Chemistry 12.1.

Slides:



Advertisements
Similar presentations
TWO STEP EQUATIONS 1. SOLVE FOR X 2. DO THE ADDITION STEP FIRST
Advertisements

Advanced Piloting Cruise Plot.
Copyright © 2003 Pearson Education, Inc. Slide 1 Computer Systems Organization & Architecture Chapters 8-12 John D. Carpinelli.
Chapter 1 The Study of Body Function Image PowerPoint
Jeopardy Q 1 Q 6 Q 11 Q 16 Q 21 Q 2 Q 7 Q 12 Q 17 Q 22 Q 3 Q 8 Q 13
Jeopardy Q 1 Q 6 Q 11 Q 16 Q 21 Q 2 Q 7 Q 12 Q 17 Q 22 Q 3 Q 8 Q 13
Chemistry.
Conversion Problems 3.3.
Chemistry.
Density 3.4.
International System of Units 3.2
Measurements and Their Uncertainty 3.1
Chemistry 2.3.
FACTORING ax2 + bx + c Think “unfoil” Work down, Show all steps.
Stoichiometry Chapter 12.
Chemistry.
Chemistry 2.3.
Chemistry 17.3.
Slide 1 of 26 Chemistry. © Copyright Pearson Prentice Hall Slide 2 of 26 Properties of Matter Bamboo has properties that make it a good choice for use.
Chemistry 13.1.
VOORBLAD.
Factor P 16 8(8-5ab) 4(d² + 4) 3rs(2r – s) 15cd(1 + 2cd) 8(4a² + 3b²)
Chemistry 17.1.
Chemistry 17.2.
© 2012 National Heart Foundation of Australia. Slide 2.
Chemistry 18.2.
Stoichiometry Chapter 12.
Understanding Generalist Practice, 5e, Kirst-Ashman/Hull
25 seconds left…...
Januar MDMDFSSMDMDFSSS
We will resume in: 25 Minutes.
©Brooks/Cole, 2001 Chapter 12 Derived Types-- Enumerated, Structure and Union.
Chemistry 22.3.
Chemistry 21.3.
PSSA Preparation.
Chemistry 14.4.
Chemistry 16.3.
Stoichiometry The Arithmetic of Equations Prentice-Hall Chapter 12.1 Dr. Yager.
Chapter 12 Stoichiometry 12.1 The Arithmetic of Equations
Chapter 12--Stoichiometry
© Copyright Pearson Prentice Hall Slide 1 of 41 The Arithmetic of Equations More than 3000 cocoons are needed to produce enough silk to make just one elegant.
CHAPTER 12 STOICHIOMETRY
Chemistry 12.2.
Slide 1 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Using Everyday Equations A _____________ _________________ _____________.
Chapter 12 Stoichiometry 12.1 The Arithmetic of Equations
Slide 1 of 41 Chemistry © Copyright Pearson Prentice Hall Slide 2 of Chemical Calculations The effectiveness of car’s air bags is based.
© Copyright Pearson Prentice Hall Slide 1 of 30 The Arithmetic of Equations More than 3000 cocoons are needed to produce enough silk to make just one elegant.
Slide 1 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Using Everyday Equations A balanced chemical equation provides the same kind.
Chapter 12 Stoichiometry Ch The Arithmetic of Equations.
12.1 The Arithmetic of Equations > 1 Copyright © Pearson Education, Inc., or its affiliates. All Rights Reserved. Chapter 12 Stoichiometry 12.1 The Arithmetic.
Slide 1 of 30 Chemistry © Copyright Pearson Prentice Hall Slide 2 of 30 The Arithmetic of Equations More than 3000 cocoons are needed to produce.
Slide 1 of 41 Chemistry © Copyright Pearson Prentice Hall Slide 2 of Chemical Calculations The effectiveness of car’s air bags is based.
Stoichiometry Chapter 12. Slide 2 of 30 Introduction More than 3000 cocoons are needed to produce enough silk to make just one elegant Japanese kimono.
Chapter 12 Stoichiometry
Chemistry 12.1.
UNIT 9: STOICHIOMETRY.
Stoichiometry Chapter 12.
Stoichiometry The Arithmetic of Equations
Drill: Determine if the following are molecular or empirical: C3H8N
Created by C. Ippolito June 2007
Chemistry 12.1.
UNIT 7: STOICHIOMETRY.
Chemistry 12.1.
Chemistry 12.1.
The Arithmetic of Equations
Chemistry 12.1.
Chemistry 12.1.
Presentation transcript:

Chemistry 12.1

The Arithmetic of Equations 12.1 The Arithmetic of Equations More than 3000 cocoons are needed to produce enough silk to make just one elegant Japanese kimono. Like silk manufacturers, chemists must know how much reactant they need to make a certain amount of product. Determining the quantities of reactants and products in a reaction requires a balanced chemical equation.

