Moments of Random Variables

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Presentation transcript:

Moments of Random Variables The moment generating function

Examples The Binomial distribution (parameters p, n) The Poisson distribution (parameter l)

The Exponential distribution (parameter l) The Standard Normal distribution (m = 0, s = 1)

The Gamma distribution (parameters a, l) The Chi-square distribution (degrees of freedom n) (a = n/2, l = 1/2)

Properties of Moment Generating Functions mX(0) = 1

The log of Moment Generating Functions Let lX (t) = ln mX(t) = the log of the moment generating function

Thus lX (t) = ln mX(t) is very useful for calculating the mean and variance of a random variable

Examples The Binomial distribution (parameters p, n)

The Poisson distribution (parameter l)

The Exponential distribution (parameter l)

The Standard Normal distribution (m = 0, s = 1)

The Gamma distribution (parameters a, l)

The Chi-square distribution (degrees of freedom n)

Jointly distributed Random variables Multivariate distributions

Discrete Random Variables

The joint probability function; p(x,y) = P[X = x, Y = y]

Marginal distributions Conditional distributions

Continuous Random Variables

Definition: Two random variable are said to have joint probability density function f(x,y) if

Marginal distributions Conditional distributions

Independence

Definition: Two random variables X and Y are defined to be independent if if X and Y are discrete if X and Y are continuous Thus in the case of independence marginal distributions ≡ conditional distributions

The Multiplicative Rule for densities if X and Y are discrete if X and Y are continuous

Proof: This follows from the definition for conditional densities: Hence and The same is true for continuous random variables.

Example: Suppose that a rectangle is constructed by first choosing its length, X and then choosing its width Y. Its length X is selected form an exponential distribution with mean m = 1/l = 5. Once the length has been chosen its width, Y, is selected from a uniform distribution form 0 to half its length. Find the probability that its area A = XY is less than 4.

Solution:

xy = 4 y = x/2

This part can be evaluated This part may require Numerical evaluation