Chemistry Daily 10’s Week 14.

Slides:



Advertisements
Similar presentations
Aim: to revise key concepts about molar calculations
Advertisements

Chemical Reactions.
Calculations from Balanced Equations
Stoichiometry Jeopardy
LIMITING REACTANT The reactant that gives the least number of product moles “limits” the reaction. To understand this concept, let’s suppose you were an.
Chapter 5 Chemical Reactions
Limiting Reactants & Percent Yield
Chapter 9 - Section 3 Suggested Reading: Pages
Chemical Quantities Chapter 9
Stoichiometry Chapter 12.
Limiting Reactions and Percentage Yield
Copyright © Houghton Mifflin Company. All rights reserved. 9 | 1 Information Given by the Chemical Equation Balanced equations show the relationship between.
Stoichiometry Review Guide
CHEMISTRY February 13, 2012.
Chemistry 12.3 “Limiting Reagent and Percent Yield”
Limiting Reactants Very rare that reactants are present in the same ratio that they are used in the rxn. This means one reactant will run out first. This.
Stoichiometry Chemistry Ms. Piela.
Entry Task: March th Block 2. Agenda: Discuss Limited and % yield ws Self Check on Limited reactant & % yields.
Chapter 9 Chemical Quantities. 9 | 2 Information Given by the Chemical Equation Balanced equations show the relationship between the relative numbers.
Stoichiometry.
9.3 Notes Limiting reagents.
Stoichiometry. The quantitative relationship between the products and reactants in a chemical equation. Compare reactants to products, products to products,
Percentage yield Perform calculations to determine the percentage yield of a reaction Atom Economy Perform calculations to determine the Atom Economy of.
© 2014 Pearson Education, Inc. Basic Chemistry, 4/e Chapter 9: Chemical Quantities in Reactions Karen Timberlake.
STOICHIOMETRY CALCULATIONS COACH COX. MOLE TO MOLE CONVERSIONS Converting from moles of one substance in a chemical reaction to moles of another substance.
Chemistry 11 Stoichiometry Reality II: Percent Yield.
Entry Task: March 13 th- 14 th Block 1 Entry task question: Question: 1.5 grams of zinc was added with 0.5 grams of iodine to produce zinc II iodide. Calculate.
Chapter 12 Stoichiometry The study of the quantitative, or measurable, relationships that exist in chemical formulas and chemical reactions.Stoichiometry.
Chapter 19 Gas Stoichiometry.
Daily Science feb How many grams of CH4 is needed to produce 50.0 g CHCl3? CH4 + 3Cl2  CHCl3 +3HCl Lithium reacts spontaneously with bromine to produce.
Stoichiometry Jeopardy Percen t Yield Limiting Reactan ts “Stoiche d” About Chemist ry Q $100 Q $200 Q $300 Q $400 Q $ Q $100 Q $200 Q $300 Q $400.
Stoichiometry II. Solve stoichiometric problems involving moles, mass, and volume, given a balanced chemical reaction. Include: heat of reaction Additional.
Things you must KNOW and what to expect  Things you must KNOW  You must KNOW your polyatomics  You must KNOW how to write a balanced formula  You have.
Stoichiometry Chapters 7 and 9.
STOICHIOMETRY REVIEW ANSWERS
CHAPTER 11 CHEMISTRY.
Stoichiometry The accounting of chemistry. Moles WWhat are moles? Moles are a measure of matter in chemistry. Moles help us understand what happens.
Reaction Stoichiometry
II. Stoichiometry in the Real World Stoichiometry.
Chapter 12: Stoichiometry 12.1 The Arithmetic of Equations.
Preview Multiple Choice Short Answer Extended Response
What is stoichiometry? A problem solving method used to calculate the amount of product made or amount of reactant needed in a chemical reaction What is.
Stoichiometry Warmup I have 1 mole of CO 2 gas at STP. How many grams of CO 2 do I have? How many Liters of CO 2 do I have? How many molecules of CO 2.
Chemical Equations. Chemical Reactions - OVERVIEW change that occurs when atoms rearrange themselves Can absorb or release energy  Heat  Light  Sound.
Starter Complete the starter for ten Learning outcomes Describe the atom economy of a chemical reaction State how an equation is used to calculate an.
MAYHAN Ch. 10/12 Moles to % yield Review ws DEFINE MOLE. MAYHAN HOW IS THE MOLE USED IN CHEMISTRY? A mole is 6.02 x “things” These things are any.
Copyright©2004 by Houghton Mifflin Company. All rights reserved. 1 Introductory Chemistry: A Foundation FIFTH EDITION by Steven S. Zumdahl University of.
By Steven S. Zumdahl & Donald J. DeCoste University of Illinois Introductory Chemistry: A Foundation, 6 th Ed. Introductory Chemistry, 6 th Ed. Basic Chemistry,
Stoichiometry Notes (Chapter 12). Review of Molar Mass Recall that the molar mass of a compound is the mass, in grams, of one mole of that compound.
Students type their answers here
Chapter 9 Stoichiometry. Stoichiometry Composition Stoichiometry: deals with the mass relationships of elements in compounds. Reaction Stoichiometry:
Chapter 9 Stoichiometry Test REVIEW SHEET
Ch. 9-3 Limiting Reactants & Percent Yield. POINT > Define limiting reactant POINT > Identify which reactant is limiting in a reaction POINT > Define.
Chapter 3 Review.
Mass-Mass Conversions 56.0 g N 2 x g N 2 g NH = 1904 = When nitrogen and hydrogen react, they form ammonia gas, which has the formula.
Stoichiometry Pronounced: Stoy-kee-AHM-uh-tree. What is stoichiometry? Its math that helps us to see the relationship between what is used and formed.
Moles Noadswood Science, 2016.
Stoichiometry.
Limiting & Excess Reactants
Chapter 12 Review.
Chapter 12 Review.
Limiting and Excess Reactants
Stoichiometry Review.
Chapter 11 Stoichiometry
How many moles of water are made by
Stoichiometry.
Bellwork Tuesday 5.9 L of carbon dioxide is combined with 8.4 g MgO in a synthesis reaction to form magnesium carbonate. How many grams of magnesium carbonate.
Adjusting to reality- Limiting and Excess Reactants
Preview Multiple Choice Short Answer Extended Response
Review #1 In the formation of carbon dioxide from carbon monoxide and oxygen, how many moles of carbon monoxide are needed to react completely with 7.0.
Presentation transcript:

