Equations – Perpendicular Lines – Shootout! Students compete (1v1 in pairs or in teams, at their tables or at the front) to answer questions the quickest. Students could write on your whiteboard or their own. Delete too difficult/easy question slides beforehand (and its individual intro slide). Click anywhere to start the music, then click ‘Go’ to show the question, then click again to show the answer. This game has sound!

Finding the Equation of Perpendicular Lines Shootout! Finding the Equation of Perpendicular Lines

Correct Answer = 1pt Fastest! = 1pt

Ready? Go!

(0,3)? 𝑦=2𝑥 𝑦=− 1 2 𝑥+3 What is the equation of the line that is perpendicular to 𝑦=2𝑥 and passes through (0,3)? 𝑦=− 1 2 𝑥+3

Ready? Go!

What is the equation of the red line? 𝑦 𝑦=𝑥 𝑥 𝑦=−𝑥

Ready? Go!

(0,1)? 𝑦= 1 2 𝑥 𝑦=1−2𝑥 What is the equation of the line that is perpendicular to 𝑦= 1 2 𝑥 and passes through (0,1)? 𝑦=1−2𝑥

Ready? Go!

(3,10)? 𝑦=− 1 2 𝑥+3 𝑦=2𝑥+4 What is the equation of the line that is perpendicular to 𝑦=− 1 2 𝑥+3 and passes through (3,10)? 𝑦=2𝑥+4

Ready? Go!

What is the equation of the red line? 𝑦 𝑦=𝑥 5 𝑥 𝑦=5−𝑥

Ready? Go!

What is the equation of the red line? 𝑦 𝑦=− 1 2 𝑥 5 𝑥 𝑦=2𝑥+5

Ready? Go!

(0,3)? 𝑦=3𝑥+1 𝑦=− 1 3 𝑥+3 What is the equation of the line that is perpendicular to 𝑦=3𝑥+1 and passes through (0,3)? 𝑦=− 1 3 𝑥+3

Ready? Go!

What is the equation of the red line? 𝑦 𝑦=2𝑥−5 2 𝑥 𝑦=2− 1 2 𝑥

Ready? Go!

(6,4)? 𝑦=4−3𝑥 𝑦= 1 3 𝑥+2 What is the equation of the line that is perpendicular to 𝑦=4−3𝑥 and passes through (6,4)? 𝑦= 1 3 𝑥+2

Ready? Go!

What is the equation of the red line? 𝑦 𝑦=𝑥−4 2 𝑥 𝑦=2−𝑥

Ready? Go!

What is the equation of the red line? 𝑦 𝑦=− 1 2 𝑥 𝑥 −3 𝑦=2𝑥−3

Ready? Go!

(4,−4)? 𝑦= 1 2 𝑥+4 𝑦=4−2𝑥 What is the equation of the line that is perpendicular to 𝑦= 1 2 𝑥+4 and passes through (4,−4)? 𝑦=4−2𝑥

Ready? Go!

What is the equation of the red line? 𝑦 𝑦=3𝑥−5 𝑥 (15, −1) 𝑦=4− 1 3 𝑥

Ready? Go!

What is the equation of the red line? 𝑦 𝑦=2𝑥−5 (−4,6) 𝑥 𝑦=4− 1 2 𝑥

tom@goteachmaths.co.uk Questions? Comments? Suggestions? …or have you found a mistake!? Any feedback would be appreciated . Please feel free to email: tom@goteachmaths.co.uk