B a l a n c i n g E q u a t i o n s B y I n s p e c t i o n.

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Presentation transcript:

B a l a n c i n g E q u a t i o n s B y I n s p e c t i o n

C h e m i c a l E q u a t i o n s A w a y t o r e p r e s e n t a c h e m i c a l r e a c t i o n o n p a p e r.

E q u a t i o n s m u s t b e b a l a n c e d : A t o m s c a n b e n e i t h e r c r e a t e d n o r d e s t r o y e d b y o r d i n a r y c h e m i c a l m e a n s. (LAW OF CONSERVATION)

E q u a t i o n s m u s t b e b a l a n c e d : a l w a y s h a v e t h e s a m e n u m b e r o f e a c h t y p e o f a t o m o n b o t h s i d e s o f t h e e q u a t i o n.

7 s t e p s t o b a l a n c e b y i n s p e c t i o n 1. C h e c k f o r d i a t o m i c m o l e c u l e s - H 2 - N 2 - O 2 - F 2 - Cl 2 - Br 2 - I 2 I f t h e s e e l e m e n t s a p p e a r b y t h e m s e l v e s i n a n e q u a t i o n, t h e y M U S T b e w r i t t e n w i t h a s u b s c r i p t o f 2.

7 s t e p s t o b a l a n c e b y i n s p e c t i o n 2. B a l a n c e m e t a l s (+) 3. B a l a n c e n o n m e t a l s 4. B a l a n c e o x y g e n 5. B a l a n c e h y d r o g e n

7 s t e p s t o b a l a n c e b y i n s p e c t i o n 6. R e c o u n t a l l a t o m s 7. I f E V E R Y c o e f f i c i e n t w i l l r e d u c e, r e w r i t e t h e w h o l e e q u a t i o n u s i n g t h e s i m p l e s t r a t i o o f c o e f f i c i e n t s.

P r a c t i c e 1 NaOH --> Na 2 O + H 2 O 2NaOH --> Na 2 O + H 2 O Fe + O --> Fe 2 O 3 4Fe + 3O 2 --> 2Fe 2 O 3

P r a c t i c e 2 O + H --> H 2 O O 2 + 2H 2 --> 2H 2 O Cl + NaI --> NaCl + I Cl 2 + 2NaI --> 2NaCl + I 2

P r a c t i c e 3 CO 2 + H 2 O --> C 6 H 12 O 6 + O 6CO 2 + 6H 2 O --> C 6 H 12 O 6 + 6O 2 FeS + HCl --> FeCl 2 + H 2 S FeS + 2HCl --> FeCl 2 + H 2 S

P r a c t i c e 4 Al(NO 3 ) 3 + H 2 SO 4 --> Al 2 (SO 4 ) 3 + HNO 3 2Al(NO 3 ) 3 + 3H 2 SO 4 --> Al 2 (SO 4 ) 3 + 6HNO 3

P r a c t i c e 5 Zn + HCl --> ZnCl 2 + H Zn + 2HCl --> ZnCl 2 + H 2

P r a c t i c e 6 Al 2 O 3 + H 2 O --> Al(OH) 3 Al 2 O 3 + 3H 2 O --> 2Al(OH) 3

P r a c t i c e 7 Pb(NO 3 ) 2 + AlCl 3 --> PbCl 2 + Al(NO 3 ) 3 3Pb(NO 3 ) 2 + 2AlCl 3 --> 3PbCl 2 + 2Al(NO 3 ) 3

E N D E Q U A T I O N S