Using Everyday Equations 12.1 Using Everyday Equations Using Everyday Equations How is a balanced equation like a recipe?

Using Everyday Equations 12.1 Using Everyday Equations A balanced chemical equation provides the same kind of quantitative information that a recipe does. A cookie recipe tells you the number of cookies that you can expect to make from the listed amounts of ingredients. Using Models How can you express a cookie recipe as a balanced equation?

Using Everyday Equations 12.1 Using Everyday Equations An equation can represent the manufacturing of a single tricycle.

Using Balanced Chemical Equations 12.1 Using Balanced Chemical Equations Using Balanced Chemical Equations How do chemists use balanced chemical equations?

Using Balanced Chemical Equations 12.1 Using Balanced Chemical Equations Chemists use balanced chemical equations as a basis to calculate how much reactant is needed or product is formed in a reaction. The calculation of quantities in chemical reactions is a subject of chemistry called stoichiometry.

12.1

12.1

12.1

12.1

for Sample Problem 12.1 Problem Solving 12.1 Solve Problem 1 with the help of an interactive guided tutorial.

Interpreting Chemical Equations 12.1 Interpreting Chemical Equations Interpreting Chemical Equations In terms of what quantities can you interpret a balanced chemical equation?

Interpreting Chemical Equations 12.1 Interpreting Chemical Equations A balanced chemical equation can be interpreted in terms of different quantities, including numbers of atoms, molecules, or moles; mass; and volume.

Interpreting Chemical Equations 12.1 Interpreting Chemical Equations Number of Atoms The balanced chemical equation for the formation of ammonia can be interpreted in several ways. Predicting How many molecules of NH3 could be made from 5 molecules of N2 and 15 molecules of H2?

Interpreting Chemical Equations 12.1 Interpreting Chemical Equations Number of Molecules The balanced chemical equation for the formation of ammonia can be interpreted in several ways. Predicting How many molecules of NH3 could be made from 5 molecules of N2 and 15 molecules of H2?

Interpreting Chemical Equations 12.1 Interpreting Chemical Equations Moles The balanced chemical equation for the formation of ammonia can be interpreted in several ways. Predicting How many molecules of NH3 could be made from 5 molecules of N2 and 15 molecules of H2?

Interpreting Chemical Equations 12.1 Interpreting Chemical Equations Mass The balanced chemical equation for the formation of ammonia can be interpreted in several ways. Predicting How many molecules of NH3 could be made from 5 molecules of N2 and 15 molecules of H2?

Interpreting Chemical Equations 12.1 Interpreting Chemical Equations Volume The balanced chemical equation for the formation of ammonia can be interpreted in several ways. Predicting How many molecules of NH3 could be made from 5 molecules of N2 and 15 molecules of H2?

Interpreting Chemical Equations 12.1 Interpreting Chemical Equations The balanced chemical equation for the formation of ammonia can be interpreted in several ways. Predicting How many molecules of NH3 could be made from 5 molecules of N2 and 15 molecules of H2?

Mass Conservation in Chemical Reactions 12.1 Mass Conservation in Chemical Reactions Mass Conservation in Chemical Reactions What quantities are conserved in every chemical reaction?

Mass Conservation in Chemical Reactions 12.1 Mass Conservation in Chemical Reactions Mass and atoms are conserved in every chemical reaction.

Conceptual Problem 12.1

Conceptual Problem 12.1

Conceptual Problem 12.1

for Conceptual Problem 12.1 Problem Solving 12.4 Solve Problem 4 with the help of an interactive guided tutorial.

12.1 Section Quiz. 12.1.

12.1 Section Quiz. 1. A manufacturer of bicycles has 5350 wheels, 3023 frames, and 2655 handlebars. How many bicycles can be manufactured using these parts? 2675 bicycles 2655 bicycles 3023 bicycles 5350 bicycles

2. A reaction that produces iron metal from iron ore is shown below. 12.1 Section Quiz. 2. A reaction that produces iron metal from iron ore is shown below. Fe2O3•H2O(s) + 3CO(g)  2Fe(s) + 3CO2(g) + H2O(g) In this equation, the volume of gas at STP that reacts and the volume of gas at STP produced will be 3 L and 4 L. 67.2 L and 89.6 L. 67.2 L and 67.2 L 3 L and 3 L

12.1 Section Quiz. 3. What is conserved in the reaction shown below? H2(g) + Cl2(g)  2HCl(g) only mass only mass and number of moles only mass, number of moles, and number of molecules mass, number of moles, number of molecules, and volume

END OF SHOW