Predicting Products

Single Displacement Use activity series of metals If metal C is more active than A, then it replaces less active metal A. AB + C  CB + A If metal F is less reactive than metal D, it cannot bump off D & reaction does not occur DE + F  no reaction

Activity Series p 148 General Trends of metal activity (how well they can displace): Lighter metals bump off heavier metals Metals with +1 charges will bump metals with +2 charges How to read table 4-12: the higher up a metal, the more active it is. Not perfect trends: Ca2+ displaces Na+

NaCl + F2 ---> NaF + Cl2 NaF + Cl2 ---> No reaction

MgCl2 + Na  KBr + Cl2  FeCl3 + Cu  Na2SO4 + Cu 

Double Displacement or Metathesis Use solubility tables p134 – 135 For rxn to occur, precipitate (ppt) must form

BaCl2(aq)+ K2SO4(aq) -----> BaSO4(s)+ KCl(aq)

3 ways to write reactions (when they’re in aqueous solutions): (p136) Formula unit equations 2 AgNO3 (aq) + Cu (s)  2 Ag (s) + Cu(NO3) (aq) Total Ionic equations 2 [Ag+(aq) + NO3- (aq)] + Cu(s)  2 Ag (s) + [Cu+(aq) + 2NO3- (aq) Net Ionic equations 2 Ag+ (aq) + Cu (s)  2 Ag (s) + Cu2+ (aq)

NaCl(aq) + KBr(aq) -----> NaBr(aq) + KCl(aq) How is this reaction written? Rewrite as total ionic. Can you rewrite as net ionic? No! Only spectator ions!

Na+ (aq) + Cl- (aq) + K+ (aq) + Br- (aq). -----> Na+ (aq) + Cl- (aq) + K+ (aq) + Br- (aq) -----> Na+ (aq) Br- (aq) + K+ (aq) + Cl- (aq)

DD or Metathesis Acid-base: When an acid is combined with a base, the products will be salt & water

HCl(aq) + NaOH(aq) -----> NaCl(aq) + H2O(l)

Mg(OH)2(aq) + H2SO4(aq)  MgSO4(aq) + H2O(l)

Ba(OH)2(aq) + CaCl2(aq) ZnCl2(aq) + K2CrO4(aq) KCl(aq) + Na2SO4(aq)

HCl(aq) + NaOH(aq) H2SO4(aq) + KOH(aq) HCl(aq) + NH3(aq)

Carbon compound + oxygen yields Carbon dioxide & water Combustion Carbon compound + oxygen yields Carbon dioxide & water

C3H6(g) + O2(g) C4H8O(l) + O2(g) C4H8O4(g) + O2(g)

Predict Products & Balance Rxn CaCl2 + F2  CaCl2 + Na  CaCl2 + KNO3  CaCl2 + K2SO4 

Predict & Balance AlBr3 + F2  AlBr3 + Zn  AlBr3 + Na  AlBr3 + Ba(NO3)2  AlBr3 + K2SO4 

Calculate the mass of solid product formed when 4 Calculate the mass of solid product formed when 4.16 g of barium chloride is added to 250 ml of 0.40 M potassium sulfate: