Objective Standard 15.0 I will solve a rational equation by multiplying the LCM of the denominators to both sides

Review 1 Solving Linear Equation Solve for x for the following equation. 2𝑥+10=3𝑥+4

Review 2 Solving Quadratic Equation Solve for x for the following equation. 2𝑥 𝑥−6 +3 𝑥+3 =27

Review 3 Solving Equation with x in Denominator Solve for x in the following equation. 3 2 = 1 𝑥 + 7 6

Solving a Rational Equation Example 1 Solve the equation: 3 𝑥−2 = 1 𝑥−1 + 7 𝑥−1 (𝑥−2) Step 1: State the excluded values for x. Step 2: Find the LCM of all the denominators. Step 3: Multiply both sides by the LCM. Step 4: Simplify the denominators. Step 5: Solve for 𝑥. Reject some of the answers.

Solving a Rational Equation Example 2 Solve the equation: 3 𝑥 + 2 𝑥+1 = 23 𝑥 2 +𝑥 Step 1: Factorize the denominator Step 2: State the excluded values for x. Step 3: Find the LCM of all the denominators. Step 4: Multiply both sides by the LCM. Step 5: Simplify the denominators. Step 6: Solve for 𝑥.

Solving a Rational Equation Example 3 Solve the equation: 4 𝑥−2 − 2 𝑥 = 14 𝑥 2 −2𝑥 Step 1: Factorize the denominator Step 2: State the excluded values for x. Step 3: Find the LCM of all the denominators. Step 4: Multiply both sides by the LCM. Step 5: Simplify the denominators. Step 6: Solve for 𝑥.

Solving a Rational Equation Example 4 Solve the equation: 4 𝑥 2 −6𝑥+8 = 3𝑥 𝑥−2 + 2 𝑥−4 Step 1: Factorize the denominator Step 2: State the excluded values for x. Step 3: Find the LCM of all the denominators. Step 4: Multiply both sides by the LCM. Step 5: Simplify the denominators. Step 6: Solve for 𝑥.

Solving a Rational Equation Example 4 Solve the equation: 4 𝑥 2 −6𝑥+8 = 3𝑥 𝑥−2 + 2 𝑥−4 4 (𝑥−2)(𝑥−4) = 3𝑥 𝑥−2 + 2 𝑥−4 𝐿𝐶𝑀=(𝑥−2)(𝑥−4) Multiply (𝑥−2)(𝑥−4) to both sides (𝑥−2)(𝑥−4) ∙ 4 𝑥−2 𝑥−4 = 3𝑥 𝑥−2 ∙ 𝑥−2 𝑥−4 + 2 𝑥−4 ∙ 𝑥−2 𝑥−4 4=3𝑥 𝑥−4 +2(𝑥−2) 4=3𝑥 𝑥−4 +2 𝑥−2 4=3 𝑥 2 −12𝑥+2𝑥−4 3 𝑥 2 −10𝑥−8=0 3𝑥+2 𝑥−4 =0 𝑥=− 2 3 𝑜𝑟 𝑥=4 (𝑟𝑒𝑗𝑒𝑐𝑡𝑖𝑒𝑑) 𝑥≠2,4

Solving a Rational Equation Example 5 Solve the equation: 2𝑥 𝑥+3 + 3 𝑥−6 = 27 𝑥 2 −3𝑥−18 Step 1: Factorize the denominator Step 2: State the excluded values for x. Step 3: Find the LCM of all the denominators. Step 4: Multiply both sides by the LCM. Step 5: Simplify the denominators. Step 6: Solve for 𝑥.

Solving a Rational Equation Example 5 Solve the equation: 2𝑥 𝑥+3 + 3 𝑥−6 = 27 𝑥 2 −3𝑥−18 2𝑥 𝑥+3 + 3 𝑥−6 = 27 (𝑥−6)(𝑥+3) 𝐿𝐶𝑀=(𝑥−6)(𝑥+3) Multiply (𝑥−6)(𝑥+3) to both sides (𝑥−6)(𝑥+3)∙ 2𝑥 𝑥+3 + 3 𝑥−6 ∙(𝑥−6)(𝑥+3)= 27 (𝑥−6)(𝑥+3) ∙(𝑥−6)(𝑥+3) 2𝑥 𝑥−6 +3 𝑥+3 =27 2 𝑥 2 −12𝑥+3𝑥+9=27 2 𝑥 2 −9𝑥−18=0 2𝑥+3 𝑥−6 =0 𝑥=− 3 2 𝑜𝑟 𝑥=6 (𝑟𝑒𝑗𝑒𝑐𝑡𝑒𝑑) 𝑥≠−3,6

Solving a Rational Equation Example 6 Solve the equation: − 12 𝑥 2 +6𝑥 = 2 𝑥+6 + 𝑥−2 𝑥 Step 1: Factorize the denominator Step 2: State the excluded values for x. Step 3: Find the LCM of all the denominators. Step 4: Multiply both sides by the LCM. Step 5: Simplify the denominators. Step 6: Solve for 𝑥.

Solving a Rational Equation Example 6 Solve the equation: − 12 𝑥 2 +6𝑥 = 2 𝑥+6 + 𝑥−2 𝑥 − 12 𝑥(𝑥+6) = 2 𝑥+6 + 𝑥−2 𝑥 𝐿𝐶𝑀=𝑥(𝑥+6) Multiply 𝑥(𝑥+6) to both sides 𝑥(𝑥+6)∙− 12 𝑥(𝑥+6) = 2 𝑥+6 ∙𝑥(𝑥+6)+ 𝑥−2 𝑥 ∙𝑥(𝑥+6) −12=2𝑥+ 𝑥−2 𝑥+6 −12=2𝑥+ 𝑥 2 +4𝑥−12 𝑥 2 +6𝑥=0 𝑥 𝑥+6 =0 𝑥=0 𝑟𝑒𝑗𝑒𝑐𝑡𝑒𝑑 𝑜𝑟 𝑥=−6(𝑟𝑒𝑗𝑒𝑐𝑡𝑒𝑑) No solutions 𝑥≠0,−6

Practice from Textbook Textbook A58 Q.45, 46, 77, 78 Once you are done, you can work on A58 Q. 79, 80 and check the answer at AN120 (A.6) middle Work at your own pace: Review on Add/Subtract RE: A40 Example 8, 9 Textbook A44 Q.61-68 Review on Complex Fractions: A41 Example 10, 11 Textbook A45 Q.73-80