EVERYTHING YOU NEED TO KNOW TO GET A GRADE C

Slides:



Advertisements
Similar presentations
Index Laws Miss Hudson’s Maths.
Advertisements

Intro To Algebra By: Carolyn Barone.
Patterns and Sequences
Consecutive Numbers Algebra I.
WHEN MULTIPLYING LIKE BASES, YOU ADD THE EXPONENTS FOR EXAMPLE: NOW YOU TRY:
ALGEBRA 1 Operations with Integers
Solving Equations with Brackets or Fractions. Single Bracket Solve 3(x + 4) = 24 3x + 12 = 24 3x + 12 – 12 = x = 12 x = 4 Multiply brackets out.
Objective How to solve Integer problems
The Basic of Algebra BY Nathaniel Jefferson. The Number Line  |  0 Always start at zero.
EVERYTHING YOU NEED TO KNOW TO GET A GRADE C ALGEBRA (FOUNDATION)
Exponents Tutorial 3f a number, letter, or algebraic expression written above and to the right of another number, letter, or expression called the base.
The length of a rectangle is 6 in. more than its width. The perimeter of the rectangle is 24 in. What is the length of the rectangle? What we know: Length.
Decimals Day 2 Multiply and Divide Decimals. DO NOT line up decimals Multiply with first number, then continue with next number Place decimal point in.
* Collect the like terms 1. 2a = 2a x -2x + 9 = 6x z – – 5z = 2z - 6.
Solving 2 step equations. Two step equations have addition or subtraction and multiply or divide 3x + 1 = 10 3x + 1 = 10 4y + 2 = 10 4y + 2 = 10 2b +
BALANCING EQUATIONS We can think of an equation like a set of scales with two sides that balance. That means that you can change one side if you do the.
Integer Operations Students will solve problems using addition, subtraction, multiplication, and division of positive and negative integers.
Algebra.
Solving Absolute-Value Equations
Solving Multi-Step Equations
Lesson 13 ONE STEP EQUATIONS A.4e.
Operations with Integers
Solving Two step equations
numerical coefficient
Notes 7.1 Day 1– Solving Two-Step Equations
Consecutive Numbers Algebra I.
Negative and Zero Exponents
Algebraic Inequalities
Patterns & Sequences Algebra I, 9/13/17.
Solving 1-Step Integer Equations
How to work with Fractions
The Equal Sign and Integers
Objectives: • Students will learn the steps necessary for solving two-step equations.
Writing Expressions and Equations
Solving Two- Step Equations
Solving Inequalities.
In this lesson you will learn how to read and write algebraic expressions by using variables.
Calculate! 3 X ÷ 2 8 ? 19 ?.
Place Value, Names for Numbers, and Reading Tables
Multiplying and Dividing Integers
2-4 Solving Multi-Step Equations
Solving Inequalities Equations
Solving Two- Step Equations
Unit 1 Day 2: Combining Like Terms Using Integers
Patterning & Algebra Grade
Sequences.
Algebra II September 2, 2011.
Learn to solve equations with integers.
Sequences.
Section 2.2 Zero and Negative Exponents
Simultaneous Equations starter
Solving 1-Step Integer Equations
Solving Two- Step Equations
Alternating signs means we have (-1)n-1 power.
A D S U B T R C I N G.
Simultaneous Equations
Solving Absolute-Value Equations
Adding and Subtracting Integers
Learning Objective Students will be able to: Solve equations in one variable that contain absolute-value expressions.
IF YOU MULTIPLY or DIVIDE BY A NEGATIVE YOU MUST SWITCH THE SIGN!
5.4 Subtracting Polynomials
EXPONENT RULES.
4-2 Warm Up Problem of the Day Lesson Presentation
Review of Integers and Solving Equations
Learn to solve equations with integers.
Algebra 1 Section 4.3.
Math-7 NOTES Solving Equations: Addition Equations: x + 8 = 2
Integers Blast Off
Warm-up!! 8/20/2019 Day 6.
Maths Unit 7 (F) – Equations & Sequences
Presentation transcript:

