Find the Area.

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Presentation transcript:

Find the Area

EOC Practice Question of the Day

Chord Properties and Segments Lengths in Circles

If two chords are congruent, then their corresponding arcs are congruent.

Solve for x. 8x – 7 3x + 3 8x – 7 = 3x + 3 x = 2

Find the length of WX.

Find 360 – 100 260 divided by 2 130º

If two chords are congruent, then they are equidistant from the center.

In K, K is the midpoint of RE In K, K is the midpoint of RE. If TY = -3x + 56 and US = 4x, find the length of TY. U T K E x = 8 R S Y TY = 32

If a diameter is perpendicular to a chord, then it also bisects the chord. This results in congruent arcs too. Sometimes, this creates a right triangle & you’ll use Pythagorean Theorem.

IN Q, KL  LZ. If CK = 2x + 3 and CZ = 4x, find x.

MT = 6 AT = 12 In P, if PM  AT, PT = 10, and PM = 8, find AT. P A M

30 Find the length of CE x BD is a radius. CB is a radius. What is the length of the radius? 25 Now double it to find CE. 30 25 x

Find the length of LN. LN = 96 MK and KL are radii. Now double it to find LN. x 50 LN = 96

Segment Lengths in Circles

Go down the chord and multiply Two chords intersect INSIDE the circle Type 1: part part part part Emphasize that the chords are NOT congruent or bisected! Go down the chord and multiply

Solve for x. 9 6 x 2 x = 3

Find the length of DB. 8 12 2x 3x A D x = 4 C DB = 20 B

Find the length of AC and DB. x – 4 x 5 C 10 x = 8 AC = 13 DB = 14 B

Sometimes you have to add to get the whole. Two secants intersect OUTSIDE the circle Type 2: Sometimes you have to add to get the whole.

Solve for x. 20 x = 31 7 4 x 7 (20) = (4 + x) 4 140 = 16 + 4x 124 = 4x

x = 11.8 Solve for x. x 5 8 6 6 (6 + 8) = 5 (5 + x) 84 = 25 + 5x

x = 6 Solve for x. 10 x 4 8 x (x + 10) = 8 (8 + 4) x2 +10x = 96

Type 2 (with a twist): Secant and Tangent

x = 36 Solve for x. 242 = 12 (12 + x) 576 = 144 + 12x 432 = 12x x 12

Solve for x. 5 15 x x = 10 x2 = 5 (5 + 15) x2 = 100