King Fahd University of Petroleum & Minerals Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 33

General Application of the Equations of Motion Summation of moment in FBD = summation of the kinetic moment in K.D

Rectilinear Translation

Curvilinear Translation

Example mm=125 kg mR= 75 kg a= ? NB=? FB=? ms=? Minimum to Lift front wheel

Problem m = 80 kg mB= 0.8 NA= ? NB= ? When rear wheel locks for break a = ? Deceleration aG mBNB NA NB

Problem m= 80 kg mB= ? NA=? NB=? a =? When traveling at constant velocity and no break was applied NA NB mBNB a = 0

Problem m= 80 kg NA=? NB=? a =? mk=? minimum When rider applies the front break and back wheel start to lift off the ground NA NB=0 mkNA

Example mBD=100kg mAB=mCD= Neglect q = 30o w = 6 rad/s TA= ? TD= ? aG=?

Rotation About a Fixed Axis

Pin Reaction Horizontal Reaction Vertical Reaction OR Normal Reaction Tangential Reaction If G&O are same use horizontal and vertical If G&O are not same use normal and tangential On Ot Ox On Oy Ot

Example 17-9 Start from rest m = 30 kg w=20rad/s Pin reaction? q=? Number

Example 17-10 m= 20 kg

Example 17-11 m=60 kg Radius of gyration kO=0.25 mb=20 kg a=? Drum a=?

Example 17-12 W=50 Ib kG=0.6 ft w= 8 rad/s Pin reaction =?

Thank you