Solutions Molarity ICS.

Slides:



Advertisements
Similar presentations
Solutions Part II DHS Chemistry Chapter 15.
Advertisements

What is the % composition of carbon in benzene (C6H6)?
16.2 Concentration of Solutions
Chapter 14 Section 14.2 Solution Concentration
ICS1 Solution Percent Concentration ICS2 Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100.
Entry Task: April 27th Friday
8.4 Percent Concentration
Calculations of Solution Concentration. CA Standards.
MOLARITY – Ch 13, p. 412 Quantifies the concentration of a solution.
Solution Concentration. Calculations of Solution Concentration Mole fraction Mole fraction – the ratio of moles of solute to total moles of solution.
3PbO2 + Cr2(SO4)3 + K2SO4 + H2O  3PbSO4 + K2Cr2O7 + H2SO4
Practice: Know your vocabulary!
1 Chapter 7 Solutions 7.5 Molarity and Dilution. 2 Molarity (M) Molarity (M) is a concentration term for solutions. gives the moles of solute in 1 L solution.
1 Chapter 10 Acids and Bases 10.10Dilutions. 2 Dilution Diluting a solution Is the addition of water. Decreases concentration. ConcentratedDilutedSolution.
1 Chapter 7 Solutions and Colloids 7.4 Solution Concentrations.
Concentration. Concentration Particles per volume Can be in grams per litre but chemists usually express concentration in moles per litre This are related.
CONCENTRATION OF SOLUTIONS Day 4 CONCENTRATION  A measurement of the amount of solute in a given amount of solvent or solution (unit of measurement.
Chapter 13 Solutions Molarity.
Molarity and Molality.
Examples-Molarity and Dilutions. Example What is the molarity of a solution that contains 4.5 moles of sucrose in L of water?
Chapter 12 Solutions 12.5 Molarity and Dilution.
Molarity. Molarity Molarity (M) or molar concentration is a measure of the concentration of a solute in a solution. Unit for molar concentration is mol/L.
CONCENTRATION OF SOLUTIONS Day 4 CONCENTRATION  A measurement of the amount of solute in a given amount of solvent or solution (unit of measurement.
Avogadro’s number is written as conversion factors x particles and 1 mole 1 mole 6.02 x particles The number of molecules in 0.50 mole.
1 Chapter 7Solutions 7.4 Percent Concentration Copyright © 2009 by Pearson Education, Inc.
Preparing a Molar Solution
Concentration Concentration is the amount of solute dissolved in an amount of solution. Molar concentration is called Molarity, or M. M = moles.
Aqueous Reactions Aqueous Reactions and Solution Stoichiometry CDO High School.
LecturePLUS Timberlake1 Chapter 8 Solutions Molarity.
Solutions Molality. Molality (m) A concentration that expresses the moles of solute in 1 kg of solvent Molality (m) = moles of solute 1 kg solvent.
1 Molarity. 2 Review of Converstions Fractions that = 1 Different units and numbers that equal each other Example: 1 in. = 2.54 cm Factors: 1 in. OR 2.54.
Solutions Molarity. Molarity (M) A concentration that expresses the moles of solute in 1 L of solution Molarity (M) = moles of solute 1 liter solution.
Molarity and Dilution Chapter 12 Solutions Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings.
1 Chapter 7 Solutions 7.5 Molarity and Dilution Copyright © 2009 by Pearson Education, Inc.
Helpful Definitions Solutions: homogeneous mixture of two or more substances physically mixed together in a uniform way. Solute: substance being dissolved.
Basic Chemistry Copyright © 2011 Pearson Education, Inc. 1 Chapter 12 Solutions 12.4 Percent Concentration.
Molarity. Molarity (M) A concentration that expresses the moles of solute in 1 L of solution Molarity (M) = moles of solute 1 liter solution.
Chemistry: An Introduction to General, Organic, and Biological Chemistry, Eleventh Edition Copyright © 2012 by Pearson Education, Inc. Chapter 7 Solutions.
1 Chapter 8 Solutions Solubility Percent Concentration Colloids and Suspensions.
Chapter 8 Molarity Part 1. Solutions Solute The substance that dissolves (the minor component of a solution). KMnO 4.
Solutions Percent Concentration Describes the amount of solute dissolved in 100 parts of solution amount of solute 100 parts solution.
© 2013 Pearson Education, Inc. Chapter 8, Section 5 1 Learning Check What is the molarity (M) of a solution prepared by diluting 10.0 mL of 2.7 M NaOH.
Solutions Molarity.
Basic Chemistry Copyright © 2011 Pearson Education, Inc Molarity and Dilution Chapter 12 Solutions.
Solutions. A solution is a homogenous mixture of 2 or more substances. The solute is(are) the substance(s) present in the smaller amount(s). What is being.
Molarity moles of solute Liters of solution Unit for molarity mole mol LiterL = M.
1 Chapter 15: Solutions Concentration: Molarity & Mass Percent Ch 15 ppt 2 - Molarity.ppt.
Monday, May 9 th,  In Chemistry, many reactions take place in water. This is also true for Biological processes.  Reactions that take place in.
Solutions:MOLARITY Monday, April 24th, 2017.
Aqueous Reactions and Solution Stoichiometry
Introduction to Molarity
LecturePLUS Timberlake
Molality (m) A concentration that expresses the
Percent Concentration
Solutions Molarity ICS.
Section 4.5 Solution Stoichiometry
Learning Check What is the molarity (M) of a solution prepared by
Solution Concentration
Solutions Section 3: Dilutions Dilutions Calculations print 1-3,5-7.
M = moles solute L vol solution M= 0.75 moles = 3 M 0.25 liters
Chapter 7 Solutions 7.5 Molarity and Dilution
Section 4.5 Solution Stoichiometry
II. Molarity.
LecturePLUS Timberlake
Percent Concentration
Percent Concentration
Conversions To Liters Using this conversion, you can determine the volume of a GAS at STP. STP is Standard Temperature and Pressure. (1 atm and 273 Kelvin)
Solution Concentration
Molarity Calculate the concentration of a solute in terms of grams per liter, molarity, and percent composition.
Table of Contents Chapter 15: Solutions.
Presentation transcript:

Solutions Molarity ICS

Molarity (M) A concentration that expresses the moles of solute in 1 L of solution Molarity (M) = moles of solute 1 litre solution ICS

Units of Molarity 2.0 M HCl = 2.0 moles HCl 1 L HCl solution ICS

Molarity Calculation NaOH is used to open blocked sinks, to treat cellulose in the making of nylon, and to remove potato peel commercially. If 4.0 g NaOH are used to make 500. mL of NaOH solution, what is the molarity (M) of the solution? ICS

Calculating Molarity = 0.20 M NaOH 1) 4.0 g NaOH x 1 mole NaOH = 0.10 mole NaOH 40.0 g NaOH 2) 500. mL x 1 L _ = 0.500 L 1000 mL 3. 0.10 mole NaOH = 0.20 mole NaOH 0.500 L 1 L = 0.20 M NaOH ICS

Test question 1 A KOH solution with a volume of 400 mL contains 2 mole KOH. What is the molarity of the solution? 1) 8 M 2) 5 M 3) 2 M Drano ICS

Answer A KOH solution with a volume of 400 mL contains 2 moles of KOH. What is the molarity of the solution? 2) 5 M M = 2 mole KOH = 5 M 0.4 L Drano ICS

Test question 2 A glucose solution with a volume of 2.0 L contains 72 g glucose (C6H12O6). If glucose has a molar mass of 180. g/mole, what is the molarity of the glucose solution? 1) 0.20 M 2) 5.0 M 3) 36 M ICS

Answer 2 A glucose solution with a volume of 2.0 L contains 72 g glucose (C6H12O6). If glucose has a molar mass of 180. g/mole, what is the molarity of the glucose solution? 1) 72 g x 1 mole x 1 = 0.20 M 180. g 2.0 L ICS

Molarity Conversion Factors A solution is a 3.0 M NaOH.. Write the molarity in the form of conversion factors. 3.0 moles NaOH and 1 L NaOH soln 1 L NaOH soln 3.0 moles NaOH ICS

Test question 3 1) 15 moles HCl 2) 1.5 moles HCl 3) 0.15 moles HCl Stomach acid is a 0.10 M HCl solution. How many moles of HCl are in 1500 mL of stomach acid solution? 1) 15 moles HCl 2) 1.5 moles HCl 3) 0.15 moles HCl ICS

Answer 3 3) 1500 mL x 1 L = 1.5 L 1000 mL 1.5 L x 0.10 mole HCl = 0.15 mole HCl 1 L (Molarity factor) ICS

Test question 4 How many grams of KCl are present in 2.5 L of 0.50 M KCl? 1) 1.3 g 2) 5.0 g 3) 93 g ICS

Answer 4 3) 2.5 L x 0.50 mole x 74.6 g KCl = 93 g KCl 1 L 1 mole KCl ICS

Test question 5 1) 150 mL 2) 1500 mL 3) 5000 mL How many milliliters of stomach acid, which is 0.10 M HCl, contain 0.15 mole HCl? 1) 150 mL 2) 1500 mL 3) 5000 mL ICS

Answer 5 0.10 mole HCl 1 L (Molarity inverted) = 1500 mL HCl 2) 0.15 mole HCl x 1 L soln x 1000 mL 0.10 mole HCl 1 L (Molarity inverted) = 1500 mL HCl ICS

Test question 6 How many grams of NaOH are required to prepare 400. mL of 3.0 M NaOH solution? 1) 12 g 2) 48 g 3) 300 g ICS

Answer 6 2) 400. mL x 1 L = 0.400 L 1000 mL 0.400 L x 3.0 mole NaOH x 40.0 g NaOH 1 L 1 mole NaOH (molar mass) = 48 g NaOH ICS