Lectures prepared by: Elchanan Mossel Yelena Shvets

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Lectures prepared by: Elchanan Mossel Yelena Shvets Introduction to probability Stat 134 FAll 2005 Berkeley Lectures prepared by: Elchanan Mossel Yelena Shvets Follows Jim Pitman’s book: Probability Section 5.4

Operations on Random Variables Question: How to compute the distribution of Z = f(X,Y)? Examples: Z=min(X,Y), Z = max(X,Y), Z=X+Y, . Answer 1: Given the joint density of X and Y, f(X,Y), We can calculate the CDF of Z, fZ(z) by integrating over the appropriate subsets of the plane. Recall: If X & Y are independent the joint density is the product of individual densities: f(x,y) = fX(x) fY(y), However, in general, it is not enough to know the individual densities.

Distribution of Z = X+Y Discrete case: Continuous case: Therefore: And: For independent X & Y:

Distribution of Z = X+Y – using CDF

Sum of Independent Exponentials Suppose that T & U are independent exponential variables with rate l. Let S = T + U, then fS(s) is given by the convolution formula:

Sum of Independent Uniform(0,1) If X,Y » Unif(0,1) and Z = X + Y then 2 1 2

Sum of Independent Uniform(0,1) If X,Y,W » Unif(0,1) and T = X + Y+W then T = Z + W, 0<t<1 1<t<2 2<t<3 2 2 2 1 1 1 1 2 1 2 1 2

Sum of Three Independent Uniform(0,1) The density is symmetric about t=3/2. 1 2 3

Example: Round-off errors Problem: Suppose three numbers are computed, each with a round-off error Unif(-10-6,10-6) independently. What is the probability that the sum of the rounded numbers differs from the true sum by more than 2£ 10-6? Solution: x1 + R1 x2 + R2 x3 + R3 Ri» Unif(-10-6, 10-6) x1 + R1 + x2 + R2 + x3 + R3 = x1 + x2 + x3 +( R1 + R2 + R3 ) Want: p = 1 - P(-2 £ 10-6 < R1 + R2 + R3 < 2 £ 10-6 ) Let: Ui = (Ri /10-6 + 1)/2. Ui ~ Unif(0,1) are independent. p = 1 - P(1/2 < U1 + U2 + U3 < 5/2) = 2P(T>5/2) = 2/48.

Ratios Let Z = Y/X, then for z>0, the event Z 2 dz is shaded. For independent X & Y:

Ratio of independent normal variables Suppose that X & Y»N(0,s), and independent. Question: Find the distribution of X/Y. We may assume that s =1, since X/Y = X/s / Y/s. This is Cauchy distribution.

Distribution of Z = Y/X – using CDF