Chemical Reaction Engineering

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Presentation transcript:

Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR

Summary At the start of the chapter we saw we needed -rA=f(X). This result is achieved in two steps. Rate Laws -rA=k f(Ci) 1st order or 2nd order Rate laws are found by experiment Stoichiometry Liquid: Gas: A + B  C -rA=kCA -rA=kACACB

(Level 1) General mole balance Ch. 1 (Level 1) General mole balance (Level 9) Find appropriate design Equation Ch.2 (Level 2) Design Equation for specific reactor IS –rA=f(X) given Ch.2 (Level 3) (level 4) determined the Rate law in terms of concentration Ch.3 Ch.4 Ch.4 (level 5) use stoichiometry to express concentration as function of X (level 6) if gas with P=P0 or Liquid Ch.3 (level 7) Determine the pressure drop in the reactor (level 8) Combine the equation of pressure drop with level 4,5 Ch.4

Algorithm for Isothermal Reactor Design Mole Balance and Design Equation Choose species reacting and the reactor Rate Law Identify the reaction order and reaction parameters Stoichiometry Choose the reaction phase and concentrations Combine Step 1, 2 & 3 Evaluate Analytical, Graphical, Numerical and Using Software

French Menu Analogy Example: Mole Balance: Rate Law: Stoichiometry: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B. Stoichiometry: Mole Balance: Rate Law: gas phase, isothermal (T=T0), no pressure drop (P=P0)

French Menu Analogy For a gas phase system: If the conditions are isothermal (T = T0) and isobaric (P =P0): We must divide by the stoichiometric coefficient of our basis of calculation yielding: And if the feed is equal molar, then:

French Menu Analogy This leaves us with CA as a function of conversion alone: Similarly for CB:

French Menu Analogy Combine: Evaluate: