Segment 5 Molecular Biology Part 1b

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Presentation transcript:

Segment 5 Molecular Biology Part 1b Chapters 12-14

b. DNA and RNA molecules have structural similarities and differences that define function. 1. Both have three components – sugar, phosphate and a nitrogenous base – which form nucleotide units that are connected by covalent bonds to form a linear molecule with 3’ and 5’ ends, with the nitrogenous bases perpendicular to the sugar-phosphate backbone.

b. DNA and RNA molecules have structural similarities and differences that define function. 2. The basic structural differences include: i. DNA contains deoxyribose (RNA contains ribose) ii. RNA contains uracil in lieu of thymine in DNA iii. DNA is usually double stranded, RNA is usually single stranded iv. The two DNA strands in double-stranded DNA are antiparallel in directionality.

b. DNA and RNA molecules have structural similarities and differences that define function. Both DNA and RNA exhibit specific nucleotide base pairing that is conserved through evolution: adenine pairs with thymine or uracil (A-T or A-U) and cytosine pairs with guanine (C-G). i.Purines (G and A) have a double ring structure. ii.Pyrimidines (C, T, and U) have a single structure.

b. DNA and RNA molecules have structural similarities and differences that define function. 4.The sequence of the RNA bases, together with the structure of the RNA molecule, determines RNA function. i. mRNA carries information from the DNA to the ribosome. ii. tRNA molecules bind specific amino acids and allow information in the mRNA to be translated to a linear peptide sequence. iii. rRNA molecules are functional building blocks of ribosomes. iv. The role of RNAi includes regulation of gene expression at the level of mRNA transcription.

c. Genetic information flows from a sequence of nucleotides in a gene to a sequence of amino acids in a protein. 1. The enzyme RNA-polymerase reads the DNA molecule in the 3’ to 5’ direction and synthesizes complementary mRNA molecules that determine the order of amino acids in the polypeptide.

c.Genetic information flows from a sequence of nucleotides in a gene to a sequence of amino acids in a protein. 2. In eukaryotic cells the mRNA transcript undergoes a series of enzyme-regulated modifications. Illustrative example: •Addition of poly-A tail •Addition of a GTP gap •Excision of introns

c. Genetic information flows from a sequence of nucleotides in a gene to a sequence of amino acids in a protein. 3. Translation of the mRNA occurs in the cytoplasm on the ribosome.

c. Genetic information flows from a sequence of nucleotides in a gene c. Genetic information flows from a sequence of nucleotides in a gene to a sequence of amino acids in a protein. 4. In prokaryotic organisms, transcription is coupled to translation of the message. Translation involves energy and many steps, including initiation, elongation, and termination. The salient features include: i. The mRNA interacts with the rRNA of the ribosome to initiate translation at the (start) codon. ii. The sequence of nucleotides on the mRNA is read in triples called codons. iii. Each codon encodes a specific amino acid, which can be deduced by using a genetic code chart. Many amino acids have more than one codon. iv. tRNA brings the correct amino acid to the correct place on the mRNA. v. The amino acid is transferred to the growing peptide chain. vi. The process continues along the mRNA until a “stop” codon is reached. vii. The process terminates by release of the newly synthesized peptide/protein.