Homework Answers 9) 6/24 + 6/24 = 12/24 or ½ 11) 12/24 + 12/24 = 24/24 or 1 23) P(2 and A) = (1/6 * 1/5) = 1/30 P(2 and B) = (1/6 * 1/5) = 1/30 P(2 and.

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Homework Answers 9) 6/24 + 6/24 = 12/24 or ½ 11) 12/ /24 = 24/24 or 1 23) P(2 and A) = (1/6 * 1/5) = 1/30 P(2 and B) = (1/6 * 1/5) = 1/30 P(2 and C) = (1/6 * 1/5) = 1/30 P(2 and A, B, or C) = 1/30 + 1/30 + 1/30 = 3/30 or 1/10

Probability of Inclusive Events Integrated Math 2 – Lesson 58 Mr. Lopez

Probability of Inclusive Events Inclusive Events: Events where some probabilities can be counted in more than one event. Ex: What is the probability of drawing a king or a red card from a standard deck of cards? This is an example of an inclusive event because there are 4 kings (2 black and 2 red) and there are 26 red cards. However, this doesnt mean that there are 30 choices. It means that there are some results that exist in both and we cant count.

Probability of Inclusive Events If two events, A and B, are inclusive then the probability that either A or B occurs is the sum of their probabilities decreased by the probability of them both occurring. P(A or B) = P(A) + P(B) – P(A and B)

Example What is the probability of drawing a king or a red card from a standard deck of cards. P(king) = 4/52 P(red card) = 26/52 P(king and red) = 2/52 Therefore P(king and red card) is 4/ /52 – 2/52 = 28/52

Example 2 On a standard die, Draw a tree diagram of rolling 2 dice and list all the possible outcomes. 1. What is the probability of rolling a number greater than 2 or even? 2.What is the probability of rolling a sum that is a multiple of 3 or multiple of 2?