Chapter 15 Advanced Problem Solving by Christopher G. Hamaker

Slides:



Advertisements
Similar presentations
CH 10: Chemical Equations & Calcs
Advertisements

Christopher G. Hamaker, Illinois State University, Normal IL © 2008, Prentice Hall Chapter 10 Chemical Equation Calculations INTRODUCTORY CHEMISTRY INTRODUCTORY.
Basic Chemistry Chapter 11 Gases Chapter 11 Lecture
General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc.1 Chapter 7 Gases 7.7 Volume and Moles (Avogadro’s Law)
Thursday, Sept. 26 th : “A” Day Friday, Sept. 27 th : “B” Day Agenda  Homework Questions/Problems  Quick Review (Practice #2c; Practice #1: c, d)
Chapter 10 Chemical Equation Calculations by Christopher Hamaker
Chapter 12 Stoichiometry 12.2 Chemical Calculations
Chapter 12 Review “Stoichiometry”
Chemical Equations and Reaction Stoichiometry
Chemical Calculations Stoichiometry OBJECTIVES: – Calculate stoichiometric quantities from balanced chemical equations using units of moles and mass.
2Mg (s) + O 2 → 2MgO INTERPRETING A CHEMICAL EQUATION Quantitative Interpretation of Chemical Reactions Stoichiometry is one of the most important topic.
Chapter 14-3 I. Avogadro’s Principle A. Equal volumes of gases at same T and P contain equal #’s of molecules B. H 2 + Cl 2 → 2HCl 1 vol. 1 vol. 2 vol.
Chemical Calculations Stoichiometry u OBJECTIVES: Calculate stoichiometric quantities from balanced chemical equations using units of moles, mass, representative.
Basic Chemistry Copyright © 2011 Pearson Education, Inc. 1 Chapter 11 Gases 11.9 Gas Laws and Chemical Reactions Under water, the pressure on a diver is.
Unit: Stoichiometry Incorporating representative particles and volume into stoichiometry calculations Day 3 - Notes.
Can’t directly measure moles Measure units related to moles: –Mass (molar mass) –Number of particles (6.02 x ) –Liters of gas (22.4 Liters at STP)
Stoichiometry. Review: Dimensional Analysis Goal: To make the units cancel out Strategy: Start out with the quantity given that you are trying to convert.
Stoichiometry Chapter 9 Mass calculations Stoich ppt _2 mass-mass.
12.2 Chemical Calculations > 12.2 Chemical Calculations > 1 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. Chapter 12 Stoichiometry.
Christopher G. Hamaker, Illinois State University, Normal IL © 2008, Prentice Hall Chapter 10 Chemical Equation Calculations INTRODUCTORY CHEMISTRY INTRODUCTORY.
Stoichiometry Chemistry – Chapter 12.
General, Organic, and Biological Chemistry
7.7 Volume and Moles (Avogadro’s Law)
Chapter 12 Review “Stoichiometry”
Stoichiometry Chemistry – Chapter 12.
Chapter 10 Chemical Quantities
Chapter 10 Chemical Quantities
Law of Conservation of Matter
Visualizing a Chemical Reaction
Chapter 12 Stoichiometry.
Equation Calculations
Identify the Representative Particle
Chapter 12 Review “Stoichiometry”
Stoichiometry Quiz Please take a card from the front
Chapter 10 Chemical Quantities
Mole and Stoichiometry Mini-Lab
Calculations from Chemical Equations
Dr. Chirie Sumanasekera
DO NOW: Turn in your homework! Fill in Table of Contents
Chapter 12 Review “Stoichiometry”
Basic Chemistry Chapter 11 Gases Chapter 11 Lecture
12.2 Chemical Calculations
Chapter 12 “Stoichiometry”
Stoichiometric Calculations
Visualizing a Chemical Reaction
Stoichiometry – Mr. Mole.
Stoichiometry.
Stoichiometry Unit 8 Lesson 1.
Chapter 10 Chemical Equation Calculations by Christopher Hamaker
Volume and Moles (Avogadro’s Law)
Stoichiometry Unit 8 Lesson 1.
Chapter 12 Stoichiometry 12.2 Chemical Calculations
5.2 Stoichiometry. 5.2 Stoichiometry Moles 6.022×1023 Particles 1mol = STP 1mol = Molar Mass The mass of 1 mole of a substance in grams (also.
Chapter 12 Stoichiometry 12.2 Chemical Calculations
Warm-Up How many molecules are in 5.78 mol of ammonium nitrate?
Avogadro’s Number: 1 mole = 6.02 x 1023 particles
Chapter 9.1 stoichiometry –
Chapter 10 Chemical Quantities
Christopher G. Hamaker, Illinois State University, Normal IL
Students type their answers here
Chapter 12 Stoichiometry 12.2 Chemical Calculations
10.2 Mole–Mass and Mole–Volume Relationships
Chapter 12 Stoichiometry
10.2 Molar Relationships.
Stoichiometry Follow along in your text Chapter 9 Section 1 Pages 302 – 311 Put on Pg.33 of your notebook!
Stoichiometry Unit 8 Lesson 1.
Stoichiometry Unit 7 Lesson 1.
Stoichiometry.
Chapter 10 Chemical Quantities
Presentation transcript:

Chapter 15 Advanced Problem Solving by Christopher G. Hamaker Illinois State University © 2014 Pearson Education, Inc. 1

Steps for Advanced Problems Advanced problems involve more than one concept. There are three steps to follow for these multi-concept problems: Examine the problem to determine the unknown quantity. Write down the given value related to the unknown quantity. Plan a strategy that relates the given value to the unknown quantity.

