PHYS 3446 – Review Review Note Test deferred until Weds.

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PHYS 3446 – Review Review Note Test deferred until Weds. Wednesday, Mar. 21, 2012 Dr. Andrew Brandt Review Note Test deferred until Weds. Quiz Monday, along with lecture on project and HW questions Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

History of Atomic Models cnt’d Lec.2 atomic models elastic scattering Rutherford scattering Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Elastic Scattering Lec.3 look at limiting cases ma q After Collisions ma mt f mt From momentum conservation From kinetic energy conservation (Elastic only!) From these, we obtain Eq. 1.2 Eq. 1.3 look at limiting cases Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Rutherford Scattering From the solution for b, we can learn the following For fixed b, E and Z’ The scattering is larger for a larger value of Z. Since Coulomb potential is stronger with larger Z. For fixed b, Z and Z’ The scattering angle is larger when E is smaller. Since the speed of the low energy particle is smaller The particle spends more time in the potential, suffering greater deflection For fixed Z, Z’, and E The scattering angle is larger for smaller impact parameter b Since the closer the incident particle is to the nucleus, the stronger Coulomb force it feels Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Total Cross Section lec. 4 diff +total xsec Total cross section is the integration of the differential cross section over the entire solid angle, W: Total cross section represents the effective size of the scattering center integrated over all possible impact parameters (and consequently all possible scattering angles) Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Total X-Section of Rutherford Scattering To obtain the total cross section of Rutherford scattering, one integrates the differential cross section over all q: What is the result of this integration? Infinity!! Does this make sense? Yes Why? Since the Coulomb force’s range is infinite (particle with very large impact parameter still contributes to integral through very small scattering angle) What would be the sensible thing to do? Integrate to a cut-off angle since after certain distance the force is too weak to impact the scattering. (q=q0>0); note this is sensible since alpha particles far away don’t even see charge of nucleus due to screening effects. Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

lec 4 Lab Frame and CM Frame The CM is moving at a constant velocity in the lab frame independent of the form of the central potential The motion is that of a fictitious particle with mass m (the reduced mass) and coordinate r. In the frame where the CM is stationary, the dynamics becomes equivalent to that of a single particle of mass m scattering off of a fixed scattering center. Frequently we define the Center of Mass frame as the frame where the sum of the momenta of all the interacting particles is 0. Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Relationship of variables in Lab and CM The speed of CM is Speeds of the particles in CM frame are The momenta of the two particles are equal and opposite!! and Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Quantities in Special Relativity lec 5 Quantities in Special Relativity Fractional velocity Lorentz g factor Relative momentum and the total energy of the particle moving at a velocity is Square of four momentum P=(E,pc), rest mass E Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Relativistic Variables The invariant scalar, s, is defined as: So what is this in the CM frame? Thus, represents the total available energy in the CM; At the LHC, eventually Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

lec 7 (worked HW 2 probs) Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Nuclear Properties: Binding Energy lec. 7 Nuclear Properties: Binding Energy The mass deficit is always negative and is proportional to the nuclear binding energy What is the physical meaning of BE? A minimum energy required to release all nucleons from a nucleus Rapidly increase with A till A~60 at which point BE~9 MeV. A>60, the B.E gradually decrease  For most of the large A nucleus, BE~8 MeV. Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Nuclear Properties: Sizes The size of a nucleus can be inferred from the diffraction pattern All this phenomenological investigation resulted in a startlingly simple formula for the radius of the nucleus in terms of the number of nucleons or atomic number, A: Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Nuclear Properties: Magnetic Dipole Moments For electrons, me~mB, where mB is Bohr Magneton For nucleons, magnetic dipole moment is measured in nuclear magneton, defined using proton mass Measured magnetic moments of proton and neutron: Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Nuclear Properties: Stability Lec.8 Nuclear Properties: Stability The number of protons and neutrons inside stable nuclei are A<40: Equal (N=Z) A>40: N~1.7Z Neutrons outnumber protons Most are even-p + even–n See table 2.1 Supports strong pairing N~1.7Z N Z Nnucl Even 156 Odd 48 50 5 N=Z Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

lec 9 Nuclear Potential A square well nuclear potential  provides the basis of quantum theory with discrete energy levels and corresponding bound state just like in atoms Presence of nuclear quantum states have been confirmed through Scattering experiments Studies of the energies emitted in nuclear radiation Studies of mirror nuclei and the scatterings of protons and neutrons demonstrate Aside from the Coulomb effects, the forces between two neutrons, two protons or a proton and a neutron are the same Nuclear force has nothing to do with electrical charge Protons and neutrons behave the same under the nuclear force Inferred as charge independence of nuclear force. Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Nuclear Radiation: Alpha Decay Represents the disintegration of a parent nucleus to a daughter through emission of a He nucleus Reaction equation is How does this compare to binding energy? Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Nuclear Radiation: Alpha Decay Most energetic a-particles produced alone Parent nucleus decays to the ground state of a daughter and produces an a-particle whose KE is lec 10-11 Less energetic ones accompanied by delayed photons Indicates quantum energy levels Parent decays to an excited state of the daughter after emitting an a Daughter then subsequently de-excite by emitting a photon Difference in the two Q values correspond to photon energy Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Nuclear Radiation: a-Decay Example 240Pu94 decay reaction is a particles observed with 5.17MeV and 5.12 MeV Since We obtain the two Q-values Which yields a photon energy of Consistent with experimental measurement, 45KeV Indicates the energy level spacing of order 100KeV for nuclei Compares to order 1eV spacing in atomic levels Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

b–Decay Reaction Equations with Neutrinos Electron emission Positron emission Electron capture lec. 12 Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Particle Numbers Baryon numbers: A quantum number assigned to baryons (protons, neutrons…) Baryons +1 Anti-baryons: -1 Protons and neutrons are baryons with baryon number +1 each Experimentally observed that baryon number is conserved. Hadrons are strongly interacting particles (all baryons are hadrons, but not vice-versa) Baryons consist of three quarks Mesons consist of a quark and an anti-quark weak Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt

Lepton Number Three charged leptons exist in nature with their own associated neutrinos These three types of neutrinos are distinct from each other muon neutrinos never produce leptons other than muons or anti-muons Wednesday, Mar. 21, 2012 PHYS 3446, Andrew Brandt