production estimate Question 1

Slides:



Advertisements
Similar presentations
Engineering economics
Advertisements

Background images courtesy of abc.com 1,000, , , ,000 64,000 32,000 16,000 8,000 4,000 2,000 1,
Excavators Cranes(will discuss another section)
Work and Energy Dr. Robert MacKay Clark College. Introduction What is Energy? What are some of the different forms of energy? Energy = $$$
Warm Up Solve each equation for y. 1. 7x + 2y = 6 2.
Speed, Velocity and Acceleration
DirectInverseJointVariations Radical Review
CalculatorsStatistics Number Sense EquationsFunctions
On your paper, graph the following: D (m) T (sec)
Welcome to Who Wants to be a Millionaire
Objectives After completion, you should 1. Know the term displacement, velocity,acceleration and deceleration for motion in a straight line 2. Be familiar.
CRCT Review. The weight of a new truck is 1,500 kg What is the weight of the truck in grams? A.) 150 B.) 15,000 C.) 1,500,000 D.) 150,000,000.
Time and Distance Formulas
HSAP TEST PREP REVIEW AND PRACTICE
Its Time For... KE and PE Jeopardy! Jeopardy $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100 $200 $300 $400 $500 $100.
What is it and how do I know when I see it?
Simple Interest Lesson
Applications Problem Solving. 6/25/2013 Applications 2 Four-step Method 1. Define variables Name the quantities to be found Write these down Example:
Looking at position, velocity, and acceleration from the integral.
What is a scale drawing?
Three featured concepts are: Speed Velocity Acceleration
Converting Fractions, Decimals & Percents Set #2.
The Science of Physics Chapter 1: Factor-Label and Dimensional Analysis.
Inverse Operations Operation Inverse Operation
$1 Million $500,000 $250,000 $125,000 $64,000 $32,000 $16,000 $8,000 $4,000 $2,000 $1,000 $500 $300 $200 $100 Welcome.
Are You Smarter Than a 5 th Grader? 1,000,000 5th Grade Topic 1 5th Grade Topic 2 4th Grade Topic 3 4th Grade Topic 4 3rd Grade Topic 5 3rd Grade Topic.
$200 $500 $1000 $2000 $100 $200 $500 $1000 $2000 $100 $200 $500 $1000 $2000 $100 $200 $500 $1000 $2000 $100 $200 $500 $1000 $2000 $100 Scientific Notation.
7th Gd, Jan. 17, Linear Functions
CC GPS Coordinate Algebra
Speed.
You will be given the answer. You must give the correct question.
Speed Calculations.
Chapter 1 Review Directions 1.The class will be split into four teams 2.Each team member will get a whiteboard to work out the problem 3.One team member.
Distance, speed and acceleration
TRAVEL MATHS D T S SPEED DISTANCE TRAVELLED JOURNEY TIME.
Speed Distance Time. Intermediate 1. Unit 2..
Physical Science Chapter 1
Chapter 11 Finishing Equipment
Section 5-8.  The dashboard of your car gives you a lot of information about your car’s ability to go  It gives no information about your car’s ability.
Solving Multiplication and Division Equations. EXAMPLE 1 Solving a Multiplication Equation Solve the equation 3x = x = 15 Check 3x = 45 3 (15)
Formula Practice Find the area for the figure below. 12 m 6 m Answer: #1.
1.5 “Problem Solving Strategies” Examples: 1. A train travels between Boston and Washington, a distance of 457 miles. The trip takes 6.5 hours. What is.
Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Chapter 7 Dozers.
Physics: Speed and Velocity Average Speed  Rate at which an object moves  Units are in distance / time  Ex. Meters/second, centimeters/hour.
Calculating Rates. Speeds Speeds are often described as rates. Ex: MPH = miles per hour MPS = meters per second In all the following slides we will use.
SOLVING AND APPLYING PROPORTIONS
To Start: 20 Points!! -2(4x + 3y – 4z – 11) 12(11) + 12(14) + 12(24) – 12(9) Use front-end estimation: Estimate the quotient: 29.5 ÷ x.
Speed, Distance, Time Calculations
What To Do… Open your manuals to page 23.
How Fast, How Far & How Long
To Start: 20 Points!! -2(4x + 3y – 4z – 11) 12(11) + 12(14) + 12(24) – 12(9) Use front-end estimation: Estimate the quotient: 29.5 ÷ 4.83.
Speed, Distance, Time Calculations
Find the product 1. (m – 8) (m – 9) ANSWER m2 – 17m + 72
Use a linear model to make a prediction.
Speed and Velocity What is Speed and Velocity?.
Speed, Distance, Time Calculations
Lecture 5 Dozer TSP-308 MPK Ferdinand Fassa.
Speed, Distance, Time Calculations
Starter Questions Convert the following to minutes :-
Speed, Distance, Time Calculations
Speed, Distance, Time Calculations
Speed, Distance, Time Calculations
An object travels 40 miles in 2 hrs. Calculate its speed?
Speed, Distance, Time Calculations
Speed, Distance, Time Calculations Final Review
Speed, Distance, Time Calculations
Velocity.
2.1 Using Problem Solving Strategies and Models
2.1 Using Problem Solving Strategies and Models
Speed, Distance, Time Calculations
Presentation transcript:

production estimate Question 1 Given the following dozer production charts, what is the average hourly production(LCY/hr) of a straight-blade D7(with tilt cylinder) moving hard-packed clay an average distance of 200 feet, down a 10 percent grade, using slot dozing. The estimated material weight is 2,500 lbs per LCY. The operator is of average ability and will work during daylight hours. Expected efficiency is 50 minutes per hours. a. How much time will it take to move 3,000LCY of hard packed clay, using one D7 dozer using the production rate figured out above? b. How many D7 dozers would be required to move 3000 LCY of clay in 7 hours? www.learncivilengineering.com

production estimate Answer 1 Given the following dozer production charts, what is the average hourly production(LCY/hr) of a straight-blade D7(with tilt cylinder) moving hard-packed clay an average distance of 200 feet, down a 10 percent grade, using slot dozing. The estimated material weight is 2,500 lbs per LCY. The operator is of average ability and will work during daylight hours. Expected efficiency is 50 minutes per hours. Step 1: Find the Ideal maximum dozer production rate. - Using production charts = 300 LCY Step 2: Find the different correction factors for less than ideal conditions. a). Material – weight Correction Factor CF = 2,300lbs/LCY / 2,500 lbs/LCY = .92 b). Operator correction factor - use table provided = .75 c). Material – Type Correction Factor - use table provided = .8 d). Operating technique Correction Factor - use table provided = 1.2 e). Visibility Correction Factor - use table provided = 1.0 f). Efficiency Factor - 50 working minutes per hour / 60 minute working hour = .83 g). Machine transmission factor h). Blade adjustment factor i). Grade Correction Factor - use chart/graph provided = 1.15 Step 3: Determine total Correction Factor - 1.15 x .92 x .8 x .75 x .83 x 1.2 x = .63 Step 4: Determine Production - Multiple Step 3 by Step 1 = 300LCY x .63 = 190 LCY How much time will it take to move 3,000LCY of hard packed clay, using one D7 dozer using the production rate figured out above? Total time (hours) = Q / (P x N) = 3,000 LCY/ (190 LCY x 1 dozer) = 16 hours b. How many D7 dozers would be required to move 3000 LCY of clay in 7 hours? Total number of dozers = Q / (P x T) = 3,000 LCY/ 190 LCY per hour x 7 hours = 2.25 up 3 www.learncivilengineering.com

Grader Example question 1 A 2000 ft x 150 ft plot of land needs to be graded, it is estimated that the grader will need to make two passes to get each pass to grade. The grader blade is 10 ft wide, with a average speed of 4 mph. The operator is very experienced, The efficiency of the operation is estimated to be 60%. The efficiency percentage takes into account the operators rest breaks and time required to turn around after each pass. How many hours is required to grade the Area? 150 ft 2000 ft Answer 3 hours 4 hours 5 hours 6 hours 3 www.learncivilengineering.com

Grader Example ANSWER 1 Using the given formula for graders production rate the questions is straight forward; Total time = (P x D) / (S x E) where— P = number of passes required D = distance traveled in each pass, in miles or feet S = speed of grader, in mph or fpm (multiply mph by 88 to convert to fpm) E = efficiency factor • Step 1: Figure out the Number of passes required.  You know that the width of the blade is 10 ft and the width of the area to be graded is 150. So 150ft divided by 10 ft per pass = 15 passes. Also it was given that the grader will need to conduct two passes in order to grade the ground properly so 15 x 2 = 30 pass required. Step 2: Figure out the required Distance traveled.  This was given to be 2000 ft Step 3: Figure out the Speed of the grader.  The speed was given as 4mph, which is 4mph x 88 fpm/mph = 352 fpm Step 4: Figure out the Efficiency factor.  This was also given to be .60 Step 5: Solve the equation  T = P x D / ( S x E ) = 30 pass x 2000ft/pass / ( 352 fpm) x .60 = 60,000 ft / 211.2 fpm = = 284 mins = 4.7 hrs round up to 5 hours 4 www.learncivilengineering.com