Torque Wrench
Torque calculation 30cm pivot 10N ⏆ = F⏊d ⏆ = (10)⏊(.3) ⏆ = 3 Nm
Torque calculation 1 ? F ⏊ Sin ⍬ = O/h O = sin ⍬ (h) O = sin 60 (10) F ⏊ = 8.66 N ⏆ = F⏊d 8.66 N (.3) = 2.60 Nm
Approaches to Torque Where is the pivot point? What was the force applied ⏊ to the axis of rotation? How far from the pivot point was the force applied? Consider the sign conventions for the torque: Clockwise is NEGATIVE Counterclockwise is POSITIVE *do not blame me – I did not make it up!!!!
Torque calculation 2 - + F⏊ = 40 cos ⍬ = 40 cos 50 F⏊ = 60N cos ⍬ ⏆ = F⏊d = 40N (cos 50) (.2m) = -5.14 Nm ⏆ = F⏊d = 60N (cos 50) (.1m) = +3.86 Nm Sum: 3.86 – 5.14 = -1.28 Nm
Torque calculation 3 try this one on your own
Torque calculation 3 - + + ⏆ = F⏊d = + 40N 1m F⏊ = 60N sin 40 = +40 Nm ⏆ total = - 19.28 + 40 = + 21 Nm