Probability – Mutually Exclusive & Exhaustive – Bingo Method

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Presentation transcript:

Probability – Mutually Exclusive & Exhaustive – Bingo Method Students should choose nine answers from the grid and place them randomly into a 3x3 square in their book. You may want to pause your display and choose questions according to difficulty during the game. Depending on time, students could win with a line, an X, or a ‘full house’ (all).

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Mutually Exclusive & Exhaustive Outcomes BINGO! 45 54 23 82 37 12 76 25 91 Mutually Exclusive & Exhaustive Outcomes

Choose your numbers… 9 13 2 7 5 9 7 10 11 13 6 13 8 11 1 5 8 15 5 12 7 9 5 13 9 14 9 11 5 17 4 11 Draw a 3x3 grid in your book.

Joe picks a button at random. What is P(red or black)? P(red or black) = P(red) + P(black) = 3 10 + 4 10 = 7 10

Joe picks a button at random. What is P(not red or black)? P(not red or black) = 1 − P(red or black) P(red or black) = P(red) + P(black) = 3 7 + 2 7 = 5 7 P(not red or black) = 1 − 5 7 = 2 7

In a bag there are red, blue and black buttons. Joe picks a button at random. What is P(red or black)? P(red or black) = P(red) + P(black) P(red) = 2 9 = 2 9 + 5 9 P(blue) = 2 9 = 7 9 P(black) = 5 9

Joe picks a button at random. What is P(yellow or black)? P(yellow or black) = P(yellow) + P(black) = 3 12 + 2 12 = 5 12

In a bag there are yellow, green and blue buttons. Joe picks a button at random. What is P(green or blue)? P(green or blue) = P(green) + P(blue) P(yellow) = 1 11 = 7 11 + 2 11 P(green) = 7 11 = 9 11 P(blue) = 2 11

Joe picks a button at random. What is P(not green or blue)? P(not green or blue) = 1 − P(green or blue) P(green or blue) = P(green) + P(blue) = 3 11 + 4 11 = 7 11 P(not green or blue) = 1 − 7 11 = 4 11

In a bag there are black, green and red buttons. Joe picks a button at random. What is P(green or red)? P(green or red) = P(green) + P(red) P(yellow) = 3 11 = 5 11 + 3 11 P(green) = 5 11 = 8 11 P(red) = ?

Joe picks a button at random. What is P(blue or yellow)? P(blue or yellow) = P(blue) + P(yellow) = 6 14 + 3 14 = 9 14

In a bag there are black, white and blue buttons. Joe picks a button at random. What is P(not white or blue)? P(not white or blue) = 1 − P(white or blue) P(white or blue) = P(white) + P(blue) P(black) = 5 13 = 5 13 + 3 13 P(white) = 5 13 = 8 13 P(not white or red) = 1 − 8 13 = 5 13 P(blue) = ?

In a bag there are red, blue and green buttons. Joe picks a button at random. What is P(not red or blue)? P(not red or blue) = 1 − P(red or blue) P(red or blue) = P(red) + P(blue) P(red) = 1 5 = 1 5 + 3 5 P(blue) = 3 5 = 4 5 P(green) = 1 5 P(not red or blue) = 1 − 4 5 = 1 5

Joe picks a button at random. What is P(pink or green)? P(pink or green) = P(pink) + P(green) = 4 13 + 5 13 = 9 13

Joe picks a button at random. What is P(not yellow or red)? P(not yellow or red) = 1 − P(yellow or red) P(yellow or red) = P(yellow) + P(red) = 1 13 + 6 13 = 7 13 P(not yellow or red) = 1 − 7 13 = 6 13

In a bag there are pink, blue and yellow buttons. Joe picks a button at random. What is P(pink or yellow)? P(pink or yellow) = P(pink) + P(yellow) P(pink) = 5 13 = 5 13 + 6 13 P(blue) = 2 13 = 11 13 P(yellow) = ?

Joe picks a button at random. What is P(not blue or green)? P(not blue or green) = 1 − P(blue or green) P(blue or green) = P(blue) + P(green) = 3 15 + 4 15 = 7 15 P(not blue or green) = 1 − 7 15 = 8 15

In a bag there are green, yellow and red buttons. Joe picks a button at random. What is P(not green or red)? P(not green or red) = 1 − P(green or red) P(green or red) = P(green) + P(red) P(green) = 2 9 = 2 9 + 2 9 P(yellow) = 5 9 = 4 9 P(red) = 2 9 P(not green or red) = 1 − 4 9 = 5 9

In a bag there are green, pink and white buttons. Joe picks a button at random. What is P(not green or white)? P(not green or white) = 1 − P(green or white) P(green or white) = P(green) + P(white) P(green) = 7 17 = 7 17 + 5 17 P(pink) = 5 17 = 12 17 P(white) = ? P(not green or white) = 1 − 12 17 = 5 17

tom@goteachmaths.co.uk Questions? Comments? Suggestions? …or have you found a mistake!? Any feedback would be appreciated . Please feel free to email: tom@goteachmaths.co.uk