EVERYTHING YOU NEED TO KNOW TO GET A GRADE C ALGEBRA (FOUNDATION) AUTHOR

BODMAS says you multiply before you add a + 2 x b + 3 x c 7 + 2 x 3 + 3 x 5 BODMAS says you multiply before you add 7 + 6 + 15 28 a x b x c Replace the letters with their respective numbers 7 x 3 x 5 105 105 x d = 0 Anything multiplied by zero is zero. So, d must equal zero.

256 2 20 C = 16 + 24 x 10 BODMAS says you multiply before you add 24 months 12 months in a year 2 C = d + 24 x m 600 = 120 + 24m Solve the equation to work out m 480 = 24m 20 20 = m

    5 x 4 20 2 x 4 + 3y = 5 8 + 3y = 5 3y = -3 -1   13 3 x 4 - -1 12 + 1

6 16 Replace p with 4 and q with -7 5 x 4 + 2 x -7 20 - 14     Replace p with 4 and q with -7 5 x 4 + 2 x -7 20 - 14 6 Replace u with 5 and v with 3   5 x 5 – 3 x 3 25 – 9 16

5 £5 + 100 x 5p £5 + 500p £5 + £5 10 £7.50 - £5 = £2.50 Cost for calls after £5 a month charge has been taken off   Cost for calls after £5 a month charge has been taken off Minutes of calls = Cost per minute for calls 50

Perimeter is the length around a shape     + 6y       56 + 6y = 68 Solve the equation to work out the value of y 6y = 12 2 y = 2

+ 7y 6 16 Replace p with 4 and q with -7 5 x 4 + 2 x -7 20 - 14   + 7y Replace p with 4 and q with -7 5 x 4 + 2 x -7 20 - 14 6 Replace u with 5 and v with 3   5 x 5 – 3 x 3 25 – 9 16

7c   - 3y

Remember a minus and a minus is only a plus when you multiply, divide or when the signs are together. When you add or subtract you use a number line. 12a - 3b    

3a 6b + 10   12

  - 4   + 18   + 14    

  + 5

When you multiply powers with the same base you can just add the powers a x a x a x a x a x a     When you divide powers with the same base you can just subtract the powers b x b x b x b x b x b x b x b x b b x b x b     1    

When you multiply powers with the same base you can just add the powers       y x y x y x y x y x y x y x y y x y x y x y x y   When you divide powers with the same base you can just subtract the powers      

When you have powers and brackets you can just multiply the powers When you multiply powers with the same base you can just add the powers y x y x y x y x y x y x y x y x y     y x y x y x y x y x y x y y x y When you divide powers with the same base you can just subtract the powers     When you have powers and brackets you can just multiply the powers       A negative number to the power of an even number makes a positive Part (iii) As you multiply a decimal by itself more times the number becomes smaller Part (ii)

+ 1 + 1 + 1 4 7 9 + 2 + 2 + 2

Add 3 to the previous term +3 +3 +3 +3 16 Add 3 to the previous term

5 x 3 - 1 14 x 3 - 1 14 41 5 x 1 5 x 2 5 x 3 5 x 4 10 15 20 1st term 2nd term 3rd term 4th term + 4 +3 +3 +3 +3 3n + 4

64 13 26 +3 +4 +5 +6 +7 16 x 4 10 dots 7 dots 1 dot 4 dots Sequence Pattern 4 Sequence 1, 4, 7, 10 Sequence goes up in threes 13 +3 +4 +5 +6 +7 26

Multiply the previous term by 2 8 x2 x2 x2 Multiply the previous term by 2 1 , 2 , 4 , 7 +1 +2 +3 Add consecutive integers

+17 +17 47 +15 +15 47 32     = 15 17 47 15