Substitution – With a Calculator – Bingo Method

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Presentation transcript:

Substitution – With a Calculator – Bingo Method Students should choose nine answers from the grid and place them randomly into a 3x3 square in their book. You may want to pause your display and choose questions according to difficulty during the game. Depending on time, students could win with a line, an X, or a ‘full house’ (all).

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BINGO! 45 54 23 82 37 12 76 25 91 Substitution with a Calculator

Choose your numbers… −7.7 19.8 9.7 22.4 12.6 −6.6 11.5 48.5 −8.2 13.2 0.4 −2.8 −12.1 0.1 10.8 −7.4 Draw a 3x3 grid in your book.

Substitute the values for the variables to find the answer. 𝑇=0.4 𝑔=0 𝑚=−2.2 𝑝=3 𝑇2−𝑝= −2.84 0.42−3= =−2.8 Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝑎=3.2 𝑏=−1.4 𝑐=−0.6 𝑑=3 𝑎2+𝑑= 13.24 3.22+3= =13.2 Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝐺=0.8 𝑖=−1.4 𝐻=2.6 𝑡=−2 5𝑡−3𝐺3= −11.536 5×−2 −3×0.83= =−11.5 Give your answer to 1 dp.

2𝑚2+3𝑔= 9.68 =9.7 𝑇=0.4 𝑔=0 𝑚=−2.2 𝑝=3 2×(−2.2)2+3×0= Substitute the values for the variables to find the answer. 𝑇=0.4 𝑔=0 𝑚=−2.2 𝑝=3 2𝑚2+3𝑔= 9.68 2×(−2.2)2+3×0= Do we need to include the negative in this calculation? =9.7 Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝑤=−2 𝑥=4.5 𝑦=−2.7 𝑧=0.4 3𝑦−𝑤2= −12.1 3×−2.7 − −2 2= Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝑎=3.2 𝑏=−1.4 𝑐=−0.6 𝑑=3 2𝑎2+𝑏2= 22.44 2×3.22+(−1.4)2= =22.4 Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝑤=−2 𝑥=4.5 𝑦=−2.7 𝑧=0.4 2𝑧2+𝑤3= −7.68 2×0.42+ −2 3= =−7.7 Give your answer to 1 dp.

𝑎2+𝑏2+𝑐2= 12.56 =12.6 𝑎=3.2 𝑏=−1.4 𝑐=−0.6 𝑑=3 3.22+ −1.4 2+ −0.6 2= Substitute the values for the variables to find the answer. 𝑎=3.2 𝑏=−1.4 𝑐=−0.6 𝑑=3 𝑎2+𝑏2+𝑐2= 12.56 3.22+ −1.4 2+ −0.6 2= Do we need to include negatives in these calculations? =12.6 Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝑤=−2 𝑥=4.5 𝑦=−2.7 𝑧=0.4 0.5𝑥𝑧2= 0.36 0.5×4.5×0.42= =0.4 Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝑎=3.2 𝑏=−1.4 𝑐=−0.6 𝑑=3 3𝑐𝑑−𝑏2= −7.36 3×−0.6×3 − −1.4 2= =−7.4 Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝑇=0.4 𝑔=0 𝑚=−2.2 𝑝=3 𝑔𝑇+3𝑚𝑝= 19.8 0×0.4+3×−2.2×3= Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝐺=0.8 𝑖=−1.4 𝐻=2.6 𝑡=−2 3𝐻−𝑖2+5= 10.84 3×2.6− −1.4 2+5= =10.8 Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝐺=0.8 𝑖=−1.4 𝐻=2.6 𝑡=−2 2𝐻𝑖+𝐺2= −6.64 2×2.6×−1.4+0.82= =−6.6 Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝑇=0.4 𝑔=0 𝑚=−2.2 𝑝=3 𝑝𝑇2 8 = 3×(−0.4)2 8 = 0.06 =0.1 Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝑤=−2 𝑥=4.5 𝑦=−2.7 𝑧=0.4 2𝑥2−𝑤3= 48.5 2×4.52− −2 3= Give your answer to 1 dp.

Substitute the values for the variables to find the answer. 𝐺=0.8 𝑖=−1.4 𝐻=2.6 𝑡=−2 𝑡2+3𝑖3−5𝐺= −8.232 −2 2+3× −1.4 3−5×0.8= =−8.2 Give your answer to 1 dp.

tom@goteachmaths.co.uk Questions? Comments? Suggestions? …or have you found a mistake!? Any feedback would be appreciated . Please feel free to email: tom@goteachmaths.co.uk