1) ALL non-zero numbers (1,2,3,4,5,6,7,8,9) are ALWAYS significant. Significant figures are critical when reporting scientific data because they.

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1) ALL non-zero numbers (1,2,3,4,5,6,7,8,9) are ALWAYS significant. Significant figures are critical when reporting scientific data because they give the reader an idea of how well you could actually measure/report your data. Before looking at a few examples, let's summarize the rules for significant figures. 1) ALL non-zero numbers (1,2,3,4,5,6,7,8,9) are ALWAYS significant. 2) ALL zeroes between non-zero numbers are ALWAYS significant. 3) ALL zeroes which are SIMULTANEOUSLY to the right of the decimal point AND at the end of the number are ALWAYS significant. 4) ALL zeroes which are to the left of a written decimal point and are in a number >= 10 are ALWAYS significant. A helpful way to check rules 3 and 4 is to write the number in scientific notation. If you can/must get rid of the zeroes, then they are NOT significant. Examples: How many significant figures are present in the following numbers? Number # Significant Figures Rule(s) 48,923 5 1 3.967 4 900.06 1,2,4 0.0004 (= 4x10-4) 1,4 8.1000 1,3 501.040 6 1,2,3,4 3,000,000 (= 3x10+6) 10.0 (= 1.00 x10+1) 3 1,3,4

ADDITION AND SUBTRACTION: When adding or subtracting numbers, count the NUMBER OF DECIMAL PLACES to determine the number of significant figures. The answer cannot CONTAIN MORE PLACES AFTER THE DECIMAL POINT THAN THE SMALLEST NUMBER OF DECIMAL PLACES in the numbers being added or subtracted. Example: MULTIPLICATION AND DIVISION: When multiplying or dividing numbers, count the NUMBER OF SIGNIFICANT FIGURES. The answer cannot CONTAIN MORE SIGNIFICANT FIGURES THAN THE NUMBER BEING MULTIPLIED OR DIVIDED with the LEAST NUMBER OF SIGNIFICANT FIGURES. Example: 23.123123 (8 significant figures) x 1.3344 (5 significant figures) 30.855495 (on calculator) 30.855 (rounded to 5 significant figures) 23.112233 (6 places after the decimal point) 1.3324 (4 places after the decimal point) +0.25 (2 places after the decimal point) 24.694633 (on calculator) 24.69 (rounded to 2 places in the answer)

Summary International System of Units (SI): Base Units length Anytime when we solve physics problems we need to use all the variables in the same system of units. It is more convenient to use International System of Units (SI units). When you solve physics problems: remember to check the units before you substitute all the numbers into the equations. All variables should be in SI units. International System of Units (SI): Base Units length meter (m) mass kilogram (kg) time second (s) electric current ampere (A) temperature kelvin (K)

Problem 2: Convert the following expressions to SI units: (a) 5 hours (b) 6 years (c) 10 in/s Solution: Equations we need to use: Problem 1: Convert the following expressions to SI units: (a) 16 in (b) 100 mph (c) 88 ft/s Solution: Equations we need to use: Problem 3: Convert the following expressions to SI units: (a)  (b)  Solution: Equations we need to use:

How many significant figures are in each of the following numbers? a) 1.234 b) 1.2340 c) 1.234 x 10-3 d) 1.2340 x 10-3 e) 1234 f) 12340 g) 0.012340 Perform the indicated operations. Express your answers with the correct number of significant figures: a) 42.3 x 2.61 = b) 0.61 x 42.1 = c) 46.1 / 1.21 = d) 23.2 / 4.1 = a) 1.234: 4 b) 1.2340: 5 c) 1.234 x 10-3: 4 d) 1.2340 x 10-3: 5 e) 1234: 4 f) 12340: 5 g) 0.012340: 5 a) 42.3 x 2.61 = 110 b) 0.61 x 42.1 = 26 c) 46.1 / 1.21 = 38.1 d) 23.2 / 4.1 = 5.7 Complete the following arithmetic operations and express the answer with the correct number of significant figures: a) 1.421+ 0.4372 = b) 0.0241 + 0.11 = c) 0.14 + 1.2243 = d) 760.0 + 0.011 = e) 1.0123 - 0.002 = f) 123.69 - 20.1 = g) 463.231 - 14.0 = h) 47.2 - 0.01 = a) 1.421+ 0.4372 = 1.858 b) 0.0241 + 0.11 = 0.13 c) 0.14 + 1.2243 = 1.36 d) 760.0 + 0.011 = 760.0 e) 1.0123 - 0.002 = 1.010 f) 123.69 - 20.1 = 103.6 g) 463.231 - 14.0 = 449.2 h) 47.2 - 0.01 = 47.2