When can we use the Sine Law?

Slides:



Advertisements
Similar presentations
Chapter 6 Additional Topics in Trigonometry Copyright © 2014, 2010, 2007 Pearson Education, Inc The Law of Sines.
Advertisements

Solve SAA or ASA Triangles Solve SSA Triangles Solve Applied Problems
Chapter 6 – Trigonometric Functions: Right Triangle Approach
Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Section 8.2 The Law of Sines.
Starter a 6 c A 49° 96° 1.Use the Law of Sines to calculate side c of the triangle. 2.Now find the Area of a Triangle.
Law of Sines Given the triangle below … … the law of sines is given by …
1 © 2010 Pearson Education, Inc. All rights reserved © 2010 Pearson Education, Inc. All rights reserved Chapter 6 Applications of Trigonometric Functions.
Copyright © 2009 Pearson Education, Inc. CHAPTER 8: Applications of Trigonometry 8.1The Law of Sines 8.2The Law of Cosines 8.3Complex Numbers: Trigonometric.
Laws of Sines. Introduction  In the last module we studied techniques for solving RIGHT triangles.  In this section and the next, you will solve OBLIQUE.
Copyright © 2011 Pearson, Inc. 5.5 Law of Sines. Copyright © 2011 Pearson, Inc. Slide What you’ll learn about Deriving the Law of Sines Solving.
Law of Sines. Triangles Review Can the following side lengths be the side lengths of a triangle?
Chapter 5: Trigonometric Functions Lesson: Ambiguous Case in Solving Triangles Mrs. Parziale.
Triangle Warm-up Can the following side lengths be the side lengths of a triangle?
9.5 Apply the Law of Sines When can the law of sines be used to solve a triangle? How is the SSA case different from the AAS and ASA cases?
Applications of Trigonometric Functions
Law of Sines Lesson Working with Non-right Triangles  We wish to solve triangles which are not right triangles B A C a c b h.
Copyright © 2011 Pearson, Inc. 5.5 Law of Sines Goal: Solve triangles that have no solution, one solution, or two solutions.
5.5 Law of Sines. I. Law of Sines In any triangle with opposite sides a, b, and c: AB C b c a The Law of Sines is used to solve any triangle where you.
Homework Questions. LOGS Warm-up Convert from log form to exponential form Convert from exponential form to log form Expand Condense.
6.1 Law of Sines. Introduction Objective: Solve oblique triangles To solve: you must know the length of one side and the measures of any two other parts.
Trigonometry Section 6.1 Law of Sines. For a triangle, we will label the angles with capital letters A, B, C, and the sides with lowercase a, b, c where.
Notes Over 8.1 Solving Oblique Triangles To solve an oblique triangle, you need to be given one side, and at least two other parts (sides or angles).
14. Law of Sines The Ambiguous Case (SSA). Yesterday we saw that two angles and one side determine a unique triangle. However, if two sides and one opposite.
7.1 The Law of Sines 56 46° 63° A B C. 7.1 The Law of Sines 14 64° 82° A B C.
Law of Sines Day 2- The ambiguous case. Reminder Yesterday we talked in great detail of the 2/3 cases in which you can use law of sines: AAS ASA Today.
Ambiguous Law of Sines Compute b sin A, then compare to a No solution One Solution Two Solutions One Solution Compute side a to side b No solution One.
Lesson 6.5 Law of Cosines. Solving a Triangle using Law of Sines 2 The Law of Sines was good for: ASA- two angles and the included side AAS- two angles.
Lesson Quiz Lesson Quiz Lesson Presentation Lesson Presentation Lesson 9.5 Apply the Law of Sines Warm-Up Standard Accessed: Students will prove, apply,
Section 4.2 – The Law of Sines. If none of the angles of a triangle is a right angle, the triangle is called oblique. An oblique triangle has either three.
The Law of Sines Day 1: Areas and AAS
Honors Geometry Section 10.5 Law of Cosines. In section 10.4, we learned how to use the Law of Sines to solve a non-right triangle. The Law of Sines will.
EXAMPLE 1 Solve a triangle for the AAS or ASA case Solve ABC with C = 107°, B = 25°, and b = 15. SOLUTION First find the angle: A = 180° – 107° – 25° =
Section 8.1: Right Triangle Trigonometry: Applications and Section 8.2: Law of Sines Copyright © 2013 Pearson Education, Inc. All rights reserved.
Pre calculus Problem of the Day Homework p. p odds, odds Find the area of a triangle with the given dimensions. r = 15 in s = 13 in t.
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
The Trigonometric Functions
Chapter 4 Laws of Sines and Cosines; Vectors 4.1 The Law of Sines 1
5.7 The Ambiguous Case for the Law of Sines
9.1 Law of Sines.
Objective: Use the law of sine. (SSA)
Section 8.2 The Law of Sines
5.6 The sine law Watch this!! Ambiguous Case
Unit 6: Trigonometry Lesson: Law of coSines.
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
The Ambiguous Case (SSA)
Section 8.1 The Law of Sines
Homework Questions.
Copyright © 2017, 2013, 2009 Pearson Education, Inc.
5.3 The Ambiguous Case.
Section 9.4 Area of a Triangle
5.5 Law of Sines.
Copyright © 2014 Pearson Education, Inc.
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
Law of Sines Goal: To solve triangles which aren’t necessarily
Section 6.1.
Law of Sines and Cosines
Law of Sines Notes Over If ABC is a triangle with sides a, b, c, then according to the law of sines, or.
Solve the oblique triangle with the following measurements:
Section 9.2 The Law of Sines
Law of Cosines.
Section 8.3 The Law of Cosines
5.5 Law of Sines.
Section 9.2 The Law of Sines
NOTES Law of Cosines.
8-6 Using the Law of Sines Objectives:
LT: I can use the Law of Sines and the Law of Cosines to find missing measurements on a triangle. Warm-Up Find the missing information.
8-5 Using the Law of Sines Objectives:
7.2 The Law of Sines.
Law of Sines (Lesson 5-5) The Law of Sines is an extended proportion. Each ratio in the proportion is the ratio of an angle of a triangle to the length.
The Law of Sines.
Presentation transcript:

