Graph Algorithm.

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Presentation transcript:

Graph Algorithm

Topological Sort Definition A topological sort of a DAG G is a linear ordering of all its vertices such that if G contains a link (u,v), then node u appears before node v in the ordering b 1 b c a c a 2 3 d d 4

Algorithm Example find source nodes (indegree = 0) if there is no such node, the graph is NOT DAG in_deg=1 in_deg=1 a f in_deg=0 in_deg=3 c e Queue b d c in_deg=2 in_deg=1 Sorted: -

span c; decrement in_deg of a, b, e store a in Queue since in_deg becomes 0 in_deg=0 in_deg=1 a f in_deg=0 in_deg=2 c e Queue a b d c in_deg=1 in_deg=1 Sorted: c

span a; decrement in_deg of b, f store b, f in Queue since ... in_deg=0 in_deg=0 a f in_deg=0 in_deg=2 c e Queue f b b d a in_deg=0 in_deg=1 Sorted: c a

span b; store d in Queue in_deg=0 in_deg=0 in_deg=0 in_deg=2 Queue f in_deg=0 in_deg=2 c e Queue d f b d b in_deg=0 in_deg=0 Sorted: c a b

span f; decrement in_deg of e no node with in_deg = 0 is found in_deg=0 in_deg=0 a f in_deg=0 in_deg=1 c e Queue d b d f in_deg=0 in_deg=0 Sorted: c a b f

span d; store e in Queue. in_deg=0 in_deg=0 in_deg=0 in_deg=0 Queue f in_deg=0 in_deg=0 c e Queue e b d d in_deg=0 in_deg=0 Sorted: c a b f d

span e; Queue is empty in_deg=0 in_deg=0 in_deg=0 in_deg=0 Queue f in_deg=0 in_deg=0 c e Queue b d e in_deg=0 in_deg=0 Sorted: c a b f d e

Example Algorithm Summary Based on indegree of each vertex if it is 0, this node is the first one in the sorted list span this node move this node from Queue to the sorted list find nodes edged from this node decrement indegrees of them It is so similar to BFS can you do it like DFS?

입력차수 ‘0’인 노드에서 시작! 큐가 비워질 때 까지 루프내의 동작을 수행! 노드 y와 연결된 노드의 입력차수를 하나씩 감소! 입력차수가 ‘0’인 노드가 생성되면 큐에 저장!

Degrees Summary number of edges connected to a vertex for undirected graphs sum of all degrees = 2 X edges the number of nodes with odd numbered degrees is even? for directed graph sum of in-degree = sum of out-degree

Conectivity connected articulation vertex there exists a path between every pair of vertices articulation vertex deleting this vertex makes the graph disconnected a graph without any such vertex is biconnected deleting a bridge edge makes the graph disconnected

Cycles A tree does not have a cycle Eulerian cycle a tour that visits every edge exactly once Hamiltonian cycle (path) a tour that visits every vertex exactly once

Spanning Tree Given a graph G = (V, E) and tree T = (V, E) for all (u, v) in E u, v  V for all connected graph, there exists a spanning tree A spanning tree can be constructed using DFS or BFS

Minimal Spanning Tree sum of edge weights is minimal if there is no weight number of edges is minimal why is it so important? search space is minimal for most problems

Example of MST: Prim’s Algorithm

Vertex D has been chosen as a starting point Vertices A, B, E, F are connected to D through a single edge. A is the nearest to D and thus chosen as the 2nd vertex along with the edge AD

The next vertex chosen is the vertex nearest to either D or A The next vertex chosen is the vertex nearest to either D or A. So the vertex F is chosen along with the edge DF

same as 2, Vertex B is chosen.

among C, E, G, E is chosen.

among C and G, C is chosen.

G is the only remaining vertex.

The finally obtained minimum spanning tree  the total weight is 39

dist: array of distances from the source to each vertex edges: array indicating, for a given vertex, which vertex in the tree it is closest to i: loop index F: list of finished vertices U: list or heap of unfinished vertices /* initialization */ for i=1 to |V| dist[i] = INFINITY edges[i] = NULL end for pick a vertex s to be the seed for the MST dist[s] = 0 while(F is missing a vertex) pick the vertex v in U with the shortest edge and add v to F for each edge of v, (v1, v2) if (length(v1, v2) < dist[v2]) dist[v2] = length(v1, v2) edges[v2] = v1 possibly update U, depending on implementation end if end while /* this loop looks through every neighbor of v and checks to see if that neighbor could reach the MST more cheaply through v than by linking a previous vertex

Dijkstra’s Algorithm Goal: Find the shortest path from s to t 2 3 s 6 24 3 9 s 18 14 2 6 6 4 30 19 11 15 5 5 6 20 16 t 7 44

All Pairs Shortest Paths Use Dijkstra’s method for all the vertices complexity? Floyd’s method Given the adjacency matrix with vertices numbered (1..n)

Network Flow (Today’s Problem) Think edges as pipes what’s the maximum flow from node 1 to node 5?