Reflection and Refraction of Light Physics 102: Lecture 17 Reflection and Refraction of Light 1

Recall from last time…. Reflection: qi = qr Refraction: Flat Mirror: image equidistant behind Spherical Mirrors: Concave or Convex Today q1 q2 n2 n1 Refraction: n1 sin(q1)= n2 sin(q2)

Concave Mirror Principal Rays 1) Parallel to principal axis reflects through f. 2) Through f, reflects parallel to principal axis. 3) Through center. #3 #2 O #1 f c I Image is (in this case): Real (light rays actually cross) Inverted (Arrow points opposite direction) Reduced (smaller than object) Comment that this is “weird” to have a real image. –demo 554, flower mirage **Every other ray from object tip which hits mirror will reflect through image tip

Preflight 17.1 Which ray is NOT correct? p.a. 1) C f 2) 3)

Mirror Equation Works for concave, convex, or flat do O f c do = distance object is from mirror: Positive: object in front of mirror Negative: object behind mirror di di = distance image is from mirror: Positive: real image (in front of mirror) Negative: virtual image (behind mirror) Note: also works for flat mirrors (f is infinite) f = focal length mirror: Positive: concave mirror +R/2 Negative: convex mirror –R/2

Preflight 17.3 The image produced by a concave mirror of a real object is: Always Real Always Virtual Sometimes Real, Sometimes Virtual

ACT: Concave Mirror Where in front of a concave mirror should you place an object so that the image is virtual? Close to mirror Far from mirror Either close or far Not Possible Demo: 1131; large concave mirror

Magnification Equation do O do ho Angle of incidence ho = height of object: Positive: always q di hi Angle of reflection I hi = height of image: Positive: image is upright Negative: image is inverted m = magnification: Positive / Negative: same as for hi < 1: image is reduced > 1: image is enlarged di Flat mirrors: m=+1 25

Solving Equations Preflight 17.2 Example A candle is placed 6 cm in front of a concave mirror with focal length f=2 cm. Determine the image location. Preflight 17.2 Compared to the candle, the image will be: Larger Smaller Same Size p.a. C f

ACT: Magnification A 4 inch arrow pointing down is placed in front of a mirror that creates an image with a magnification of –2. What is the size of the image? 2 inches 4 inches 8 inches 4 inches What direction will the image arrow point? Up 2) Down

3 Cases for Concave Mirrors Object Image Upright Enlarged Virtual Inside F C F Object Image Inverted Enlarged Real Between C&F C F Object Image Inverted Reduced Real Past C

two identical spherical mirrors f image object Demo 296: penny mirage Demo: two identical spherical mirrors each mirror is positioned at the focal point of the other

Convex Mirror Rays 1) Parallel to principal axis reflects through f. 2) Through f, reflects parallel to principal axis. 3) Through center. #1 O #2 #3 I f c Make this mirror almost flat so that it is like your review mirror Image is: Virtual (light rays don’t really cross) Upright (same direction as object) Reduced (smaller than object) (always true for convex mirrors!):

Solving Equations Example A candle is placed 6 cm in front of a convex mirror with focal length f=-3 cm. Determine the image location. Determine the magnification of the candle. If the candle is 9 cm tall, how tall does the image candle appear to be?

Preflight 17.4 The image produced by a convex mirror of a real object is always real always virtual sometimes real and sometimes virtual

Mirror Summary Angle of incidence = Angle of Reflection Principal Rays Parallel to P.A.: Reflects through focus Through focus: Reflects parallel to P.A. Through center: Reflects back on self |f| = R/2

Index of Refraction 186,000 miles/second: it’s not just a good idea, it’s the law! Speed of light in vacuum Speed of light in medium Index of refraction so always!

Snell’s Law Preflight 17.6 n1 sin(q1)= n2 sin(q2) When light travels from one medium to another the speed changes v=c/n, but the frequency is constant. So the light bends: n1 sin(q1)= n2 sin(q2) Preflight 17.6 n1 q1 Start next lecture here. Demo 281: Snells Law 1) n1 > n2 2) n1 = n2 3) n1 < n2 q2 n2 Compare n1 to n2.

Snell’s Law Practice Example Usually, there is both reflection and refraction! A ray of light traveling through the air (n=1) is incident on water (n=1.33). Part of the beam is reflected at an angle qr = 60. The other part of the beam is refracted. What is q2? 1 r n1 q2 = n2 normal

Apparent Depth d d Apparent depth: n2 n1 apparent fish actual fish