GIG Read the passage and mark your answers on your whiteboard. NOT ON THE PAPER. Questions 27-29.
Power
Power Power is a measure of how much work is done within a given time. It is measure in watts (W). The formula for power is: P = W power = work / time t
Watts A watt (W) is 1 joule per second. 1W = 1 J s
Sample Problem An 80.0kg person climbs stairs, rising 3.7m vertically in 22s. How much power did the person apply?
Sample Problem An 80.0kg person climbs stairs, rising 3.7m vertically in 22s. How much power did the person apply? First find the force applied against gravity. F = mg = 80.0kg ✕ 9.81m/s2 = 784.8N Now find work. W = Fd = 784.8N(3.7m) = 2904J
Sample Problem An 80.0kg person climbs stairs, rising 3.7m vertically in 22s. How much power did the person apply? Power = work / time P = 2904J = 130W 22s
Try This on Your Whiteboard The “fancy” car in the example used 40.9 horsepower. How fast can a 2021kg Dodge Challenger Hellcat, using all 797 horsepower, accelerate from 13.4m/s to 17.9m/s? 797hp = 594,323W
Try This on Your Whiteboard The “fancy” car in the example used 40.9 horsepower. How fast can a 2021kg Dodge Challenger Hellcat, using all 797 horsepower, accelerate from 13.4m/s to 17.9m/s? P = W/t 594,323W = .5(2021kg)(17.9m/s)2 - .5(2021kg)(13.4m/s)2 t t = 142329J = 0.239s 594323W
Another Way to Think of Power If we rewrite P = W/t to include the definition of work (Fd), we have P = Fd = F(d/t) t d/t is velocity, so it is also true that P = Fv power = force times velocity
Solve These with your Teammates Page 216, LessonCheck problems 56-59.
Homework Review your notes from unit 1. Test on block day next week.
Closure In chapter 6, we learned that energy is conserved in a closed system and that we can calculate from energy to velocity. This will become important to collisions in chapter 7.