Chapter 3: Independent Events

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Chapter 3: Independent Events http://www.cartoonstock.com/directory/p/probability.asp

Example: Independence Roll a red 4 sided die and a white 4 sided die. Let A: event that the red die is a 1 B: event that the white die is a 1 C: event that the sum of the two dice is 4 Are events A and B independent? Are events A and C independent?

Example: Disjoint and Independent Roll a red 4 sided die and a white 4 sided die. Are each of the following disjoint and/or independent? 1) A: event that the red die is a 1 B: event that the red die is a 2 2) A: event that the red die is a 1 B: event that the white die is a 2 3) A: event that the red die is a 1 B: event that the sum of the two dice is 4

Example: Pairwise Independence Roll a red 4 sided die and a white 4 sided die. Let A: event that the red die is even B: event that the white die is even C: event that the sum of the two dice is even Show that A, B, and C are pairwise independent. Show that A ∩ B and C are NOT independent.

Example: Mutual Independence Roll a red 6 sided die and a white 6 sided die. Let D: event that the red die is 1 or 2 or 3 E: event that the white die 4 or 5 or 6 F: event that the sum of the two dice is 5 Show that P(D ∩ E ∩ F) = P(D)P(E)P(F) but D, E and F are NOT (mutually) independent events.

Example 3.19: Independence A student flips a coin until the tenth head appears. Let A denote the event that at least 3 flips are needed between the 7th and 8th heads; let B denote the event that at least 3 flips are needed between the 8th and 9th heads. What would be considered the trial? Are A and B independent?

Example: Independence (cont.) If the probability that a fuse is good in a particular batch of fuses is 0.8 and each fuse is independent of the other fuses, what is the probability that 2 fuses are bad?

Theorem 3.24: Good before Bad Consider a sequence of independent trials, each of which can be classified as good, bad, or neutral, which happen (on any given trial) with probabilities p, q, and 1 – p – q. (We do not necessarily have q = 1 – p here, although that is allowed.) Then the probability that something good happens before something bad happens is 𝑝 𝑝+𝑞 .