parallel rays to a point (focal point) A concave.

College Physics, 7th Edition

Lenses – An application of refraction

Lenses Topic 13.4.

Draw ray diagrams: An object is standing 3 m away from a convex lens with focal length 2 m. An object is standing 2 m away from a convex lens with focal.

Light and Reflection.

Chapter 17 Objectives: 1) Define the Law of Reflection and use a plane mirror as an example. 2) Differentiate between regular and diffuse reflection. 3)

RAY DIAGRAMS FOR MIRRORS

Chapter 18 Mirrors/lenses.

Mirror Equations Lesson 4.

A light beam striking a boundary between two media can be partly transmitted and partly reflected at the boundary.

06 – Concave or Converging Mirrors

Curved Mirror Equations

7. Spherical mirror 1) Mirror equation h C di do Example:

SPHERICAL MIRROR EQUATIONS

13.4 The Lens Equation.

What Happens When… Light is transmitted through a glass shaped like a triangle? Light is transmitted straight toward a glass shaped like a square?

Thin Lenses-Intro Notes

Reflections in Mirrors

Chapter 7 Light and Geometric Optics

Refraction at Spherical Surfaces.

Free-Response-Questions

MIRROR EQUATIONS.

Millions of light rays reflect from objects and enter our eyes – that’s how we see them! When we study the formation of images, we will isolate just a.

2nd period: TX 146 3rd period: VA 144

Unit 8, Lesson 7 Convex Lenses.

Millions of light rays reflect from objects and enter our eyes – that’s how we see them! When we study the formation of images, we will isolate just a.

Millions of light rays reflect from objects and enter our eyes – that’s how we see them! When we study the formation of images, we will isolate just a.

Light and Reflection Curved Mirrors.

Ray Diagrams for spherical mirrors

Geometrical Optics Seminar add-on Ing. Jaroslav Jíra, CSc.

Images Formed by Lenses

Chapter 13 Light and Reflection

Optics Mirrors and Lenses.

Equations with Lenses SNC2D.

Summary of Sign Conventions

Lens Equations.

Lenses Physics Mr. Berman.

Mirrors Physics Mr. Berman.

Mirror Equations.

Thin Lens Equation 1

F = 1.75 cm 2F = C = 3.50 cm do = 3 cm ho = 1 cm F MEASURED

Mirrors Reflection of Light.

SPHERICAL MIRROR EQUATIONS

Presentation transcript:

Lens Equation Word Problems Seo Physics

Word problem terminologies 1) Spherical center = radius of curvature 2) Focal point = half of the radius of curvature 3) Converging lens = convex lens 4) Diverging lens = concave lens 5) Double concave lens = concave mirror

Mirror equation review Lens Equation? 1 + 1 = 1 do di f do di

Magnification review hi = -di = M do ho ho hi Magnification ratio equation? hi = -di = M ho do ho hi

Practice 1 An object is 3.3 cm high is 22.0 cm from a concave lens. The radius of curvature is 25 cm. A) Draw the Ray Diagram B) Image Characteristics Image is Reduced, Real, and Inverted 3.3 cm hi 22 cm

di = 29.0 cm hi = -4.35 cm Practice 1 (con.) 1 + 1 = 1 do di f An object is 3.3 cm high is 22.0 cm from a concave lens. The radius of curvature is 25 cm. (Focal length is half of the radius curvature. f= 12.5 cm). 1 + 1 = 1 do di f C) Find the Image distance 1 = 1 - 1 22 cm di 12.5 cm = 0.08 cm- 0.045 cm di = 29.0 cm 1/di= 0.0345 cm hi = -di = M ho do D) Find the height of the Image hi = -4.35 cm hi = -di x ho do hi = -29 cm x 3.3 cm 22 cm

DIY A bird 2.0 cm high is 30.0 cm from a concave lens. The radius of curvature is 20.0 cm. A) Draw the Ray Diagram B) Image Characteristics Image is Reduced, Real, and Inverted 2 cm hi 30 cm

di = 15 cm hi = -1 cm DIY (con.) 1 + 1 = 1 do di f 1 = 1 - 1 A bird 2.0 cm high is 30.0 cm from a concave mirror. The radius of curvature is 20.0 cm (focal length is half of the radius curvature= 10 cm) 1 + 1 = 1 do di f C) Find the Image distance 1 = 1 - 1 30 cm di 10 cm = 0.1 cm – 0.03cm di = 15 cm 1/di= 0.0667 cm hi = -di = M ho do D) Find the height of the Image hi = -1 cm hi = -di x ho do hi = -15 cm x 2.0 cm 30 cm

Practice 2 hi ho 20 cm 15 cm B) Image Characteristics A bird that is 5 cm high is placed 15 cm in front of a converging lens with focal length of 20 cm. A) Draw the Ray Diagram ho hi 20 cm 15 cm B) Image Characteristics Image is Reduced, Inverted and Virtual

di = -58.82 cm hi = 19.60 cm Practice 2 (con.) 1 + 1 = 1 do di f A bird that is 5 cm high is placed 15 cm in front of a converging lens with focal length of 20 cm. 1 + 1 = 1 do di f C) Find the Image distance 1 = 1 - 1 15 cm di 20 cm = 0.05 cm – 0.067cm di = -58.82 cm 1/di= -0.017 cm hi = -di = M ho do D) Find the height of the Image hi = 19.60 cm hi = -di x ho do hi = 58.82 cm x 5.0 cm 15 cm

DIY hi ho 20 cm 35 cm B) Image Characteristics A bird is 10 cm high and placed 35 cm in front of a converging lens with radius of curvature of 20 cm. A) Draw the Ray Diagram ho hi 20 cm 35 cm B) Image Characteristics Image is Reduced, Inverted and Virtual

di = 14.28 cm hi = -4.08 cm DIY (con.) 1 + 1 = 1 do di f 1 = 1 - 1 A bird is 10cm high and placed 35 cm in front of a converging lens with radius of curvature of 20 cm. 1 + 1 = 1 do di f C) Find the Image distance 1 = 1 - 1 35 cm di 10 cm = 0.1 cm – 0.03cm di = 14.28 cm 1/di= 0.07 cm hi = -di = M ho do D) Find the height of the Image hi = -4.08 cm hi = -di x ho do hi = -14.28 cm x 10.0 cm 35 cm