Chemistry Daily 10’s Week 14

1 1. For the reaction represented by the equation CH4 + 2O2  CO2 + 2H2O, how many moles of carbon dioxide are produced from the combustion of 100. g of methane? a. 6.23 mol b. 10.8 mol c. 12.5 mol d. 25 mol

2. For the reaction represented by the equation Pb(NO3)2 + 2KI  PbI2 + 2KNO3, how many moles of lead(II) iodide are produced from 300. g of potassium iodide and an excess of Pb(NO3)2? a. 0.904 mol b. 1.81 mol c. 3.61 mol d. 11.0 mol

2 1. For the reaction represented by the equation Cl2 + 2KBr  2KCl + Br2, how many grams of potassium chloride can be produced from 300. g each of chlorine and potassium bromide? a. 98.7 g b. 111 g c. 188 g d. 451 g

2. A chemist interested in the efficiency of a chemical reaction would calculate the a. mole ratio. b. energy released. c. percentage yield. d. rate of reaction.

3 1. If the percentage yield is equal to 100%, then a. the actual yield is greater than the theoretical yield. b. the actual yield is equal to the theoretical yield. c. the actual yield is less than the theoretical yield. d. there was no limiting reactant.

2. For the reaction represented by the equation Cl2 + 2KBr  2KCl + Br2, calculate the percentage yield if 200. g of chlorine react with excess potassium bromide to produce 410. g of bromine. a. 73.4% b. 82.1% c. 91.0% d. 98.9%

4 1. What is the maximum possible amount of product obtained in a chemical reaction? a. theoretical yield b. percentage yield c. mole ratio d. actual yield

2. For the reaction represented by the equation SO3 + H2O  H2SO4, how many grams of sulfuric acid can be produced from 200. g of sulfur trioxide and 100. g of water? a. 100. g b. 200. g c. 245 g d. 285 g

5 1. After calculating the amount of reactant B required to completely react with A, then comparing that amount with the amount of B available, one can determine the a. limiting reactant. b. rate of the reaction. c. energy released in the reaction. d. pathway of the reaction.

2. For the reaction represented by the equation 2Na + 2H2O  2NaOH + H2, how many grams of hydrogen are produced if 120. g of sodium and 80. g of water are available? a. 4.5 g b. 45 g c. 80. g d. 200 g

Answers & Standards 1.1. ANS: A STA: SC2.d 1.2. ANS: A STA: SC2.d 2.1. ANS: C STA: SC2.d 2.2. ANS: C STA: SC2.e 3.1 ANS: B STA: SC2.e 3.2. ANS: C STA: SC2.e 4.1. ANS: A STA: SC2.e 4.2 ANS: C STA: SC2.d 5.1. ANS: A STA: SC2.e 5.2. ANS: A STA: SC2.d