When can we use the Sine Law? B A a C c b SINE LAW : 𝑎 𝑠𝑖𝑛𝐴 = 𝑏 𝑠𝑖𝑛𝐵 = 𝑐 𝑠𝑖𝑛𝐶 So if we knew Angles A and B and side c our calculations would be: Case 1: Two Angles & a Side ( AAS) solve for the 3rd unknown angle using the fact that the 3 angles add to 180o Use 2 ratios of the Sine Law to solve for one of the two unknown sides Use 2 ratios of the Sine Law to solve for the last unknown side 𝐶= 180 𝑜 −𝐴−𝐵 𝑎 𝑠𝑖𝑛𝐴 = 𝑐 𝑠𝑖𝑛𝐶 ⇒𝑎= 𝑐(𝑠𝑖𝑛𝐴) 𝑠𝑖𝑛𝐶 𝑏 𝑠𝑖𝑛𝐵 = 𝑐 𝑠𝑖𝑛𝐶 ⇒𝑏= 𝑐(𝑠𝑖𝑛𝐵) 𝑠𝑖𝑛𝐶 Washington/Evans Basic Technical Mathematics 11e -- Copyright © 2018 Pearson Inc.

When can we use the Sine Law? B b c SINE LAW : 𝑎 𝑠𝑖𝑛𝐴 = 𝑏 𝑠𝑖𝑛𝐵 = 𝑐 𝑠𝑖𝑛𝐶 Case 2: Two Sides & Angle Opposite a Side ( SSAopp) solve for the unknown angle opposite the known side solve for the last unknown angle using the fact that the 3 angles add to 180o Use 2 ratios of the Sine Law to solve for the last unknown sides So if we knew Angle A and sides a and b our calculations would be: 𝑎 𝑠𝑖𝑛𝐴 = 𝑏 𝑠𝑖𝑛𝐵 ⇒𝑠𝑖𝑛𝐵= 𝑏(𝑠𝑖𝑛𝐴) 𝑎 𝐶= 180 𝑜 −𝐴−𝐵 𝑎 𝑠𝑖𝑛𝐴 = 𝑐 𝑠𝑖𝑛𝐶 ⇒𝑐= 𝑎(𝑠𝑖𝑛𝐶) 𝑠𝑖𝑛𝐴 Washington/Evans Basic Technical Mathematics 11e -- Copyright © 2018 Pearson Inc.

Case 2 – possible solutions SINE LAW : 𝑎 𝑠𝑖𝑛𝐴 = 𝑏 𝑠𝑖𝑛𝐵 = 𝑐 𝑠𝑖𝑛𝐶 Case 2: Two Sides & Angle Opposite a Side ( SSAopp) we could get the following solutions: No solution if 𝑎<𝑏(𝑠𝑖𝑛𝐴) a b A A a b A right triangle solution if 𝑎=𝑏 𝑠𝑖𝑛𝐴 Called Ambiguous Case a b A B C a b A C’ B’ a b A Two solutions if 𝑏(𝑠𝑖𝑛𝐴)<𝑎<𝑏 One solution if 𝑎>𝑏(𝑠𝑖𝑛𝐴) Washington/Evans Basic Technical Mathematics 11e -- Copyright © 2018 Pearson Inc.