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STOICHIOMETRY Study of the amount of substances consumed and produced in a chemical reaction.
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Presentation transcript:

DO NOW

THE MOLE AND STOICHIOMETRY REVIEW

REVIEW FOR EXAM Know the MOLE as the basic SI unit for measuring the amount of a substance. Know Avogadro’s number (6.02 x 1023) as it is related to a mole of any substance. Calculate the molar mass from the periodic table for any substance. Calculate the mole-mole, mole-mass, mass-mole, mole-particle, and particle- mole problems. Use the mole to convert between mass and number of particles.

REVIEW FOR EXAM 6. Calculate empirical formulas, molecular formulas, and hydrate formulas from appropriate data. 7. Calculate mole-mole, mass-mole, mole- mass, and mass-mass problems. 8. Knowing the limiting reagent in a reaction, calculate the maximum amount of product(s) produced. Identify the limiting reagent in a reaction.

REVIEW FOR EXAM 4. Calculate the mole-mole, mole-mass, mass- mole, mole-particle, and particle-mole problems. How many moles of oxygen atoms are present in 5.00 mol P2O5? 5.00 mol P2O5 5 mol O = 25.0 mol O 1 mol P2O5

REVIEW FOR EXAM 4. Calculate the mole-mole, mole-mass, mass- mole, mole-particle, and particle-mole problems. Calculate the number of molecules in 11.5 moles of H2O. 11.5 mol H2O 6.02 x 1023 molecules H2O 1 mole H2O = 6.923 x 1024 = 6.92 x 1024 molecules H2O Calculate the number of moles in 25.5g Ag. 25.5g Al 1 mol Al = 0.2363956 107.87g Ag = 0.236 mol Ag

REVIEW FOR EXAM 5. Use the mole to convert between mass and number of particles. Calculate the number of atoms in 55.2g Li. 55.2g Li 1 mol Li 6.02 x 1023 atoms Li 6.94g Li 1 mol Li = 4.78824 x 1024 = 4.79 x 1024 atom Li Calculate the mass in grams of 6.02 x 1024 atoms Bi. 6.02 x 1024atoms Bi 1mol Bi 208.98g 6.02 x 1023 atoms Bi 1 mol Bi = 2089.8 = 2090g Bi

REVIEW FOR EXAM 6. Calculate empirical formulas, molecular formulas, and hydrate formulas from appropriate data.

REVIEW FOR EXAM

REVIEW FOR EXAM

REVIEW FOR EXAM

REVIEW FOR EXAM 7. Calculate mole-mole, mass-mole, mole- mass, and mass-mass problems. WYK: 0.020mol Cl2 ? moles NaCl EQN: 2Na + Cl2  2NaCl SOLVE: 0.020mol Cl2 2 mole NaCl = 0.040mol NaCl 1 mole Cl2

REVIEW FOR EXAM = 2.3376 = 2.3g NaCl 7. Calculate mole-mole, mass-mole, mole- mass, and mass-mass problems. WYK: 0.020mol Cl2 ? grams NaCl EQN: 2Na + Cl2  2NaCl SOLVE: 0.020mol Cl2 2 mole NaCl 58.44gNaCl 1 mole Cl2 1 mol NaCl = 2.3376 = 2.3g NaCl

REVIEW FOR EXAM 7. Calculate mole-mole, mass-mole, mole- mass, and mass-mass problems. WYK: 45.0g Cl2 ? mol NaCl EQN: 2Na + Cl2  2NaCl SOLVE: 45.0g Cl2 1mol Cl2 2 mole NaCl 70.90g Cl2 1 mole Cl2 = 1.26939 = 1.27mol NaCl

REVIEW FOR EXAM 7. Calculate mole-mole, mass-mole, mole- mass, and mass-mass problems. WYK: 45.0g Cl2 ? grams NaCl EQN: 2Na + Cl2  2NaCl SOLVE: 45.0g Cl2 1mol Cl2 2 mole NaCl 58.44gNaCl 70.90g Cl2 1 mole Cl2 1 mol NaCl = 74.1833568 = 74.2g NaCl

REVIEW FOR EXAM 8. Knowing the limiting reagent in a reaction, calculate the maximum amount of product(s) produced and the amount of any excess reagent. Identify the limiting reagent in a reaction.

WHAT I WILL LOOK FOR Be sure to show all your work. Be sure to use the correct number of significant digits. Be sure to show all units and substances. Remember the more you show me, the more credit I can give.

TO DO Ten problem practice – answers will be available after tomorrow so you can check your work.

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