Unit Analysis We have seen the unit analysis method previously. For advanced problems, we need to use a more complex approach. Keep the following points in mind when using the unit analysis method for advanced problems: Many problems cannot be solved in a single unit analysis operation. If the unknown quantity is a single unit (e.g., cm, g, mL), the given value should also be a single unit.

Unit Analysis Continued A problem may include given values that are not relevant. A problem may omit information that is necessary to obtain a solution. If the calculation is based upon a chemical reaction, first write a balanced chemical equation for the reaction. Before using your calculator, estimate an approximate answer.

Algebraic Analysis Most problems are best solved using the unit analysis method; however some problems are not suited to that method. Many problems can be solved using algebraic analysis. An example is density problems. mass volume density =

Algebraic Analysis Example What is the mass of 22.5 cm3 of iron metal with a density of 7.874 g/cm3? m 22.5 cm3 7.874 g/cm3 = m = (22.5 cm3) × 7.874 g cm3 = 178 g

Concept Maps A concept map is a diagram relating one or more chemical concepts. It is a flow diagram outlining the steps that need to be taken in order to solve a problem. An example is shown below for the problem “What is the volume in liters of 3.24 g of oxygen gas at standard conditions?”

Visualization Visualization can help to understand concepts by forming mental pictures. Although we cannot see atoms and molecules, we can visualize what a sample of a gas may look like as we change the conditions of the sample.

“Ballpark” Answers Before using the calculator it is useful to estimate the answer. This estimate is called a ballpark answer because it should be near the actual answer. If the answer obtained for the calculator is significantly different than the estimated answer it can indicate an error in the calculation.

Concept Map – Mole Relationships The concept map for mole relationships from Chapter 8 is shown below.

Mole Relationship Example Calculate the volume and number of atoms of 2.50 g of neon gas at STP. = 0.124 mol Ne × 2.50 g Ne 1 mol Ne 20.18 g Ne = 2.78 L Ne × 22.4 L Ne mol Ne 0.124 mol Ne × 6.02 x 1023 atoms Ne mol Ne 0.124 mol Ne = 7.47 × 1022 atoms Ne

Concept Map – Stoichiometry

Stoichiometry Example How many atoms of iron metal are produced from the reaction of 125 grams of aluminum metal with excess Fe2O3 in the thermite reaction? Fe2O3 (s) + 2 Al (s) → 2 Fe (l) + Al2O3 (s) The conversion goes: g Al → mol Al → mol Fe → atoms Fe

Stoichiometry Example Continued × 125 g Al 1 mol Al 26.98 g Al 2 mol Fe 2 mol Al = 4.63 mol Fe × 4.63 mol Fe 6.02 x 1023 atoms Fe mol Fe = 2.79 × 1024 atoms Fe

Multiple-Reaction Stoichiometry Often you may need to consider the stoichiometry of more than one chemical reaction. Using the same concept map, apply it to each of the reactions in the sequence stepwise until you arrive at your final answer.

Multiple-Reaction Stoichiometry Example What volume of sulfur trioxide gas is produced at STP from the reaction of 45.5 g of sulfur with excess oxygen according to the following equations? S (s) + O2 (g) → SO2 (g) 2 SO2 (g) + O2 (g) → 2 SO3 (g) The conversion goes: g S → mol SO2 → mol SO3 → mol SO3 → volume SO3

Multiple-Reaction Stoichiometry Problem × 45.5 g S 1 mol S 32.07 g S 1 mol SO2 = 1.42 mol SO2 Reaction 2 1.42 mol SO2 × 2 mol SO3 2 mol SO2 = 1.42 mol SO3

Multiple-Reaction Stoichiometry Problem Use PV = nRT to get volume of SO3. At STP, T = 273 K and P = 1.00 atm V = nRT . P V = (1.42 mol) (0.0821 atmL/molK)(273K) (1.00 atm) V = 31.8 L

Critical Thinking: Nanotechnology Nanotechnology is the use of materials on the nanometer (10–9 m) scale. Typically devices are in the 1–100 nm scale. A human hair is approximately 100,000 nm thick! DNA molecules are nanoscale substances, with a diameter of about 1 nm. Nanoparticles of TiO2 are used in sunscreens and of silver are used as antibacterial agents.

Chapter Summary Follow the three steps for advanced problem solving: Examine the problem to determine the unknown quantity. Write down the given value related to the unknown quantity. Plan a strategy that relates the given value to the unknown quantity.

Chapter Summary Continued When solving problems, estimate a ballpark answer to be sure that you have used your calculator correctly. Most often the dimensional analysis method is best, but some simpler problems can be done using algebraic analysis. Visualization is a useful tool for estimating answers.

Chapter Summary Continued The use of concept maps for problems can help you to ensure that you have all the necessary steps for an advanced problem. For stoichiometry involving more than one reaction, apply the stoichiometry concept map to each reaction in sequence until you arrive at your answer. Practice doing problems!