Before the Bell Rings Grab 1 Paper from the side table Have your Conductivity Lab Sheet out to check.
ETD 48 2019 Rank the conductivity of the following in solution, Draw + Explain your predictions. Lithium Chloride C6H12O6 Strontium Chloride
ETD 48 ANS B. Rank the conductivity of the following in solution, Draw + Explain your predictions? Lithium Chloride C6H12O6 Strontium Chloride
ETD 48 ANS B. Rank the conductivity of the following in solution, Draw + Explain your predictions? Lithium Chloride C6H12O6 Strontium Chloride
Learning Targets I can explain qualitatively the different points on a solubility curve. I can calculate the mass percentage of a solution. I can calculate the molarity of a solution.
Notebook check next class Numbers 31-45 All slides should be posted to my Google Classroom or Swift Site 3 points for each ETD- Total out of 45 in front, total out of 3 on each 1 for having the ETD number 1 for having the question 1 for having the answer
Notes on new things
Solubility Curves What does the word soluble mean? What does this graph tell you about each of the chemicals?
Mass Percent By mass, the percent of the solution that is solute = Mass of solute______ x 100 Total mass of solution How many grams of a 20.5% solution of NaCl would contain 10.2 grams of NaCl?
Mass Percent By mass, the percent of the solution that is solute = Mass of solute______ x 100 Total mass of solution How many grams of a 20.5% solution of NaCl would contain 10.2 grams of NaCl?
Mass Percent By mass, the percent of the solution that is solute = Mass of solute______ x 100 Total mass of solution How many grams of a 20.5% solution of NaCl would contain 10.2 grams of NaCl? 20.5 % NaCl = (10.2g NaCl)(100) (x) (20.5)(x) = (10.2g NaCl)(100) x = 49.75609756 g of Solution x = 49.8 g of Solution
Chemical representation of concentration M = moles of solute = mol Molarity Chemical representation of concentration M = moles of solute = mol liters of solution L
Try this Molarity Problem 1. Calculate the molarity of a solution prepared by dissolving 11.5 g of solid NaOH in enough water to make 1500. mL of solution. 11.5 g of NaOH is the same as 0.288 moles of NaOH. 1500 mL equals 1.5 L. Therefore the molarity is 0.288 moles/1.5 L = 0.19M 450 mL = 0.450 L The problem is set up as x/0.450 L = 0.251 M. X equals 0.113 moles of NH4Cl. 0.113 moles of NH4Cl = 6.05 g of NH4Cl
1. Ans Try these Molarity Problems 1. Calculate the molarity of a solution prepared by dissolving 11.5 g of solid NaOH in enough water to make 1500. mL of solution. 11.5 g of NaOH is the same as 0.288 moles of NaOH. 1500 mL equals 1.5 L. Therefore the molarity is 0.288 moles/1.5 L = 0.19M 450 mL = 0.450 L The problem is set up as x/0.450 L = 0.251 M. X equals 0.113 moles of NH4Cl. 0.113 moles of NH4Cl = 6.05 g of NH4Cl
1. Ans Try these Molarity Problems 1. Calculate the molarity of a solution prepared by dissolving 11.5 g of solid NaOH in enough water to make 1500. mL of solution. 11.5 g of NaOH is the same as 0.288 moles of NaOH. 1500 mL equals 1.5 L. Therefore the molarity is 0.288 moles/1.5 L = 0.19M 450 mL = 0.450 L The problem is set up as x/0.450 L = 0.251 M. X equals 0.113 moles of NH4Cl. 0.113 moles of NH4Cl = 6.05 g of NH4Cl
Learning Targets I can explain qualitatively the different points on a solubility curve. I can calculate the mass percentage of a solution. I can calculate the molarity of a solution.
Homework Molarity #1 WS Due next class Notebook check 31-45