MEKANIKA FLUIDA II Nazaruddin Sinaga KULIAH VIII - IX MEKANIKA FLUIDA II Nazaruddin Sinaga
Entrance Length
Shear stress and velocity distribution in pipe for laminar flow
Typical velocity and shear distributions in turbulent flow near a wall: (a) shear; (b) velocity.
Solution of Pipe Flow Problems Single Path Find Dp for a given L, D, and Q Use energy equation directly Find L for a given Dp, D, and Q
Solution of Pipe Flow Problems Single Path (Continued) Find Q for a given Dp, L, and D Manually iterate energy equation and friction factor formula to find V (or Q), or Directly solve, simultaneously, energy equation and friction factor formula using (for example) Excel Find D for a given Dp, L, and Q Manually iterate energy equation and friction factor formula to find D, or
Example 1 Water at 10C is flowing at a rate of 0.03 m3/s through a pipe. The pipe has 150-mm diameter, 500 m long, and the surface roughness is estimated at 0.06 mm. Find the head loss and the pressure drop throughout the length of the pipe. Solution: From Table 1.3 (for water): = 1000 kg/m3 and =1.30x10-3 N.s/m2 V = Q/A and A=R2 A = (0.15/2)2 = 0.01767 m2 V = Q/A =0.03/.0.01767 =1.7 m/s Re = (1000x1.7x0.15)/(1.30x10-3) = 1.96x105 > 2000 turbulent flow To find , use Moody Diagram with Re and relative roughness (k/D). k/D = 0.06x10-3/0.15 = 4x10-4 From Moody diagram, 0.018 The head loss may be computed using the Darcy-Weisbach equation. The pressure drop along the pipe can be calculated using the relationship: ΔP=ghf = 1000 x 9.81 x 8.84 ΔP = 8.67 x 104 Pa
Example 2 Determine the energy loss that will occur as 0.06 m3/s water flows from a 40-mm pipe diameter into a 100-mm pipe diameter through a sudden expansion. Solution: The head loss through a sudden enlargement is given by; Da/Db = 40/100 = 0.4 From Table 6.3: K = 0.70 Thus, the head loss is
Example 3 Calculate the head added by the pump when the water system shown below carries a discharge of 0.27 m3/s. If the efficiency of the pump is 80%, calculate the power input required by the pump to maintain the flow.
Solution: Applying Bernoulli equation between section 1 and 2 (1) P1 = P2 = Patm = 0 (atm) and V1=V2 0 Thus equation (1) reduces to: (2) HL1-2 = hf + hentrance + hbend + hexit From (2):
The velocity can be calculated using the continuity equation: Thus, the head added by the pump: Hp = 39.3 m Pin = 130.117 Watt ≈ 130 kW.
EGL & HGL for a Pipe System Energy equation All terms are in dimension of length (head, or energy per unit weight) HGL – Hydraulic Grade Line EGL – Energy Grade Line EGL=HGL when V=0 (reservoir surface, etc.) EGL slopes in the direction of flow
EGL & HGL for a Pipe System A pump causes an abrupt rise in EGL (and HGL) since energy is introduced here
EGL & HGL for a Pipe System A turbine causes an abrupt drop in EGL (and HGL) as energy is taken out Gradual expansion increases turbine efficiency
EGL & HGL for a Pipe System When the flow passage changes diameter, the velocity changes so that the distance between the EGL and HGL changes When the pressure becomes 0, the HGL coincides with the system
EGL & HGL for a Pipe System Abrupt expansion into reservoir causes a complete loss of kinetic energy there
EGL & HGL for a Pipe System When HGL falls below the pipe the pressure is below atmospheric pressure
FLOW MEASUREMENT Direct Methods Examples: Accumulation in a Container; Positive Displacement Flowmeter Restriction Flow Meters for Internal Flows Examples: Orifice Plate; Flow Nozzle; Venturi; Laminar Flow Element
Definisi tekanan pada aliran di sekitar sayap
Flow Measurement Linear Flow Meters Examples: Float Meter (Rotameter); Turbine; Vortex; Electromagnetic; Magnetic; Ultrasonic Float-type variable-area flow meter
Flow Measurement Linear Flow Meters Turbine flow meter Examples: Float Meter (Rotameter); Turbine; Vortex; Electromagnetic; Magnetic; Ultrasonic Turbine flow meter
Flow Measurement Traversing Methods Examples: Pitot (or Pitot Static) Tube; Laser Doppler Anemometer
The measured stagnation pressure cannot of itself be used to determine the fluid velocity (airspeed in aviation). However, Bernoulli's equation states: Stagnation pressure = static pressure + dynamic pressure Which can also be written
Solving that for velocity we get: Note: The above equation applies only to incompressible fluid. where: V is fluid velocity; pt is stagnation or total pressure; ps is static pressure; and ρ is fluid density.
