Lesson 56 – Probability of Dependent Events – Conditional Probabilty

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Lesson 56 – Probability of Dependent Events – Conditional Probabilty Math 2 Honors - Santowski 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Lesson Objectives Give the definition of the term dependence. Explain the meaning of P(E|F). Use the properties in this section to compute probabilities. Use given information to find probabilities. Use the definition of independence to determine whether or not two events are independent. 11/24/2019 Math 2 Honors - Santowski

(A) Review – Independent Events If A and B are two independent events, then the probability of occurrence of A and B together is given by: If two fair dice are thrown, the probability of a double 5 is (1/6)(1/6) = 1/36. 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski (B) Dependent Events If two events are DEPENDENT  the occurrence of one affects the probability of the occurrence of the other. If the events are dependent, conditional probability must be used  which we define as the probability of one event, A, occurring given that another, B, is already known to have occurred: 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski (B) Dependent Events If the events are dependent, conditional probability must be used. The conditional probability of B given that A occurs, or on condition that A occurs, is written P[B | A]. Conditional probability can be found by considering only those events which meet the condition, which in this case is that A occurs. 11/24/2019 Math 2 Honors - Santowski

(B) Dependent Events – Multiplication Rule The multiplication rule for the occurrence of both A and B together when they are NOT independent is the product of the probability of one event and the conditional probability of the other. 11/24/2019 Math 2 Honors - Santowski

(B) Dependent Events – Multiplication Rule The formula(s) Can be rearranged as follows: 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski (B) Dependent Events 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski (C) Example There are 14 balls in a box of which 5 are red and 9 are blue. If two balls are selected at random without replacement, (i) what is the probability that just one ball is red? (ii) What is the probability that both balls are red? 11/24/2019 Math 2 Honors - Santowski

Tree diagram R2 Pr[R2 | R1] = 4/13 R1 Pr[R1] = 5/14 Pr[B2 | R1] = 9/13 Pr[R2 | B1] = 5/13 Pr[B2 | B1] = 8/13 Pr[B1] = 9/14 B1

Math 2 Honors - Santowski Example (Solution) What is the probability that just one ball is red? What is the probability that both balls are red? 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 2 Three balls are drawn one after the other from a bag containing 6 red balls, 5 yellow balls and 3 green balls. What is the probability that all three balls are yellow if: (a) the ball is replaced after each draw and the contents are well mixed? (b) the ball is not replaced after each draw? 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 2 If the ball is replaced after each draw, then the events are independent and the probability of drawing a yellow ball remains same. Pr[Y1] = Pr[Y2] = Pr[Y3] = 5/14 Pr[ three balls are yellow] = (5/14)(5/14)(5/14) = 0.046 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 2 If the ball is not replaced, then the events are NOT independent and the probability of drawing a yellow ball depends on the previous draw. Pr[Y1] = 5/14 and Pr[Y2 | Y1] = 4/13 And: 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 3 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 3 - Solution 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 3 - Solution 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 4 Given 2 die, What is the probability of rolling the sum of 3, given that we rolled a sum less than 5 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 4 - Solution Event E is rolling the sum of 3  E = {(1,2), (2,1)} and we know P(E) = 2/36 = 1/18 Event F is rolling a sum less than 5  F = {(1,1), (1,2), (2,1), (1,3), (3,1), (2,2)} Therefore, P(E|F) = 2/6 = 1/3 or using our formula 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 5 The probability that event E occurs is 0.63 The probability that event F occurs is 0.45 The probability that both events occur is 0.10 Find P(E|F) and P(F|E) 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 5 - Solution The probability that event E occurs is 0.63 The probability that event F occurs is 0.45 The probability that both events occur is 0.10 Find P(E|F) and P(F|E) 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 6 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Example 6 - Solution 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Independent Events 11/24/2019 Math 2 Honors - Santowski

Independent Events - Examples 11/24/2019 Math 2 Honors - Santowski

Independent Events – Examples (Solns) 11/24/2019 Math 2 Honors - Santowski

Independent Events – Examples (Solns) 11/24/2019 Math 2 Honors - Santowski

Independent Events – Examples (Solns) 11/24/2019 Math 2 Honors - Santowski

Math 2 Honors - Santowski Homework 11/24/2019 Math 2 Honors - Santowski