2018 Arithmetic.

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STRING AN EXAMPLE OF REFERENCE DATA TYPE. 2 Primitive Data Types  The eight Java primitive data types are:  byte  short  int  long  float  double.

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Section 12-1 Sequence and Series

This is the series In other words it is Consider the bars and how the represent the numbers in the sequence, and how the total sum of all.

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Example #1: Two angles are supplementary. The smaller angle is 3 more than seven times x. The larger angle is 21 less than 11 times x. Find the measures.

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Objective: Learn to describe the relationships and extend the terms in arithmetic sequence.

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Algebra with Whole Numbers Algebraic Notation. Simplify.

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Presentation transcript:

2018 Arithmetic

1 1 6 7 3 3 9 + + 4 0 = 7 1 3 - 1 = 7 1 2 7 1 2 7 1 2

5 11 5 11

1 4 5 2 x Double 4 0 = 8 0 Double 5 = 1 0 9 9 0

8 3 8

9 x 1 1 = 9 9 9

5 x 4 = 2 0 2 0 x 1 0 = 2 0 0 2 0 0

6 7 0 6 4 5 0 2 - 1 - 5 0 0 = 6 5 6 4 - 2 = 6 5 6 2 6 5 6 2 6 5 6 2

6 x 6 = 3 6 3 6 + 1 0 = 4 6 4 6

1 1 5 6.3 8 + 2 5 = 8 1.3 8 + 2 4.7 - 0.3 = 8 1.0 8 8 1 . 8 8 1.0 8

3 0 8 2 9 8 + 1 0 = 3 0 8

. 9 2 7 ÷ 3 = 9 3 2 7 0 9 0 .

. . 6 5 4 ÷ 9 = 6 9 5 4 0 0 6 0 0 . .

1 x = 1 5 2 x = 3 0 3 x = 4 5 4 x = 6 0 4

4 9 2 1 4 5 7 7 6 8 5 5 - 1 4 9 2 1

50 000

9 1 0 1 .0 1 - 5 = 5 - 5.4 - 0.4 = 4.6 4 . 6 4.6

x3 5 1 5 1 5 3 1 8 = + = 7 2 1 2 1 2 1 2 1 x3 1 8 2 1

0.1 . 1 0.0 0 1

1 2 5 2 5 0 4 1 0 0 0 x 3 2 7 5 7 5 0

1 1 2 1 1 2 3 5 5 1 5 7 1 8 5 5 18 055

1 0 0 2 0 1 2 0 0 ÷ 1 0 0 = 1 2 1 2 x 2 0 = 2 4 0 . . 1 2 4 5 5 1 2 0 0 2 2 4 0

1 5 4 3 1 x + 4 3 - 4 3 8 6 2 x 2 1 5 + 4 3 1 1 2 9 3 x + 4 3 1 1 7 2 4 x + 4 3 2 1 5 5 x 1 5

4 2 8 Half of 2 8 = 1 4 x 0.5 1 4 . 1 4

x5 x2 1 5 1 2 = = 2 1 0 5 1 0 x5 x2 5 2 7 7 + = 1 0 1 0 1 0 1 0

3 3 6 2 + = = 1 4 4 4 4 2 1 + 1 4 2 2 4

7 3 1 0 + = 4 4 4 1 0 4

5 9 9 6 .0 0 0 1 1 1 + 0.0 0 2 = 5.7 4 - 5.7 3 8 + 0.0 6 = 5.8 . 2 6 2 + 0.2 = 6 0.2 6 2 0.2 6 2

x10 ÷10 2 3.9 3.9 x 3 = 1 1.7 x 3 0 1 1.7 x 1 0 = 1 1 7 1 1 7 3 9 x 3 = 1 1 7 1 1 7 0 . 1 1 7

x3 2 6 = 5 1 5 x3 1 6 6 1 0 1 0 - = 1 5 1 5 1 5 1 5

3 1 2 2 1 1 3 2 4 7 8 4 3 3 4 4 6 5 5 1 8 465 518

1 1 0 0 9 9 2 0 0 ÷ 1 0 0 = 2 9 9 2 x If 1% is 2 9 9% is 2 0 0 - 2 1 9 8 1 9 8

1 4 x 2 1 8

8 1 - 3 6 ÷ 9 = 8 1 - 4 = 7 7

1 x 4 0 = 4 0 1 2 x 4 0 = 2 4 0 = 2 0 6 0

3 x 4 0 = 1 2 0 1 2 0 ÷ 2 = 6 0 . . . . 2 2 6 0

1 4 1 0 0 2 8 6 5 0 ÷ 1 0 0 = . 6.5 6 . 5 x 2 8 5 2 1 3 1 8 2 . 1 8 2

1 4 1 8 x7 x3 4 - 1 2 1 4 6 1 8 2 1 2 1 = = 3 2 1 7 2 1 x7 x3 3 5 1 8 3 - 1 2 1 2 1 1 7 2 2 1

1 4 1 3 - 3 7 x7 x3 2 1 4 9 8 1 3 3 9 1 4 7 x = = 3 2 1 7 2 1 9 8 x7 x3 9 8 3 9 5 9 5 9 - = 2 1 2 1 2 1 2 1

9 7 1 x 9 1 1 9 4 2 x 2 9 1 3 x - 8 7 3 3 8 8 4 x 9 7 4 8 5 5 x 5 8 2 6 x 6 7 9 7 x 7 7 6 8 x 8 7 3 9 x 9 7 0 1 0 x 9 1