The value for the pressure drop p2 – p1 or Δp to Δh, the reading on the manometer: Δp = Δh(ρA-ρ)g Where: ρA is the density of the fluid in the manometer Δh is the manometer reading
EXTERNAL INCOMPRESSIBLE VISCOUS FLOW
Main Topics The Boundary-Layer Concept Boundary-Layer Thickness Laminar Flat-Plate Boundary Layer: Exact Solution Momentum Integral Equation Use of the Momentum Equation for Flow with Zero Pressure Gradient Pressure Gradients in Boundary-Layer Flow Drag Lift
The Boundary-Layer Concept
The Boundary-Layer Concept
Boundary Layer Thickness
Boundary Layer Thickness Disturbance Thickness, d where Displacement Thickness, d* Momentum Thickness, q
Boundary Layer Laws
Laminar Flat-Plate Boundary Layer: Exact Solution Governing Equations
Laminar Flat-Plate Boundary Layer: Exact Solution Boundary Conditions
Laminar Flat-Plate Boundary Layer: Exact Solution Equations are Coupled, Nonlinear, Partial Differential Equations Blassius Solution: Transform to single, higher-order, nonlinear, ordinary differential equation
Laminar Flat-Plate Boundary Layer: Exact Solution Results of Numerical Analysis
Momentum Integral Equation Provides Approximate Alternative to Exact (Blassius) Solution
Momentum Integral Equation Equation is used to estimate the boundary-layer thickness as a function of x: Obtain a first approximation to the freestream velocity distribution, U(x). The pressure in the boundary layer is related to the freestream velocity, U(x), using the Bernoulli equation Assume a reasonable velocity-profile shape inside the boundary layer Derive an expression for tw using the results obtained from item 2
Use of the Momentum Equation for Flow with Zero Pressure Gradient Simplify Momentum Integral Equation (Item 1) The Momentum Integral Equation becomes
Use of the Momentum Equation for Flow with Zero Pressure Gradient Laminar Flow Example: Assume a Polynomial Velocity Profile (Item 2) The wall shear stress tw is then (Item 3)
Use of the Momentum Equation for Flow with Zero Pressure Gradient Laminar Flow Results (Polynomial Velocity Profile) Compare to Exact (Blassius) results!
Use of the Momentum Equation for Flow with Zero Pressure Gradient Turbulent Flow Example: 1/7-Power Law Profile (Item 2)
Use of the Momentum Equation for Flow with Zero Pressure Gradient Turbulent Flow Results (1/7-Power Law Profile)
Pressure Gradients in Boundary-Layer Flow
Drag Drag Coefficient with or
Drag Pure Friction Drag: Flat Plate Parallel to the Flow Pure Pressure Drag: Flat Plate Perpendicular to the Flow Friction and Pressure Drag: Flow over a Sphere and Cylinder Streamlining
Drag Flow over a Flat Plate Parallel to the Flow: Friction Drag Boundary Layer can be 100% laminar, partly laminar and partly turbulent, or essentially 100% turbulent; hence several different drag coefficients are available
Drag Flow over a Flat Plate Parallel to the Flow: Friction Drag (Continued) Laminar BL: Turbulent BL: … plus others for transitional flow
Drag Coefficient
Drag Flow over a Flat Plate Perpendicular to the Flow: Pressure Drag Drag coefficients are usually obtained empirically
Drag Flow over a Flat Plate Perpendicular to the Flow: Pressure Drag (Continued)
Drag Flow over a Sphere and Cylinder: Friction and Pressure Drag
Drag Flow over a Sphere and Cylinder: Friction and Pressure Drag (Continued)
Streamlining Used to Reduce Wake and Pressure Drag
Lift Mostly applies to Airfoils Note: Based on planform area Ap
Lift Examples: NACA 23015; NACA 662-215
Lift Induced Drag
Lift Induced Drag (Continued) Reduction in Effective Angle of Attack: Finite Wing Drag Coefficient:
Lift Induced Drag (Continued)
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